Partnered Output Coils - Free Energy

[MarkE]

This is your post 94 back to PIH123's 92:

Quote from: PIH123 on January 21, 2015, 09:59:52 PM

    Hi EMJunkie

    Sorry, this may seem like more nitpicking and I know it can get tedious when someone asks what at first seem like an irrelevant question,
    but I think this one needs to be addressed if any measurements are to be considered.

    Could you please explain the scope display in your video at 4:01 in https://www.youtube.com/watch?v=ZhQgch4L5XY

    The scope is a PDS7102T so according to the user manual
    (http://www.ageta.hu/pdf/PDS7102T%20USER%20MANUAL.pdf page 14 item 15.)

    The icon "～" indicates the AC coupling

    If the channels were showing DC coupling, then we would see "-", but we don't.

    And according to http://www.phys.ufl.edu/courses/phy4802L/f05/lectures/oscilloscope.pdf pages 5 ad 6,
    AC coupling is used to Remove all DC information and also To observe small AC on top of large DC

    So What is the purpose of this display mode in this particular test ?
    and hence, Where are you showing the DC components of the channels ?

    I apologize in advance if I have missed that.

    Many Thanks

@PIH123

Scope was AC Coupled @10 per div. The Output is AC on this device, not DC. Input is chopped DC, Bi-Polar via a H-Bridge, which is also considered to be AC, just a AC Square wave.

Kind Regards

   Chris Sykes - hyiq.org
   To Reach New Horizons!

Do you still hold this view?

[MarkE]

So, given the circuit diagram you supplied below, what do you think it is that the scope probe is measuring?  What do you think it is measuring when you get your "huge difference" by moving the scope probe ground clip to the bottom of R1?  What major sources of error if any do you think either set-up might have?  When Q1 turns on where do you think energy goes in the circuit?  How about when Q1 turns off?

« Reply #907 on: February 05, 2015, 01:36:16 AM »

    Quote

Quote from: PIH123 on February 05, 2015, 01:03:49 AM

    In order for me to proceed to answer, I need a little input 1st.

    1. What is the exact circuit under test ?
    2. What are the component manufacturers and part numbers used ?
    3. Where you sourced them would be useful but not required.
    4. What equipment did you use to test ?
    5. What settings on that equipment ?
    6. Where was that equipment connected to the circuit.


    Without AT LEAST that info, I would be wasting my time replicating.

    There are others who are in progress with less than a month in this. (unfortunately, due to lack of up front info, most are guessing).
    You had 16 years.
    Why not just spill the beans.
    Your 9 out of 10 failures must have told you what not to do, and assuming you documented those failures,
    just dig out that info and divulge.

I have wasted no ones time, they have voluntarily attempted this.

I have raised Valid Points and questions!

If we can get to OU then maybe we must understand these Questions before we proceed!

See Itsu's YT Channel: https://www.youtube.com/watch?v=4EbNr3czXdQ&feature=youtu.be

Simply changing the Scope Ground Clamp from the 0 Voltage Terminal to the other side of the resistor gives a huge difference.

[EMJunkie]

This is your post 94 back to PIH123's 92:


@PIH123

Scope was AC Coupled @10 per div. The Output is AC on this device, not DC. Input is chopped DC, Bi-Polar via a H-Bridge, which is also considered to be AC, just a AC Square wave.

Kind Regards

   Chris Sykes - hyiq.org
   To Reach New Horizons!

Do you still hold this view?

Well done MarkE - You can Read! Excellent start!

[tinman]

So, given the circuit diagram you supplied below, what do you think it is that the scope probe is measuring?  What do you think it is measuring when you get your "huge difference" by moving the scope probe ground clip to the bottom of R1?  What major sources of error if any do you think either set-up might have?  When Q1 turns on where do you think energy goes in the circuit?  How about when Q1 turns off?

The scope would be measuring the big current loop between L1,L2 and L3-not to mention that the 10 ohm wire wound resistor would also be inductive.

[EMJunkie]

@Tinman - MarkE is trying to be Amazing again - Ignore the Troll...

So, given the circuit diagram you supplied below, what do you think it is that the scope probe is measuring?  What do you think it is measuring when you get your "huge difference" by moving the scope probe ground clip to the bottom of R1?  What major sources of error if any do you think either set-up might have?  When Q1 turns on where do you think energy goes in the circuit?  How about when Q1 turns off?

I have wasted no ones time, they have voluntarily attempted this.

I have raised Valid Points and questions!

If we can get to OU then maybe we must understand these Questions before we proceed!

See Itsu's YT Channel: https://www.youtube.com/watch?v=4EbNr3czXdQ&feature=youtu.be

Simply changing the Scope Ground Clamp from the 0 Voltage Terminal to the other side of the resistor gives a huge difference.

Stan Meyer used a variant of this Circuit. When this Circuit is done correctly, and as I stated before the GOON Squad started the ASSUMPTION Train, it was supposed to a "Resonant" Charging Circuit for a HHO Cell, which essentially was a Capacitor!!!

But alas, the GOON Squad could not keep their Beef Jerky in their pants and went off on all sorts of tangents!!! Some not even completing the Circuit properly and others giving up simply because it was too hard.

This is the Trolls Job!

Very Poorly Replicated Circuits that do not follow any of the given guidelines!

So, Stan Meyer's VIC is now Trollified also!

What a total mess!!! I just shake my head at these Buffoons!