Partnered Output Coils - Free Energy

[Grumage]

Is this a stand-up comedy routine?

NO. Just a severely cracked " Gramaphone" record!! 

Cheers Grum.

[MarkE]

I was just going from memory when I made the post, using the PWI you did without having the actual numbers in front of me.  I recalled that you found the result something a little over one Watt and that my input power was something around 7 Watts. 1/5, 1/6, it's still not chopped liver. The major uncertainties are in the input current level, so I'm hesitant to put 2 significant figures to the report. I'm happy to call it 5:1 input:output if you like, that would be closer to the actual values you used in the PWI.

Thanks for doing that integration by the way, I was too burned out last night to do it myself.

Thanks.

[MarkE]

Is this a stand-up comedy routine?

It has looked like a comedy routine from the start.  I am not sure I would call it stand-up though.

[TinselKoala]

Back on topic:

I have just checked the Input Current waveform to the EMJ-Meyer testboard. I have been citing "raw" inline DMM readings for input current. But the actual Vdrop across an inline Current Viewing Resistor has a waveshape that is, as one might expect, actually a "sharkfin" sawtooth kind of affair. So I have asked the old Link DSO to compute the "average" of this waveform. And lo and behold... the result agrees with the inline ammeter's reading, with an error of less than 10 percent. The ammeter actually reads a few percentage points less than the value from the DSO's computed average reading. So once again I think it is safe to conclude that DMMs do a pretty good job of returning a fairly accurate "average" reading on even pulse or sawtooth waveforms at relatively high frequencies.

So there is no major under- or over- estimation of input current by using the DMM inline in this case.

[EMJunkie]

@EMJ:

The post you linked quotes me:


But it conveniently omits the rest of what I said:

Now, where do you get "OU" from that?

"Ballpark",  very roughly  one-sixth of the input power is being dissipated in the neons, and they do get hot. Almost _none_ is being dissipated in the load resistor, whether the neons are in the circuit or the HV branch is left open. The load resistor doesn't warm perceptibly even after long periods of running. The transistor gets hot when it is fully driven, at current levels which your FG probably can't supply. In fact that is another source of error in your setup, whatever you are using to drive the transistor: It must supply significant power to the circuit to make the transistor work, and you have never accounted for this supply.

You say you know where the energy comes from....  so do I. It comes from the big honking power supply that's under my bench, and before that from the local grid, which gets it from a mix of sources: about 1/3 from coal-fired generators, 1/3 from a nuclear power plant, 1/6 from natural gas-fired generators and 1/6 from "renewables" (solar PV).

Not only that, but Synchro doesn't even think my version of your circuit works. I really don't think you can have it both ways.

So I say it's not OU, Synchro who sees OU in everything he looks at on YouTube says it's "a piece of crap"..... so why do you think it's OU?

I think I know why... it's because you can't provide results of your own that are any better than these, isn't it.

TK - merely pointing out that there has been a output measurement neglection.

You're on your way, you've noticed what I have already said and no one else could see.

You've not given any definitive figures on in/out I find this very interesting! Only rough guesses, 1/6th.... 1/3rd....

Anyway, this stand up comedian is sitting down waiting for a punch line, none I have seen yet, except more confirmations of what I have already said all along.

   Chris