Partnered Output Coils - Free Energy

[tinman]

The things PW and I asked for are not too complicated.

Why dismiss the anomaly and move on without investigating? Have a look at the diagram again, in particular the two voltage measurements on the secondary, i.e. 1.48V and 128mV.

The current through a resistor is the voltage across it over the resistance value. Calculate the current in R2 and R3, based on the voltage across each. Are they equal? Why not?

We both mentioned this anomaly, but you have not commented on it that I've seen.

Why is it that we can have water flowing through a pipe at high pressure and at one point in that pipe have no pressure-but the water still flows at the same volume.

Like i said to PW-i can only go by what me equipment shows me.
there is a 1.19mA difference between the two,and you have chose to use the low current measurement. So what if it is the higher current of the two that is correct?.
Also,are you able to work out the real power on the input due to the phase shift from the scope shots i provided earlier?-this is also something that seems to be ignored.

So going on the low side,our transformer is 94 odd% efficient. Now if we look at the outer secondary,the efficiency is a mere 62% efficient. Now,the efficiency is low in regards to a normal setup between the primary and outer secondary because of the poor construction of the transformer it self-->badly wound,and poor core material,and yet we have an efficiency above 94% between the primary and inner secondary. So what happens if we improve the transformer quality,so as we get say an 80% efficiency between the primary and outer secondary?-->what will the efficiency be between the primary and inner secondary then?.

Anyway,i will keep chugging away at it for a while yet.

[picowatt]

Why is it that we can have water flowing through a pipe at high pressure and at one point in that pipe have no pressure-but the water still flows at the same volume.

Tinman,

In this water analogy, pressure is voltage, flow volume is current.  Your example varies the pressure (voltage) at various points, while maintaining the same flow (current) throughout.

I don't understand your apparent objection to refining your measurement accuracy or investigating the observed measurement discrepancy.  Most likely your measured CSR value is incorrect.  At least consider acquiring some Caddock MP800 or 900 series resistors for CSR use at some point.  They are very low inductance with a 1% tolerance and low TC.

Also, 0.1%, 1/4 watt metal film resistors (with low TC) are readily available at very low cost and having several different values in a drawer (1, 10, 100, 1000, 10K) are very useful for checking ohmmeter calibration.

PW

[Magluvin]

If you apply an input to the inner secondary, the inner most core would have a mag field going in one direction and the outer most core would have a field going in the other direction. That may scramble understanding it as a secondary when it carries current induced by the primary.

And if we apply an input to the inner secondary, and the outer core has a field, opposite of the inner most core, but still a field, would there be an E field outside of the core?

Mags

[tinman]

Tinman,

In this water analogy, pressure is voltage, flow volume is current.  Your example varies the pressure (voltage) at various points, while maintaining the same flow (current) throughout.

  Most likely your measured CSR value is incorrect.  At least consider acquiring some Caddock MP800 or 900 series resistors for CSR use at some point.  They are very low inductance with a 1% tolerance and low TC.

Also, 0.1%, 1/4 watt metal film resistors (with low TC) are readily available at very low cost and having several different values in a drawer (1, 10, 100, 1000, 10K) are very useful for checking ohmmeter calibration.

PW

I don't understand your apparent objection to refining your measurement accuracy or investigating the observed measurement discrepancy.

I have no objection toward refining my measurements. What i do object to is the bias toward my measurement errors having to be in the negative. Read all the post from people in the !know!,and you will soon see it's almost as though they insist that i keep measuring until i meat the expected criteria-->under unity. Not once have i seen any of those in the know that have said-hey,due to the phase shift on the input,the input you calculated will be higher than it actually is. Nor have i seen any of those in the know say that the error on the output could be in favor of the calculated output-it's always assumed to be in the negative.

What becomes apparent is-no mater how far you go to insure correct measurements,it is never enough unless it shows a COP<1. As long as it remains within known physics,then it's all good. As soon as it go's beyond the !must adhere to! known science,then there is always errors some where. The more i do,the more is requested-->fair enough. But when you start to get comments like-your scope is wrong,your meters are wrong-and so on,it gets a bit anoying. Then you have to go ahead and start proving that your equipment is reading correct,and start supplying references to equipment error margins. So i post a link to a website that offers these error margine's,and i make a video showing that my scope,the SG and even the DMM all read the same value's-exactly. But still my resistor values are incorrect,as things just dont add up. I swap out the two 10.3 ohm resistor's with each other,and the output remains exactly the same-along with the input. I then change out the 100 ohm resistor for another that is close to the 98.3 ohm's,and still things remain the same.

So why is there a discrepancy at the output?--i do not know. As i said,i can only be as accurate as my equipment. Anyway,off to jaycar now to see if they have any of these high end CVR's,although i have a feeling even that will not be enough,and it will once again become equipment error.

[EMJunkie]

@Tinman

Once you have done this a few times, you will think "Wow this was easy!"

Watch: Phase measurement - Keith Hekman

Attached are 2 x apps, Power Calculator and Phase Angle Calculator.

Use the Circuit you are already familiar with to measure the Voltage and Current on your Scope.

   Chris Sykes
       hyiq.org