Partnered Output Coils - Free Energy

[tinman]

Yes, that would be a fair description.

Does it makes sense to you? Do you see how an emf is induced in the secondary?

A good example that shows that the magnetic flux must extrude out side of the core in order to produce an EMF in the secondary,as the conducting wire is around the outside of the core,and not within the core where the magnetic flux is said to be contained. If a transformer is said to be 90% efficient,then 90% of the magnetic flux induced by the primary coil must be cutting the secondary coil.

You must also remember that the conducting wire !is! magnetically active when magnetic flux cuts this conductor. So as the conducting wire is rapped around the toroid core,it becomes part of that core,and thus the magnetic flux exist within the conducting wire as well.

[tinman]

Here is another demonstration done by JLN  https://www.youtube.com/watch?v=ZFZ4vxedHOY

Luc

There it is-right in that video.
The Jerard Morin overunity waste water pump rotor

[MileHigh]

A good example that shows that the magnetic flux must extrude out side of the core in order to produce an EMF in the secondary,as the conducting wire is around the outside of the core,and not within the core where the magnetic flux is said to be contained. If a transformer is said to be 90% efficient,then 90% of the magnetic flux induced by the primary coil must be cutting the secondary coil.

You must also remember that the conducting wire !is! magnetically active when magnetic flux cuts this conductor. So as the conducting wire is rapped around the toroid core,it becomes part of that core,and thus the magnetic flux exist within the conducting wire as well.

I'm baffled by your statement because I assumed we all take it for granted that we agree on the basics.  That being the changing magnetic flux that passes through the inside of a loop of coiled wire causes EMF to be generated across the two terminals of the loop.  The toroidal core is just a means of allowing more magnetic flux to pass through the loop of the wire.

For a toroidal core, very very little flux escapes the core.  No matter what kind of wire configuration we are using to make something to produce a magnetic field, we have to remember that the magnetic field produced by any small length of that wire has to form a closed loop around that wire, even if it takes a convoluted path.  This is an absolute constraint dictated by Nature.

Look at the attached diagram were I added an arrow to point out a small length of wire on the inside wall (smallest radius) of the toroid.  You can see that the magnetic field generated by that small length of wire can travel all the way around the inside of the toroid and complete the circle like that.  So for a wire that is flush to the inside face of the toroid, probably something like 99.99% of the flux produced by that length of wire passes through the toroid.  When you look at a segment of wire on the inside face of the toroid that is pretty easy to visualize.

When you look at a segment of wire flush to the outside face (largest radius) of the toroid, it's more difficult to visualize that the magnetic field produced by that segment of wire is also satisfying the requirement to form a closed loop around the wire by traveling through the toroidal core but it is.

Therefore, at low frequencies it does not matter if the coils wrapped around the toroidal core cover 10%, 50% or 100% of the circumference of the toroid.

When it comes to how flush the wire is to the toroid, if you wrap multiple layers of wire, one on top of the other, that also does not make much difference.  For sure the coils of wire on the top layers leak more magnetic flux outside of the toroid as compared to the coils of wire that are flush with the surface of the toroid.  The real question is by how much of a difference as compared to the flux that is traveling through the core itself and the answer is not much at all.

For this you can use the analogy of electrical resistance for permeability.  The top layer windings that are at some distance from the surface of the toroid see a ring of "air" and a center toroidal core when you look at a cross-sectional slice of the doughnut.    That looks something like a 10 ohm resistor in parallel with a 0.01 ohm resistor.  The "magnetic current" will mostly flow through the 0.01 ohm resistor and "bypass" the 10 ohm resistor.

The moral of the story is that if you are going to make your own toroidal transformer and will be operating it at relatively low frequencies and not very high power levels then a "quick and dirty" winding of the coils will be 99.9% as good as spending hours meticulously winding the coils and making it all neat and perfect.

[gotoluc]

Great examples. So is your diode acting like a flyback diode and killing the back spike or it feeds the back spike back into the coil some how? Does it matter which way your coils are wound?

Yes, like a flyback diode except the diode is connected across the coil which feeds back the flyback and seems to hold the magnetic field longer then the input pulse.
See below scope shots of no diode vs with diode.

Luc

[MileHigh]

A good example that shows that the magnetic flux must extrude out side of the core in order to produce an EMF in the secondary,as the conducting wire is around the outside of the core,and not within the core where the magnetic flux is said to be contained. If a transformer is said to be 90% efficient,then 90% of the magnetic flux induced by the primary coil must be cutting the secondary coil.

You must also remember that the conducting wire !is! magnetically active when magnetic flux cuts this conductor. So as the conducting wire is rapped around the toroid core,it becomes part of that core,and thus the magnetic flux exist within the conducting wire as well.

As a follow-up to my previous posting, probably something like 99.5% or more of the flux produced by the primary will cut the secondary of the coil.   You can assume that there are two main factors influencing the efficiency of the transformer, 1) the resistances of the primary and secondary, and you can't forget that this is also load dependent, and 2) the hysteresis and other losses that you get for a given core material.   Then if you start talking about frequency, then as you sweep the input frequency of the transformer then you can assume that the efficiency of the transformer will change.  Naturally at very high frequencies capacitive effects come into play and will affect the efficiency.

There is a simple way to take a crash course in all of these matters.  Just find detailed datasheets from a few manufacturers for a few types of transformers and study them in detail:  1) power distribution utility transformers, 2) small power transformers for powering electronics and appliances. and 3) small PCB-type low-power signal transformers.