Partnered Output Coils - Free Energy

[alan]

Hi folks, Hi emjunkie, well just fired it up and i am using an led bulb to see if it can power things, it lights the led bulb well.
When i use a wire to short the partnered secondary coils, the amp draw lowers from 360 milliamps while powering led bulb down to 260 milliamps using 3.7 volt input.
My other setup did not do this when a dead short was applied across partnered coils.
So does this sound like the right behavior so far, emjunkie.
Here is a pic of it.
peace love light

Awesome

I wonder what the output I and V are.
Will build it myself soon, if I get my hands on an old crt monitor.

[EMJunkie]

I have difficulty understanding this picture; shouldn't the thumbs point in the opposite direction of the field of the primary (which isn't seen)?

Hi Alan,

Good Question!

What happens if we bring two coils together, one has an input of say 10V 10ma?

The Secondary Coil, in it is Induced and EMF, (Charge Separation), via Time Rate of Change of the Magnetic Field of the Primary! This Magnetic Field (Result of Charge Flowing) is in the Opposite Direction to the Primary! So in the Picture (Attached) we see Net Zero Magnetic Field. The Vector from each Magnetic Field, Sums to Zero! This is Lenz's Law! A Magnetic Field that Opposes the Primary! Only if Loaded and Current is Flowing!

Now, in a Secondary, which would normally be carrying Current anyway, if we bring another Coil in (Tertiary Coil), we see again a Tertiary Field, Lenz Law, Induced EMF in our Tertiary Coil! Because of the Magnetic Field in the Secondary, which in turn opposes the Primary. Our Tertiary Coil actually Adds to the Primary Coils Field.

IMPORTANT: The Electric Fields of each Coil must Add (Like Floyd Sweet said) - So simply putting a bunch of coils together may not work as one may expect! It has to be configured correctly to work!

"If the directions of the two signals are such that opposite H-fields cancel and E-fields add, an apparently steady E-field will be created. The energy density of the fields remain as calculated above, but the value of the E-field will double from E/2 to E. It is a simple matter using the equations √ue and 1/√ue for a team wave to get rid of H and C and so convert the first equation into the well known equation for energy density in the so-called electrostatic field"

Its a little complicated to get ones head around at the start. Keep thinking, it will come!

Kind Regards

   Chris Sykes - hyiq.org
   To Reach New Horizons!

[TinselKoala]

@TinselKoala

The output on these devices are AC!

Everyone knows this capacitor is just a decoupling cap!

Go away and distract others that worship your holiness  I don't want your idioms here!

Kind Regards

   Chris Sykes - hyiq.org
   To Reach New Horizons!

No, the AC-coupling capacitor is a high-pass filter that filters out DC components and moves the signal average down to the channel baseline. Did you not read the references, especially the one from NATIONAL INSTRUMENTS ? You really should.

The use of AC-coupling puts the _average_ of any AC signal on the zero volts baseline, in addition to removing DC offsets. For power measurements of rough signals or especially signals with any DC component, this gives inaccurate results.

And of course you do not want any criticisms here. You are always right and your measurements are not to be questioned, you have already said that!

But you are just revealing your ignorance with this matter. Do a little homework! Read the references I have cited! Look up some other references on your own! Learn to use your test equipment properly!

You can believe whatever you want, but when you start delivering clearly incorrect information you can expect criticism from people who know better.

But you would be well advised to believe the engineers from National Instruments! And until you can demonstrate that you know how properly to use your test equipment... everyone would be well advised to question your measurements and your claims.

It may be in special cases (like truly symmetrical sinusoidal AC signals)  that there is no difference in the readings taken with AC vs. DC coupled scope channels. Is your system such a special case? It's easy to test. Does the displayed signal move up or down _at all_ when you switch from DC coupled to AC coupled? If it doesn't, then you have such a special case, but you should still  be using DC-coupled channels by default for _all measurements_ unless you have some good reason not to, so that you don't miss DC offsets or falsely change the average position of the signal.

Here's a demonstration I made a long time ago when LTseung was claiming OU from some JT measurements made with his scope AC-coupled.
http://www.youtube.com/watch?v=EVFyaQY6pR0

[EMJunkie]

No, the AC-coupling capacitor is a high-pass filter that filters out DC components and moves the signal average down to the channel baseline. Did you not read the references, especially the one from NATIONAL INSTRUMENTS ? You really should.

The use of AC-coupling puts the _average_ of any AC signal on the zero volts baseline, in addition to removing DC offsets. For power measurements of rough signals or especially signals with any DC component, this gives inaccurate results.

And of course you do not want any criticisms here. You are always right and your measurements are not to be questioned, you have already said that!

But you are just revealing your ignorance with this matter. Do a little homework! Read the references I have cited! Look up some other references on your own! Learn to use your test equipment properly!

You can believe whatever you want, but when you start delivering clearly incorrect information you can expect criticism from people who know better.

But you would be well advised to believe the engineers from National Instruments! And until you can demonstrate that you know how properly to use your test equipment... everyone would be well advised to question your measurements and your claims.

It may be in special cases (like truly symmetrical sinusoidal AC signals)  that there is no difference in the readings taken with AC vs. DC coupled scope channels. Is your system such a special case? It's easy to test. Does the displayed signal move up or down _at all_ when you switch from DC coupled to AC coupled? If it doesn't, then you have such a special case, but you should still  be using DC-coupled channels by default for _all measurements_ unless you have some good reason not to, so that you don't miss DC offsets or falsely change the average position of the signal.

Here's a demonstration I made a long time ago when LTseung was claiming OU from some JT measurements made with his scope AC-coupled.
http://www.youtube.com/watch?v=EVFyaQY6pR0

@TinselKoala,

So you're saying that perhaps the most accurate instrument that Human Kind has ever designed and built, with many decades of refinements, cant be trusted because of a high-pass filter that filters out DC components?

My Frequency was 394.4Hz - Really!!!

My Output was AC!

Go away, you're being stupid!

This information you have provided does not prove a single thing except that you have read the references! It certainly does not prove any measurement error! Besides, like I said, I am well past my second device now. This is now old tech for me. Its what I have decided to share with others!

Stop wasting everyone's time and distracting others! Let others work and get on with things!

Go and take pictures of your scope and stop bothering us!

Kind Regards

   Chris Sykes - hyiq.org
   To Reach New Horizons!

[TinselKoala]

A decoupling capacitor would be connected from the signal input to the ground. The AC-coupling capacitor on a scope channel is connected _IN SERIES_ with the scope probe, not to ground.

http://en.wikipedia.org/wiki/Decoupling_capacitor