Free energy with Seesaw and Kinetic movement

[Low-Q]

The main problem is you are calculating kinetic energy without applying force .
just tell me only that  what will be the kinetic energy of a 100 gram ball if we apply 1 newton force on it?

The formula of kinetic energy is 1/2 * m(V*V). There is no way around this formula.
The force is applied in advance, so it is already included. Because without the force, there will be no velocity V.

[vikram_gupta11]

Dear Sir,
I have started worked to build this device and will present a working model before this community soon.

Vikram

[Low-Q]

what will be the kinetic energy of a 100 gram ball if we apply 1 newton force on it

I forgot to answer this question.
Applying 1N to a 100g mass will provide an acceleration of exactly 10m/s^2. The kinetic energy will increase with time as the mass increase in velocity.
After 1 second the velocity is 10m/s, so Ke is therfor 1/2 * 0.1(10*10)= 5 Joule.
After 2 seconds, Ke is 20 Joule because velocity is 20m/s
After 3 seconds, Ke is 45 Joule because velocity is 30m/s
4 seconds, 80 Joule because velocity is 40m/s.


Vidar

[vikram_gupta11]

 So tell me where I'm wrong ?I'm not wrong and my calculations are very much correct if you read the entire post carefully and this is 101% an overunity device.

Vikram

[Low-Q]

I think you should continue to build it. I can obviously not explain in words that you are wrong, because you deny the fundamental physics, so you have to experience this in practice.
I whish you a honest good luck with your project.


Vidar