Partnered Output Coils - Free Energy

[poynt99]

Here you go Brad.

Obviously I don't have all the values correct, but I did just throw this together having to guess at them.

However, it clearly illustrates the "below zero" current flow you are observing in your setup.

[tinman]

Here you go Brad.

Obviously I don't have all the values correct, but I did just throw this together having to guess at them.

However, it clearly illustrates the "below zero" current flow you are observing in your setup.

Nice going Darren.
So can you calculate the disipated power in L2 during the 5% on time of L1,and the disipated power from L2 during the off time of L1. Is  the disipated power of L2 during the off time of L1 100% of the disipated power by L2 during the on time of L1.

[tinman]

Brad,

You have a flyback diode across the primary, and this "rectifies" the current through the coil. You see it as voltage/current hanging below the 0 ref line. I explained this years ago. It is a little different here because you are seeing the effect on the secondary, but it has the same effect.

Your primary isn't actually "open" when the MOSFET is OFF, it is shorted by the flyback diode, and this "load" is seen by the secondary. I will do a simulation to show you what is happening. Let's hope this is the last time I have to go through this. 

.99

Darren
Yes,i know all this,but it is not the same. Im not sure if you have seen all the video's or not,but wound around the outside of the core along side the primary coil is a second coil with a turn ratio the same as the two coils within the center of the core. Below is a scope shot. The yellow trace is across a 2.2 ohm CSR(CSR1) that is in series with our load(globe) and the secondary coil that is wound along side the primary coil around the out side of the core.
The blue trace is across a CSR(CSR2) of the same type and value as CSR1,and is in series with our load(same type of globe)and inner secondary coil. Now,you will note that in the yellow trace you can see when the primary coil switches of,and a slight ringing follows. After that,there is no current flowing through that secondary that is wound right next to the primary-the magnetic field in the primary has collapsed. Now look at the blue trace,and here you see an almost stedy continuous current flow from the internal secondary to the load,and the two loads are identical.

I have confirmed tonight,that i can get 100% of the disipated power from the internal coil during the L1 on time when L1 is switched off. So if L2(the internal coil) disipates say 1 watt across the load during the on time of L1,i can also disipate another 1 watt across that same load during L1's off time. I know of no other system that can do this. My scope shows an average voltage of 0,and my DMM shows an average DC current of 0. I checked my DMM with the SG at the same frequency,and same resistive load,and the DMM is spot on. If i offset the square wave by just 1%,the DMM shows the offset current value. To have an average voltage value of 0,and an average DC current value of 0 over a set resistive load(in this case 33 ohms) ,that means the disipated power is the same in both directions.

You would also have to agree that the inductive kickback energy is always less,and even more so here where we have the voltage drop across the diode across L1. The yellow trace clearly shows when L1's magnetic field has disipated,and my point here is that that magnetic field that is no longer present around the outside of the core,is still extreemly strong within the core center,and remains long enough to maintain an almost constant current flow until L1 switches on again. Do you see the difference between your sim scope shot,and mine below.

[picowatt]

Tinman,

Did I understand you correctly, in response to one of my previous questions, that you do not have another core similar to the one inside the potted toroid?

PW

[picowatt]

Tinman,

Consider repeating the test performed to acquire the scope capture you posted in your last response to .99, using just fixed resistors as the load and without the lamps in the circuit.  You could up the R value of the load resistors to something closer to the hot bulb resistance. 

The lower peak voltage of the outer secondary is heating the bulb less, hence there is a greater load on it during the off time than the lamp on the inner secondary.  Fixed resistors would eliminate that load difference. 

This does not, however, address the apparent increased coupling between the primary and inner secondary.  Perhaps the plastic putty is less efficient as a core material than the inner core material.

Of course, this does not address the results observed when one of the inner windings was used as the primary.  Possibly you are unable to drive the inner primary at the same current level as the outer primary due to differences in wire resistance and/or inductance.

It might be worthwhile to repeat the "using an inner winding as a primary" and the "using the outer secondary" tests again and tweaking the FG's freq and duty cycle during those tests to determine if there is a more optimum operating point when those windings are utilized.

Just thinking out loud...

PW