3rd working machine you gandmother could make _2nd Law crushed

[MarkE]

Buoyancy is something i know very well,having owned my own boat building firm,and i was also one of the builders .
Because of this,I too have an OU buoyancy device that i designed many years ago -but where to get the money to fund such a device or project.
No broken laws of physics,and the complete math to boot to back up said OU device. The opperation is so simple--.increasing and decreasing mass density/surface area. This is where the !buoyant force! comes into play.If the object's weight is less than the buoyant force, the object will float.  If the object's weight is greater than the buoyant force, the object will sink.The buoyant force is the force that pushes against the bottom and top surface areas of the object in the body of water,as the side ways forces cancel each other out.Because the bottom of the object has a greater depth than that of the top of the object(as the object will have hight/thickness),the object will feel slightly lighter under water,as the water pressure under the object will be slightly higher than it is on top of the object-and this depends on many factors in regards to the object. So all you need to do is increase the objects buoyant surface area without increasing it's weight,and the object will float. We then decrease the objects buoyant surface area,and the object will sink.

So here is the kicker. Once the object begins to sink,it will keep sinking with the same downward force until it hits the bottom-ocean floor. And when it begins to float,it will rise with the same force until it reaches the surface. So if it takes say 10000 joules of energy to get the object to sink say 10 feet,it takes the same amount of energy to get the object to sink 1 000 000 feet-->and this is done by decreasing the objects buoyant surface area,while maintaining the object weight.

They say that it takes x amount of energy to lift y amount of weight a set distance. Well using buoyancy as a tool,this is where that law dose not apply.This is one case it takes x amount of energy to lift y amount of weight to any hight,and return it back to it's starting point.

The net downward force on a submerged object is simply the difference between the dry weight of the object and the equivalent weight of fluid displaced by the object's volume.  The energy involved sinking or raising the object is offset by the complementary movement of the displaced fluid.  Altering the object's volume while submerged requires work to increase the volume of displaced fluid, or absorbs work by shrinking.  Rheology aside, there is really no difference in the mechanics of a rock falling through the atmosphere to the land below or a rock sinking in the ocean.  the net energy per unit height is simply reduced in the case of falling through the denser fluid.

[telecom]

Hi guys,
there was a French patent where the guy had it with the weight pushing out pistons on one side to
increase the byouncy. And on another side to pull inward to decrease it.
Regards

[The Eskimo Quinn]

This is a PDF that has the original doc, the validation and notes, and full mechanical design instructions as well now on the end. all in one doc.

if you are building one as a model you can reverse the side drives, so the chain is simply a bicycle chain and the protruding post are on the box. clear perspex is ideal or glass and silicone for models.

[tinman]

The net downward force on a submerged object is simply the difference between the dry weight of the object and the equivalent weight of fluid displaced by the object's volume.  The energy involved sinking or raising the object is offset by the complementary movement of the displaced fluid.  Altering the object's volume while submerged requires work to increase the volume of displaced fluid, or absorbs work by shrinking.  Rheology aside, there is really no difference in the mechanics of a rock falling through the atmosphere to the land below or a rock sinking in the ocean.  the net energy per unit height is simply reduced in the case of falling through the denser fluid.

There is a very large difference between the mechanics of air and water. A heavier than air object will not float in the atmosphere,but a heavier than water object will float in water. You can hollow out a rock all you like,and it will not float in air,but it will in water.This means the mechanics are different between fluid displacement and atmospheric displacement. No work is required to alter the objects volume when submerged,as the work is done by way of pressure equilization between the internal and external pressures of the submerged object. Work is only required to reduce surface area of the object at the begining of the cycle,which is while the object is afloat.Once that work is done,the object will sink an infinite depth that is limited only to the deepest water body.If we take a balloon and fill it with a lighter than air gas,the balloon will loose lifting force as it gains altitude,while the same balloon would maintain the same lifting force in water regardless of depth(we are asumeing the balloon is strong enough to withstand crushing forces in this example)

[TinselKoala]

There is a very large difference between the mechanics of air and water. A heavier than air object will not float in the atmosphere,but a heavier than water object will float in water.

Sorry, you are wrong. An object that is heavier than the water it displaces will not float in water, and an object that is heavier than the air it displaces will not float in air.  An object that is lighter than the air it displaces, like a big blimp, will float in air, and an object that is lighter than the water it it displaces, like a huge container ship, will float in water. Buoyancy is buoyancy, no matter the surrounding material.

You can hollow out a rock all you like,and it will not float in air,but it will in water.This means the mechanics are different between fluid displacement and atmospheric displacement.

No, you are comparing apples and oranges. If your hollow rock displaces enough air mass, it will float, sure enough. Our air isn't dense enough for any real hollow rock to float, but it will float just fine in a much denser gas environment.

No work is required to alter the objects volume when submerged,as the work is done by way of pressure equilization between the internal and external pressures of the submerged object. Work is only required to reduce surface area of the object at the begining of the cycle,which is while the object is afloat.Once that work is done,the object will sink an infinite depth that is limited only to the deepest water body.If we take a balloon and fill it with a lighter than air gas,the balloon will loose lifting force as it gains altitude,while the same balloon would maintain the same lifting force in water regardless of depth(we are asumeing the balloon is strong enough to withstand crushing forces in this example)

Again, you are confounding your facts with false comparisons. Take a look at how high-altitude research balloons work. They start at the ground only "partially" inflated, just enough to be buoyant (they displace slightly more airmass than they weigh) and as they rise, the gas inside expands, so they displace more and more volume, of less and less dense air, so they continue to rise until they finally burst from being completely overfull. If you sink a balloon in water by deflating it at the surface, the only way to get it to rise up again is to pump gas into it, and you will have to pump harder the deeper the balloon is. A volume of water must be displaced that has a mass that is greater than the balloon's mass for it to rise up, and the deeper the balloon the more gas must be pumped into it, because the gas is compressible and the pressure inside the balloon must be slightly greater than the pressure of the water, for the balloon to expand and displace the necessary volume of water. When the balloon is expanded enough to displace more mass of water than the balloon weighs, the balloon will begin to rise _and expand even more_ as the gas inside expands to match the water pressure at whatever depth it is at.
When you sink a closed, constant volume thing like your hollow rock, the water level rises. Take a bucket and mark the water level on the side of the bucket, then sink your rock to just below the surface. You will note that the water level is now above your mark; an equal volume of water has been _lifted up_ as your rock has been sunk. This lifting of water takes work. Now let your rock sink more, say one-rock-diameter further. Now you have lifted up another volume of water, but you don't see the water level increase because you aren't changing the overall volume of the system any more, but you still have displaced one rock's worth of water from underneath the rock and moved it to above the rock. This takes work. If you have a rope attached to the rock, the work available by the rock pulling on the rope is _less than_ the work available from dropping the rock/rope in air, less by the amount of work it takes to raise up that water, continuously all the way down. When you pull the rock up, it's easier than in air because the water is flowing back underneath the rock as you lift it. This is buoyancy. There is no free lunch, even underwater.