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Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

Previous topic - Next topic

0 Members and 168 Guests are viewing this topic.

Brian516

my god.... is this a thread for grabbing at each other's throats???

I thought that it was to explore partnered output coils.....  transformers with the outputs in bucking configuration...
similar to the Joule Thief coil arrangement....
or should I just abandon the OU forum ship right now before I even get started????????

MileHigh

QuoteWOW I see this as a massive bag of worms! Many people will not even want to discuss this! Many will just want this to go away!

For starters you have to make a more serious measurement.

You measure the current flowing through L1 at the point when the MOSFET switches off.  Then you take your inductance meter and measure the inductance of L1.  I am assuming that L2 and L3 will cancel each other out to keep it simple.  So you do the calculation for the energy.

Okay, so you have a certain number of millijoules in L1 when it is ready to discharge.

Now with your scope you measure the current through L1 and the voltage across L1 and treat the entire string of components in the loop as the load.  That includes the wire itself that looks like different inductors.  You measure the energy discharge of L1 through the loop during the proper and precise time interval.

You compare the millijoules of energy in L1 with the amount of energy discharged into the loop.  If you want, you can just measure the energy that goes into the load resistor.

So those are the big measurements to make.  Do them properly and the two measurements should be very close in value.

MileHigh

P.S.:  It's a little bit more complicated than I state because L1 never fully discharges, it always has current circulating through it.  It's more like the energy change in L1 vs. the amount of energy that gets discharged into the loop.

EMJunkie

Quote from: Brian516 on February 04, 2015, 09:24:18 PM
my god.... is this a thread for grabbing at each other's throats???

I thought that it was to explore partnered output coils.....  transformers with the outputs in bucking configuration...
similar to the Joule Thief coil arrangement....
or should I just abandon the OU forum ship right now before I even get started????????

Hahaha yeah I know, gotta make sure you have the Chickens when feeding the Crocks!  ;)

EMJunkie

Quote from: MileHigh on February 04, 2015, 09:27:48 PM
For starters you have to make a more serious measurement.

You measure the current flowing through L1 at the point when the MOSFET switches off.  Then you take your inductance meter and measure the inductance of L1.  I am assuming that L2 and L3 will cancel each other out to keep it simple.  So you do the calculation for the energy.

Okay, so you have a certain number of millijoules in L1 when it is ready to discharge.

Now with your scope you measure the current through L1 and the voltage across L1 and treat the entire string of components in the loop as the load.  That includes the wire itself that looks like different inductors.  You measure the energy discharge of L1 through the loop during the proper and precise time interval.

You compare the millijoules of energy in L1 with the amount of energy discharged into the loop.  If you want, you can just measure the energy that goes into the load resistor.

So those are the big measurements to make.  Do them properly and the two measurements should be very close in value.

MileHigh

Yeah, again I hear you, see what youre saying, I agree... But:

From 0 Volts Terminal to Point C we have 3.3 Watts

From 0 Volts Terminal to Point B we have 1.4 Watts

But Across the Load we have only 0.68 Watts

So do you see where I am going with this?

We gain 1.3 Watts when Measuring relative from the 0 Volts Terminal, from Input to Output, not loose it!



We should see, 1.4 Watts (Input) - 0.68 (Output) = Total Power Relative used from 0 Volts Terminal

But we see, 1.4 Watts (Input) + 0.68 Watts (Load Power) + 1.3 Watts (Unknown) = Total Power Relative used from 0 Volts Terminal = 3.3 Watts Measured

EDIT: I mean, the point here is, we Measure Power from the Positive Terminal, relative to the 0 Volts Terminal don't we, so, we should be able to account for all power from the 0 Volts Terminal!

Pirate88179

Quote from: EMJunkie on February 04, 2015, 07:36:16 PM


If we can get to OU then maybe we must understand these Questions before we proceed! (Emphasis mine)



What do you mean IF?  First, you claimed 1.7 O.U. and now, within the past day or so, I saw a new figure from you of around 2.5 O.U.

Now you say we must understand these questions before we proceed.  Proceed to what?  Obtaining O.U.?  But, you have said that you have already done that so...............

I mean, I make a certain JT circuit.  I have no problems explaining to others how to replicate this circuit.  (Many have)  I do not tell them...."Well, you need to understand these questions...and...I took it apart and don't have it anymore...and...anyone that can't make this work is an idiot."

So, now we are back to IF?

IF this, then that?  But you said we already had "That".

Now I am confused.

Bill
See the Joule thief Circuit Diagrams, etc. topic here:
http://www.overunity.com/index.php?topic=6942.0;topicseen