Sharing ideas on how to make a more efficent motor using Flyback (MODERATED)

[tinman]

Brad,  here i have the "on time" shown when running (white trace) and when stopped (purple trace) on top of each other.
It does not show any difference, only the spike (outside the "on time") is higher.
Its point C compared to point B (ground lead) in the earlier shown diagram.


Itsu

And that is what we would expect to see.
You can see that the induced reversed voltage dose not change the voltage across the coil during the on time,as the coil is basically shorted across the battery,and would be seeing the battery voltage only. The induced reverse voltage is an open voltage only,and voltage alone is not power. So at this point in time,the rotor is not returning any of it's stored energy back to the system,as the circuit is open. But what has happened is this-
Lets say your coil is producing a north field at the rotor end of the coil when the mosfet switches on. I will also have a guess that this is when the north out magnet on the rotor has just passed the coils core--as mine dose. So the coil now pushes the north magnet away,and draws the south magnet toward it. But also,as the north magnet has just passed the coils core,the core will already have the correct induced magnetic flux from that passing north magnet,and so,less power from your supply is required to align the magnetic domains within the core,as they have already been mostly aligned by the passing magnet.


Brad

[poynt99]

Like Itsu said-the rotor seems to be putting more energy back into the system than it takes to run it.

I did not see itsu say that anywhere.

[tinman]

I did not see itsu say that anywhere.

Post 656: http://overunity.com/16167/sharing-ideas-on-how-to-make-a-more-efficent-motor-using-flyback-moderated/msg470141/#msg470141

Quote:
This "negative-induced voltage in series with the battery voltage", or "EMF superposition" seems stronger then the driving power for the rotor.

[poynt99]

OK, thanks.

I'm not sure how one would come to that hypothesis. Obviously it can not be true. Only a portion of the stored energy is returned each cycle.

[itsu]

Well, thats the problem with words, they can be explained differently as one had originally intended, if not selected carefully, like in this case.

What i was trying to say was that it looks like the magnets (fields) are inducing this "negative-induced voltage in series with the battery voltage"
against the power needed to drive the coil.

So at that instance, this "negative-induced voltage" seems stronger then the driving power for the rotor (otherwise we would not "see" the effects
of this "negative-induced voltage"), but it does not mean that "the rotor seems to be putting more energy back into the system than it takes to run it"

Itsu