Partnered Output Coils - Free Energy

[picowatt]

Yes-coil B is the one that is shorted.
When coil B become's open,then a small amount of current can flow back to the cap via the resistor-->this current is negligible,but every bit help's. I shouldnt even call it a current flow,but that is the result when you need to pull down the Fet

That is correct. Coil B's main job is to provide torque and to buck the rotors field at the right time. As i also explained in the video,this bucking effects coil A through the inductive path of the stator core,and thus the two coils are inductively coupled to each other as well as to the rotor.

PW-You need to add in the bit's that i spoke to you about via PM-the bits of the device i had concerns with.

OK, this explanation is more in line with my previous understanding and my confusion has evaporated a bit.

Is the following statement accurate?

The current flow you are depicting via the red arrows is a negligible amount of current, more akin to a bias current and does not represent a significant amount of the output current produced by the device.

PW

[EMJunkie]

OK, this explanation is more in line with my previous understanding and my confusion has evaporated a bit.

Is the following statement accurate?

The current flow you are depicting via the red arrows is a negligible amount of current, more akin to a bias current and does not represent a significant amount of the output current produced by the device.

PW

This is just getting more and more confusing!

If we are talking Gate Current, then 10.40 Volts on the Cap is going to do what? FET on 24/7 

Lets not forget that the IRF540 has an Internal Diode!

[EMJunkie]

Post Removed!


   Chris Sykes
       hyiq.org

[tinman]

OK, this explanation is more in line with my previous understanding and my confusion has evaporated a bit.

Is the following statement accurate?

The current flow you are depicting via the red arrows is a negligible amount of current, more akin to a bias current and does not represent a significant amount of the output current produced by the device.

PW

That is correct.

I want you to look at the two scope shot's below PW.
This is as close to my RT that i could whip up in a solid state version(to date). This is extremely close to the workings of the MEG<--believe it or not.

The input current is being measured over a 33 ohm resistor(yellow trace),and the output current is also being measured over a 33 ohm resistor(blue trace)-->no cap's,just straight from the inductor.
The first scope shot show's current in and out without the component of concern.
The second scope shot shows current in and out with that component installed.
No other parameters where changed during the installation of said component.

[tinman]

This is just getting more and more confusing!

If we are talking Gate Current, then 10.40 Volts on the Cap is going to do what? FET on 24/7 

Lets not forget that the IRF540 has an Internal Diode!

You are making assumptions EMJ that you know how the Fet is wired up.
I ask you this. If we take the simple SSG circuit that has a pot and resistor in series with the trigger coil/base and emitter of the transistor. The depicted series connection go's- emitter,trigger coil,pot,100 ohm resistor ,base. Would it matter if it went-emitter,100ohm resistor,pot,trigger coil,base ?.