Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of this Forum, I am asking that you help him
by making a donation on the Paypal Button above
Thanks to ALL for your help!!


Water and pressure reduction

Started by Gabriele, November 08, 2014, 09:51:24 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

Gabriele


Gabriele

I tried computate an immaginary sistem formed by weights and boxes allowing the weight is on the box full of air,after a compression,to move on the first...than let the compression i gave go,and to return the weight to the ground...i got a surplus. But probably is a mistake,cause i'm not really able to do that math,really i don't know how to do that...

Green and white go on red after compression...the red compress more,i let pressure decreese,and i re-put the green white on the ground

MarkE

On the left the water contributes pressure based on the water height.

Assigning X left to right, Y into page, and Z as height, and taking the 0,0,0 datum at the lower left hand corner:

Weight_water = 9.8m/s2*1000kg/m3*water_volume

Pressure_bottom_left = air_pressure + weight_water/(x_wall * y)

Force_left_to_right = y * ( 0.5*pressure_bottom_left*z_water + air_pressure * z_wall )

=

Force_right_to_left = y * ( air_pressure * z_wall ) + Kspring * (box_width + x_wall - spring_uncompressed_length)   (spring K is negative value)

y * ( 0.5*(air_pressure + weight_water/(x_wall * y))*z_water ) = Kspring * (box_width + x_wall - spring_uncompressed_length) 

Solve for x_wall.

Gabriele

It is clear the wall moves. What for me isn't clear is,i repeat,if when i remove the compression when the level of water is rised,how much energy the water returns... 100% of elastic energy due to liquid compression or less? Thx

Low-Q

Quote from: Gabriele on November 08, 2014, 07:47:03 PM
this way....
This shuld be "easy" to confirm if you had some mercury. And we can eleminate pressure as it is equal in both chambers anyways.


In the first experiment you use water - completely filled up. No pressure. Measure force acting on the wall.
In the next experiment, replace water with the same weight in mercury. No pressure. Measure force acting on the wall


Mercury is known to be denser than water. Well, the level of mercury would require only 7.4% of water level.
So imagine that the mercury is seriously compressed water. Water so compressed it has shrinked by 93.6% - that must require a very expensive pump, made by some very exotic materials!


Anyway. Then you can calculate the force that the mercury and water respectively is pushing on the wall. Do you find any difference?


Vidar