Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



A3C & X-MAGNETS AND PMF.

Started by ageofmagnetizm, May 19, 2017, 08:07:51 PM

Previous topic - Next topic

0 Members and 3 Guests are viewing this topic.

ageofmagnetizm

Sparkmen,
once you consider that if multimeter is connected in single circuit
with generator and load - then measurements of AC voltage and resistance
are impropper for comprehension of Powers. While before, Gyulasun and many
others wher persuating me that inclussion of resistors in series will show the true Power
of loaded generator and will produces decelaration of rotor and much lover voltage.
This went to be unrelating to my design of coils on C-Cores and with loads voltage and
RPM is the same as without loads.


Your point is that loads need to be meassured with AC voltmeter connecting in parallel circuit,
I agree that all kinds of measurements are useful, but -
please explaine how do you count powers from so obtained results, on your link no mentions of such calculations.


For exzample: if measuremnts are taken with standard portable fuel generator of known
220 AC voltage being connected to standard 10 watt and tnen 30 watt lamps ,
and voltmeter connecting in paralel circuit shows 100 AC volts and then 10 AC volts.
How do you calculate Power of portable generator, plaese explain this and provide some link so that everybody
can understand why such methods are even beter...


Belfior

Would it be possible to just rectify to DC and then use a DC load to check the power? I mean you get a voltage drop from the bridge, but then you have DC without any reactance or frequency bullshit, that might cause measurements to fail.

https://www.aliexpress.com/wholesale?catId=0&initiative_id=SB_20180513232810&SearchText=dc+load


ageofmagnetizm

Digital multimeters have rectifiers build inside,


But I was asking why meassuments in parallel circuits are better than
maesurment in series, and how one use parallel circuits to calculate power of standart
Generator.


Please post here no links advertizing for sale offers or donations seaking web sites.

gyulasun

Quote from: ageofmagnetizm on May 14, 2018, 01:41:36 AM
Sparkmen,
once you consider that if multimeter is connected in single circuit
with generator and load - then measurements of AC voltage and resistance
are impropper for comprehension of Powers. While before, Gyulasun and many
others wher persuating me that inclussion of resistors in series will show the true Power
of loaded generator and will produces decelaration of rotor and much lover voltage.
This went to be unrelating to my design of coils on C-Cores and with loads voltage and
RPM is the same as without loads.

Your point is that loads need to be meassured with AC voltmeter connecting in parallel circuit,
I agree that all kinds of measurements are useful, but -
please explaine how do you count powers from so obtained results, on your link no mentions of such calculations.

For exzample: if measuremnts are taken with standard portable fuel generator of known
220 AC voltage being connected to standard 10 watt and tnen 30 watt lamps ,
and voltmeter connecting in paralel circuit shows 100 AC volts and then 10 AC volts.
How do you calculate Power of portable generator, plaese explain this and provide some link so that everybody
can understand why such methods are even better...


Hi ageofmagnetizm,

I travelled abroad for a few days and went through your recent posts now. You asked a question this morning
from sparkmen, I put your text in bold to show what I mean but briefly it is: how you measure and or calculate
power consumed by a load when an AC voltmeter is in parallel with a load. 

To help you understand this: you need to have some background knowledge to arrive at a correct answer.

1) standard lamps with their rated 10W or 30W or whatever power should receive 220V AC to behave as a
10W or 30W (or whatever) load, otherwise their loading effect back to the generator will be much less. 
Be it either an incandescent or LED or other lamp, they change their current consumption nonlinearly when the
operating voltage differs from 220V.  This is why an AC Ampermeter is needed in series with such lamps to check
actual AC current taken by the lamp and also you would need to use an AC voltmeter across the lamp to see the
actual voltage feeding the lamp.  (I am aware your DMMs cannot measure AC current.)

2) you surely know why a standard 10W lamp may have only 100V AC across it when connected in parallel with a
220V AC generator output which showed the 220V AC output voltage before the lamp was connected? 
I think you know why this is so.
If not, then I can give you the explanation later on, question is whether you are going to disregard it or will
accept it. I say this because you wrote above that for your coils on C cores this is unrelated when you load them.

3) even if you measure the AC current with an Ampermeter in series with a load, you have to know whether the
measured AC voltage across the load is in phase or not with that measured AC current: if not, than you need to
estimate the phase angle, phi, somehow (say by a two channel oscilloscope) and  multiply the cosine value of this
angle by the measured RMS voltage and current values. The formula is well known in AC circuits: P=Vrms*Irms*cos(phi)
An incandescent lamp run at low frequencies like 50-60 or say at even 200 Hz will surely cause a negligible phase
shift between its own current and voltage so cos(0°)=1 i.e. its power factor is 1, you surely have heard about this.

So the point is: when you have less AC voltage feeding a bulb which was manufactured for 220V AC operation and
consumes its rated 10W or 30W (or whatever) power only when it is run from 220V AC, the only way to know how
many Watts it actually takes from a generator is to measure its current and feeding voltage in RMS and multiply the
two values. If the lamp is say a kind of fluorescense or say a LED, then the phase angle between the current and
voltage is to be measured too.

Gyula

gyulasun

Quote from: ageofmagnetizm on May 14, 2018, 04:03:03 AM
Digital multimeters have rectifiers build inside,

Correct.  But this has nothing to do with what member Belfior suggested above. 
Understand: he meant to use a full wave diode bridge across the output of the generator coil and the DC output
of the bridge is fed into a puffer capacitor and then your load is run from this DC voltage. This way the measurements
of DC current feeding the load and the DC voltage across the load can be measured with your DMMs because they can
measure DC current (but not AC current).  Measuring DC quantities gives results that are very very close to reality.

Quote
But I was asking why meassuments in parallel circuits are better than
maesurment in series, and how one use parallel circuits to calculate power of standart
Generator.
....

"Why meassuments in parallel circuits are better than measurment in series..."  I can answer this, this is point # 2 in
my above answer too.  I wonder whether you would make a short video on the parallel measurements?

Gyula