Energy from water arc explosions

[pomodoro]

No. We are talking about a beaker with sodium carbonate and two tungsten electrodes. A DC current is passed. Its impossible to pass a DC current for any time longer than that required to charge the double layer and not have a chemical reaction at both electrodes. The cathode may have a plasma sheath but hydrogen will surely be made at the plasma/water interface, just as oxygen or oxide, hydroxide or carbonate, depending on the anode metal will be made at the anode.


The reason is simple. As soon as the voltage at the double layer at each electrode exceeds that required by the ions to reduce or oxidize, there is an acceptance of an electron at the cathode and a release at the anode. A chemical reaction occurs. 

[Zephir]

As soon as the voltage at the double layer at each electrode exceeds that required by the ions to reduce or oxidize, there is an acceptance of an electron at the cathode and a release at the anode. A chemical reaction occurs.

Some chemical corrosion always occurs, but ideal plasma electrolysis has electrodes solely surrounded with coat of water vapor filled with plasma, so that the electrode actually doesn't touch the electrolyte due to Leidenfrost effect. This regime can be also recognized with sudden change of discharge color above certain limit of input power, once the electrode switches itself from electrolysis mode into a plasma discharge mode.

Albert Einstein: "Make things as simple as possible, but not simpler".

[pomodoro]

No, the plasma is an extension of the electrode. At the plasma/electrolyte interface , is where the electrolysis occurs. Well the cathodic reaction only that is. Interesting, its easier for the anode to strike an arc but as it is believed that some kind of cold fusion occurs, it is the cathode that is chosen as the arcing electrode as that is where hydrogen is formed, by you guessed it, ELECTROLYSIS! The tungsten cathode is meant to have some hydrogen embrittlement before it produces OU . Some prayers might help too.


This plasma electrolysis has nothing to do with magical plasma OU like in gas discharge tubes, its all about cold fusion of hydrogen. Or perhaps warm fusion.

[Zephir]

You should really delete yourself from here - but not for hostility toward overunity concept, but for insufficient mental capacity, which is primary reason of this attitude. Did you ever play with high voltage over surface of water? Well, it's not difficult to achieve the circuit closed with water surface, even when both electrodes are outside the water: the discharge comes from first electrode to water, the current passes the water and another discharge comes from it through air into another electrode. Because both electrodes don't touch the water, no electrolysis can run on them and the transfer of current is solely electronic - i.e. no ions participate on it.

The ideal plasma electrolysis is the same process, except that both electrodes are immersed, but they still remain separated from water with layer of ionized water vapor (at least one of them). Only their arrangement is similar to electrolysis, the chemistry and physics not. Not to say, that many experiments (Energoniva) utilize high frequency current - so no electrolysis can run on electrodes even at the second electrode.

This plasma electrolysis has nothing to do with magical plasma OU like in gas discharge tubes, its all about cold fusion of hydrogen. Or perhaps warm fusion

Or perhaps because of hydrinos. Or perhaps condensed plasmoids. Or perhaps due to recombination of atomic gases. We simply don't know. The overunity has been observed in various plasmas other than hydrogen too (there is whole thread about it). So I seriously doubt, that the cold fusion will be involved in all these cases.

[pomodoro]

. Because both electrodes don't touch the water, no electrolysis can run on them and the transfer of current is solely electronic - i.e. no ions participate on it.

This is a massively retarded statement. Try it  with doubly distilled water that has no ions and see what a massive arc you get.  You get no conduction at all, apart from the miniscule dissociation of water giving a resistivity of 18Mcm.  But you will get conduction if there is no water phase and only vapor, but you stated that there is water liquid between the electrodes right?

Since you like your journals so much go find one with DC, yes DC only,  passage of current through liquid water  involving no chemical reduction or oxidation at the interface with electrodes or plasma.  Even the Grotthuss mechanism requires reduction of the proton at the cathode.

There is no frigging DC conduction through water without some type of electrolysis  unless the water is  completely gaseous between the electrodes and thus becomes ionized.  AC current at a high enough frequency can, as it is capacitivilely coupled through the double layer.  But you did not see to know that did you.  I deliberately left it out before  to check your knowledge.
It can even do it al lower frequency , so long as the reactions are completely reversible, you better look reversible  up quick, for your next smartass reply.

So please , show us, with real science,  you know some nice journal, how water, liquid water, not vapour, magically conducts a DC current without electrolysis at the water to electric source interface.

Oh finally just to rub it it, have you , yes you tried using Zinc Sulfate, or copper sulfate as the electrolyte,  youll be very embarassed indeed when you see the mass of zinc or copper engulfing the beaker right where the plasma is , Oh dear..