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Lenz free generator + a different pulse motor!

Started by life is illusion, December 21, 2014, 06:36:25 PM

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dieter

life is illusion (may I call you lii) , I found your vids interesting. Me too, was thinking that a coil causes a reverse current flow when switched "off". It takes a while to build up the B field when turned on, energy is stored in the B field, just like in a cap. You turn it off, then that energy is still there, the field collapses and the current flows back. It may be ideal to shorten this reverse current, so the coil rings on the back EMF. however, I find it rather tricky to harvest the back EMF with diodes because you don't want the fwd EMF to go the same way.
One method would be, since the Back EMF tends to be a HV Spike, compared to the fwd voltage, to use a sparkgap to extract the back EMF. By doing so, it may be possible to even grab some additonal free electrons in an electron-avalanche situation ala Townsend-Brown.


Keep it up, I'd like to see somebody build a prototype. This Bitoroid Gen has some serious potential, considering some bitoroid successes using metglas cores, as seen on tube.

tinman

Quote from: Magluvin on December 21, 2014, 11:51:40 PM

When we apply voltage across a coil, magnetic field increases and current increases. The self inductance offers impedance to magnetic field and current build, because as the field that is building cuts the coils windings produces current influence opposite of the input. So the field and current increase are not instantaneous.   lol, thats why I imagine a super conductive inductor to not pass any current at all, because without losses, the self induced impedance, again, without losses, would never let current flow from the input. ;D

Now, when we cut the input, the field, of the same polarity that was produced, collapses and the fields 'cut' the coil windings inward instead of outward, causing currents in the coil to want to go forward, the same direction as the input produced.

But, if the switch, which ever kind it may be, is shut off without allowing the HV developed by the field collapse to to cross the gap/terminals/semiconductor, then the coil field collapse will produce a HV charge from end to end, with no where to go. So the high voltage potential across the coil produces a reverse current, in turn producing a reverse field.  But the switch needs to be able to resist the high voltage when the switch is opened. Like in a reed switch of a pulse motor, the spark when the switch opens drains the forward voltage from the coil and the coil does not produce back emf, and the field of the coil doesnt get a chance to reverse. Just saying, under special circumstances, yes, the current and the field of the coil can reverse if once the input is cut, the coil is isolated enough to allow the coil to build to full voltage from the field collapse. Then it has to reverse.  Then use a diode to send that energy simply back to the battery.

In fact, if the input is cut, and the coil is left completely isolated, with no where for the currents of the coil to go in either direction, the coil will oscillate, at a very high freq, till it dies off due to losses.

So I say yes, there can be a reversal of current and magnetic field, under the right conditions. ;)

Mags
Mag's
If the inductor become's open circuit(power interupted),and the inductive kickback has no where to go,then there will be no current flow(or an extreem small amount),and the magnetic field will collap's almost instantly. Current cannot reverse direction if there is no current,and it is current that creat's the magnetic field-not voltage.Only the voltage reverses polarity,not the current when the power supply is disconected from the inductor-->this is the very reason the negative terminal of the charge battery is hooked to the positive terminal of the run battery in the SSG circuit.

@LII
The current will continue to flow in the same direction.
The magnetic field will remain the same polarity(if we can call it polarity)
Only the voltage across the inductor will change polarity.
The lower the resistance of the load capturing the inductive kickback,the longer it will take for the magnetic field to collaps.

@ Chet.
I dont see this as being any different to school,where the teachers correct your mistakes so as you learn. I see many here haveing a dig at MH,but i see him as a great teacher,and only once has it been me that corrected MH(yes,im learning through bench time). Is he any different to that of poynt99,TK and the like's?,the guys that point out our mistakes,and give solid explinations as to why some asumptions are wrong. It's these guys(poynt,TK,MH) that have allowed me to get to where i am today(along with my own experimentation),the guys that show me the path to correct test method's,and correct outcomes. When i first started out in all this FE stuff,i built a pulse motor that i thought was way OU ;D-->i can now sit back and have a good laugh at myself. If it wasnt for these guy's,i'd still be leeding myself up the garden path--you know this with a couple of devices that i had poynt spend quite some time on with me. The only one i havnt figured out yet is my dad's little setup,but one day i will know enough to work that out too-->that is what im waiting for.

life is illusion

Quote from: tinman on December 22, 2014, 06:57:07 AM

@LII
The current will continue to flow in the same direction.
The magnetic field will remain the same polarity(if we can call it polarity)
Only the voltage across the inductor will change polarity.
The lower the resistance of the load capturing the inductive kickback,the longer it will take for the magnetic field to collaps.



Thanks everyone for commenting :)
And Tinman, I am very glad that I can finally talk to you, I have been watching your vids and learning a lot from you ^_^

Back to the topic:
I'm uploading a drawing for you and in the drawing we can see a normal DC electricity running through a solenoid and producing N pole at the entrance of positive pole! Then after disconnecting the current, the BEMF is being used to run a load. By doing so, the direction of current is changed, the voltage and current both are going the opposite direction and thus I think they are going to be generating an opposite magnetic pole just simply because positive is not in the same place it was in, thus the N pole can't stay in its place either :)

I also would like to say that the existence of magnetic field in an electromagnet is absolutely dependent on the flow of current. So in an air core solenoid when we disconnect the current flow, the electromagnetic field around the solenoid will collapse and disappear immediately regardless of we collect the BEMF or not. But if we DO collect the BEMF, just like I explained earlier, the current changes direction and I assume it will change the poles of electromagnet. The current of BEMF is much weaker that the main input, so the changed magnetic poles might not be as strong as the main poles but I think they still do exist and can cause a small problem in system :)

mscoffman

Quote from: life is illusion on December 21, 2014, 08:02:05 PM
I have always been under the impression that when current direction changes, (like when we pick up the BEMF) the magnetic flied of solenoid will change as well. I mean how can magnetic field stay the same when a REVERSED current is running through the solenoid, is picked up by diodes and charges a cap, battery or lighting a lamp? :)

Just like when a capacitor stores voltage putting a non-powerful minus voltage on the wire does not immediately switch the capacitor
to minus (it takes time to discharge). Then it becomes minus after a time delay. An inductor does exactly the same thing
*except* the => inductor does that with current <=.  If you look up the mathematical definition of a capacitor and compare
it with the mathematical definition of an inductor in Wikipedia, you will see that e voltage potential is replaced by i current
in their respective equations. The magnetic field takes time to shrink when a non powerful current is applied so for a time the collapse
current overwhelms it. This is why an inductor+capacitor circuit will ring. If this ringing is done because of the inductance and
capacitance of "free space", an EMF wave will be transmitted through space. Light does this, so when light travels billions of years
between stars one can see that this LC relation must be perfectly described by it's mathematics as nearly as is possible.

:S:MarkSCoffman

gyulasun

Quote from: life is illusion on December 22, 2014, 10:12:49 AM
...

I'm uploading a drawing for you and in the drawing we can see a normal DC electricity running through a solenoid and producing N pole at the entrance of positive pole! Then after disconnecting the current, the BEMF is being used to run a load. By doing so, the direction of current is changed, the voltage and current both are going the opposite direction and thus I think they are going to be generating an opposite magnetic pole just simply because positive is not in the same place it was in, thus the N pole can't stay in its place either :)

....

Hi Sam,

When you have time please edit your post with the high sized picture attachment above and use  max of 860 pixels horizontally, that is the pleasant acceptable size so that we do not have to scroll forever horizontally to read the posts. You can edit your post within 12 hours, after that you cannot Modify it. (You can find your Modify possibility if you scroll to the very right of you post...  :) )  You can use MS Windows Paint to resize it easily.

I edited your drawing to explain how the current directions are and why the original poles of electromagnet do not change (only diminish towards zero). 
When you switch off the current in a coil, it is the polarity of the voltage across the coil which changes, the current starts to decrease towards zero but its original direction does not change.  Its amplitude changes to a lower and lower value till full dissipation by a load and by the losses but its direction does not change in the switch-off moment.   The coil becomes a generator with instanteneous output voltage polarities as you also indicated in red, hence the current direction in the coil remains the same as was from the input voltage source. 

Why the induced voltage polarity changes after the switch-off with respect to the input voltage: the change in the magnetic field reverses from an increasing (or already steady) state to a decreasing state as the field collapses.

Keep up the ideas coming, possibly with practical tests if you can.

Gyula