Partnered Output Coils - Free Energy

[Farmhand]

ok I've got the input power side looking much the same as in Tinmans video, kinda like the effect Tinsel showed. Uploading a clip anyway just for the hell of it, i'll post the link when it's done. I got confused in the video for a second so have a laugh it's good for the soul. 

I just need to work out how to get to be able to measure an increased output as compared to the input now. I blew all my 21 Watt auto bulbs long ago so I need to find an appropriate load bulb or something.

Anyone got any drawn idea's for the external circuit ?

..

This clip shows the bulb being applied in series with one and both Field coils and being powered by the battery through the field coils, basically the bulb is in the field circuit and parallel to the rotor coils rather than in series with them. I think,. Also shown at the end is the current draw of the motor when it is powered with all coils in series eg. the field coils in series with the rotor coils.

https://www.youtube.com/watch?v=3rjEemA2ik8&feature=youtu.be

.

[gotoluc]

Thanks for your test video Farmhand.

The below is the circuit TinMan presented. Apparently the field coils are not connected to the brushes or rotor coil like you have in your video.

I'm glad you're on this as you are a great researcher.

Looking forward to more of your test videos

Thanks for sharing

Luc

[gotoluc]

The below is a collection of TinMan's posts I found to be informative.

TinMan's posts:
http://overunity.com/15395/partnered-output-coils-free-energy/msg453754/#msg453754
Q: Importantly, each Coil is drawn, as a parallel Connection to each other,
A: No they are not. Each coil is connected to the cap, but separated by the mosfet and diode.
Q: all Single Pole Electric Motors may not work for this reason!
A: Im not sure what your reason is,but it is true that not all universal motors will work straight up. Some may require that the coils be rewound on the stator -->as in the case of my larger universal motor.
Coils A and B's resistance is 3.2 ohms. At 10.4 volts across 3 ohms is only 3,25 amp's. The IRF540 will handle a
continuous drain current of 20 amp's at 100*C, and a pulsed current of 100 amps.
I think there was a mix up with the coil shorting and partnered coil situation...  What i was meaning is both situations cause a bucking magnetic field. I think many people here also are a bit confused as to how and where the magnetic fields are on the rotor in regards to the position of the stators magnetic field. The rotors fields are actually between (close to) the two stator fields, not close to the center of each stator field <-- im talking about the motor being in standard operation mode here.

http://overunity.com/15395/partnered-output-coils-free-energy/msg453788/#msg453788
Input wave forms are smooth, even without the caps, only very thin spikes from brush noise-nothing like the output.

http://overunity.com/15395/partnered-output-coils-free-energy/msg453878/#msg453878
Q: Shorted to What exactly? Shorted back on itself? Because the Built in Diode will do this Half Cycle on the Fet
anyway!
A: No it wont,if the current flow in the coil is opposite to what it needs to be,due to a magnetic field that is opposite to that of the rotors field.
A: I am using a bucking field effect between the rotor and coil B,not between coil B and coil A  -->unless you take
into account the inductive coupling between coils A and B via the steel laminated stator housing.
You mean universal motor's,that can be either AC or DC. It is true not all will work off the shelf,as some are wound to suit a certain configuration of operation.
Coils A and B are not partnered coil's. Each has it's own function.
Coil B's current can flow into the cap along with coil A's current for a brief period of time,but coil A's current cannot flow into coil B at any point.
And we will make sure those elusive dollars dont flow into the hands of the likes of teslatronix.
No it's not. It's bucking magnetic fields, which can be produced by your partnered coils,or via shorting a coil as i do.  I have no partnered coils in my setup.
Yes, coil B is shorted for part of the rotor segments induced time.

http://overunity.com/15395/partnered-output-coils-free-energy/msg453963/#msg453963     current flow.jpg
Q: the arrow in the symbol of the diode points to the direction of the conventional current (flow of + charge).
A  That is correct, and thus current cannot flow in the direction of the yellow arrow's (through coil A), but only in the direction of the red arrows (to the cap).

http://overunity.com/15395/partnered-output-coils-free-energy/msg453974/#msg453974
Q:  are you saying current flows from Coil B "electrically" to the output?  If so, is this current flow occurring when Coil B is not being shorted?
A:  Yes-coil B is the one that is shorted.
When coil B becomes open, then a small amount of current can flow back to the cap via the resistor -->this current is negligible, but every bit help's. I shouldnt even call it a current flow, but that is the result when you need to pull down the Fet.
Q:  Again, from your video explanation I understood the only effective current flow between Coil B and the rest of the circuit to be inductive when Coil B is shorted.  You seemed to indicate that Coil B was not a "generator" coil per se' but rather was only used to provide an inductive kick at the proper time.
A:  That is correct. Coil B's main job is to provide torque and to buck the rotors field at the right time. As i also explained in the video,this bucking effects coil A through the inductive path of the stator core,and thus the two coils are inductively coupled to each other as well as to the rotor.

http://overunity.com/15395/partnered-output-coils-free-energy/msg453980/#msg453980
Q:  The current flow you are depicting via the red arrows is a negligible amount of current, more akin to a bias current and does not represent a significant amount of the output current produced by the device.
A:  That is correct.  see current scope shots.

http://overunity.com/15395/partnered-output-coils-free-energy/msg453983/#msg453983
Q: There have been claim's that current from coil B flows through coil A
A: it dose not.
Q: Coil B is not shorted 
A: yes it is.
Q: The coil's are partnered 
A: no there not.
Q: Current is flowing from coil B
A: very little. Not even enough to light a 1/2 watt bulb.
Q: The resistor go's to the gate of the mosfet, and thus is fed current from the cap
A: really an assumption based on what you see in the schematic.

[Jimboot]

Wow thanks Luc! Sorry you had to wade through so much noise to get this. I'm copying and pasting this

[synchro1]

"The reactance of the armature winding can be lowered by placing a compensating winding on the
stator so that the fluxes oppose or "cancel" each other. This same compensating winding can be
connected in series with the armature winding. In this case, the motor is said to be conductively
compensated. Under these conditions, the universal motor will have similar operating characteristics
whether on AC or DC power.


The compensating winding may be simply shorted upon itself, so that it behaves like a shortcircuited
secondary of a transformer (the armature winding acting as the primary). The induced AC
current in the compensating winding again opposes or "bucks" the armature current and the motor
is said to be inductively compensated. The reactance of the field winding can be kept low by
limiting the number of turns".