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Overunity Machines Forum



Sharing ideas on how to make a more efficent motor using Flyback (MODERATED)

Started by gotoluc, November 10, 2015, 07:11:57 PM

Previous topic - Next topic

0 Members and 9 Guests are viewing this topic.

tinman

Quote from: Erfinder on December 11, 2015, 11:27:34 AM

It sad that more experimenters working with pulsed machines don't know realize this!



It's well established that CEMF limits the input current.  When CEMF and its generating mechanism is "truly" comprehended, we will then be in the position to reverse the effect CEMF has on the input current, specifically, we should note current increase with increasing RPM and CEMF, versus the well known decrease in current with increasing RPM and CEMF.  This would constitute something akin to a phase shift, far removed from the text book definition of a phase shift.   This is the condition I establish in my machines.




Regard

Yes Erfinder.
But we do our best to show what we can.
Is a magnet doing useful work when it alone is responsible for increasing the efficiency of a device or system ?.

The screen shots you see below are across the emitter/collector.

Enjoy.

https://www.youtube.com/watch?v=tVNABy8fSlI


Brad

verpies

Quote from: tinman on December 11, 2015, 10:15:45 AM
The opposite is actually true.
Having permanent magnets on the rotor actually increases the efficiency of the motor in two way's.
I know that there is more torque when the rotor is made out of magnets, but torque is a different concept than O/I efficiency.
These types of motors can have two output energies: the mechanical output and recovered electric energy.

Quote from: tinman on December 11, 2015, 10:15:45 AM
First,the magnets actually generate a current within the drive coil,and this is additive to the inductive kickback output energy-so the inductive kickback output will rise.
I think that the approaching attracted magnets generate current that is subtractive to  the "inductive kickback output energy".
In other words: the current generated by the approaching attracted magnets, subtracts from the external current that made the coil an attracting electromagnet in the first place.
If I am wrong about this point then you've already won the OU prize.

Quote from: tinman on December 11, 2015, 10:15:45 AM
Second,the power consumption (P/in) will also drop when a rotor with magnets is used,as apposed to there being no rotor at all.
That's to be expected when the total current flowing through the coil decreases.

Quote from: tinman on December 11, 2015, 10:15:45 AM
This is of course using a non ideal coil,as we cannot make an ideal coil.
Note that a ferro-cored coil is less ideal than an air coil, so there are different grades of non-ideality.

Quote from: tinman on December 11, 2015, 10:15:45 AM
The problem here is that it takes energy to align those domains in the first place,so there will be no gain to be had this way.
Of course, but if the entire energy required to align those domains can be recovered back at TDC (even in theory) and in the meanwhile the attraction to these aligned domains has performed mechanical work, then there is gain to be had.

tinman

Quote from: verpies on December 11, 2015, 11:42:21 AM
I know that there is more torque when the rotor is made out of magnets, but torque is a different concept than O/I efficiency.
These types of motors can have two output energies: the mechanical attraction and recovered electric energy.
I think that the approaching attracted magnets generate current that is subtractive to  the "inductive kickback output energy".
In other words: the current generated by the approaching attracted magnets, subtracts from the external current that made the coil an attracting electromagnet in the first place.
If I am wrong about this point then you've already won the OU prize.
That's to be expected when the total current flowing through the coil decreases.
This is of course using a non ideal coil,as we cannot make an ideal coil.
Of course, but if the energy required to align those domains can be recovered back at TDC and in the meanwhile the attraction to these aligned domains performed mechanical work, then there is gain to be had.

QuoteI think that the approaching attracted magnets generate current that is subtractive to  the "inductive kickback output energy".

Verpies
Watch the video i just posted a few post back. Here is the link again.
What happens when we have alternating magnets?. ;)

https://www.youtube.com/watch?v=tVNABy8fSlI

Brad

verpies

Quote from: tinman on December 11, 2015, 11:47:53 AM
Verpies
Watch the video i just posted a few post back. Here is the link again.
What happens when we have alternating magnets?. ;)
When we have magnets with N poles sticking out, alternating with magnets with S poles sticking out, while the coil is supplied with unipolar Pulsating DC, then half of the time a repelling magnet is approaching the coil and in such case it is my opinion that the flux of this magnet induces current that adds to the current already circulating in the coil.

The other half of the time, when an attracting magnet is approaching the coil, the flux of this magnet induces current that subtracts from the current already circulating in the coil.


Quote from: tinman on December 11, 2015, 11:47:53 AM
https://www.youtube.com/watch?v=tVNABy8fSlI
I can't put the schematic together in my mind.  Unlike Hoppy, I am not very good in analyzing wired connections in videos :( .

Without knowing the schematic, the only objection that I can make now is that you are measuring a voltage across a capacitor (behind a diode) and if that voltage is supposed to represent the energy recovered from the coil, then that is an accurate measure only without that 100Ω resistor across it and when starting with an empty capacitor.

tinman

Quote from: verpies on December 11, 2015, 01:43:14 PM
When we have magnets with N poles sticking out, alternating with magnets with S poles sticking out, while the coil is supplied with unipolar Pulsating DC, then half of the time a repelling magnet is approaching the coil and in such case it is my opinion that the flux of this magnet induces current that adds to the current already circulating in the coil.

The other half of the time, when an attracting magnet is approaching the coil, the flux of this magnet induces current that subtracts from the current already circulating in the coil.


Without knowing the schematic, the only objection that I can make now is that you are measuring a voltage across a capacitor (behind a diode) and if that voltage is supposed to represent the energy recovered from the coil, then that is an accurate measure only without that 100Ω resistor across it and when starting with an empty capacitor.

QuoteI can't put the schematic together in my mind.  Unlike Hoppy, I am not very good in analyzing wired connections in videos :( .

Circuit below.

Inductive kickback dissipated across R1.