Confirmation of OU devices and claims

[gyulasun]

Hi Nick,

This was the core of my earlier post where I finished it yesterday:

...
In the present setup discussed here the receiver coils are very close to the TX coil, within a small fraction of a wavelength.
This inherently involves mutual coupling not only between the TX and RX coils but between the RX coils too. So basically adding
more and more receiver coils would demand more TX power if the TX (antenna) circuit were a parallel LC circuit. But the TX circuit here is a series LC circuit driven from a function generator or from a gate driver IC. 
Consider the impedance behaviour of parallel LC and series LC circuits in the function of frequency.
...

And this was the core of your latest answer to me:

   ...
   As itsu has shown a slight decrease in input power, while adding more coils onto the main coil, what makes this possible is the question at hand. And how many other coils can also tap into that near field, while dropping the input even lower, to actually obtain a higher output, than the input. Of course, that is still to be seen, replicated and shown. Whether one believes it, or not, is up to each person's discretion.

First I continue with well known things: the impedance of a parallel LC circuit is high at resonance (several tens of kOhm and higher) and the impedance of a series LC circuit is low (from a few Ohms down to a fraction of an Ohm), the latter depends mainly on whether the coil is wound with relatively thin or thick wire, whether has a lossy core or the core has very little eddy current and hysteresis losses, and  whether the tuning capacitor is of relatively good quality. Practically the DC resistance of the coil can dominate the series LC circuit impedance at resonance when there is no any other coil coupled to it.

Now let's consider this: our gate driver IC drives the series LC TX circuit at its resonant frequency and we couple a parallel LC circuit to it (also resonant at the same frequency). Induced voltage appears across the coupled LC circuit and if now we load this parallel LC circuit, the induced voltage amplitude will be reduced. However what is also very important here is that due to the mutual electromagnetic coupling between the two LC circuits, they influence each other's resonant impedance like this: the moment our load appears across our coupled LC circuit, this reflects back to the TX series LC circuit in the form of an increased series resistance. They influence each other's resonant frequency of course but we retune and fine tune them as needed for best energy transfer, changing also the coupling factor by the distance. If we do not retune the LC circuits, then the AC impedance of the small off tuned LC TX circuit also increases even though we have not loaded the coupled LC circuit yet. This is why I mentioned above the impedance behaviour of series and parallel LC circuits in the function of frequency. 

When the resonant impedance of the TX circuit increases from say its original 1 Ohm example value to a 3 Ohm transformed back impedance, then naturally the gate driver IC can drive less current into the same TX circuit than it could in the previous unloaded coupled circuit case. This is important to understand: more and more coupled coils will increase the series impedance of the series LC TX circuit higher and higher. 
This process manifests measurably across the TX coil and capacitor: their resonant voltage amplitude gradually decreases, say from the initial some kV to as low as some hundred volts or lower. 
In return for this, the AC current taken out from the output pin of the driver IC will decrease according to the increasing number of the satellite coils and a decreasing AC current involves a decreasing DC current draw by the driver IC from its DC supply.  This process inherently involves a decreasing input power draw by the gate driver IC of course, hence the EM field the TX coil creates around itself will also decrease gradually.   

If there is a trick or two here which still maintains the high level of oscillations in the LC circuits close to each other, then it has not been revealed. The so called DS effect whereby electrons are taken from the Earth via a ground wire and the useful output gets enhanced is not proven yet for us to give the COP > 1 claim so it remains a claim.  A.king21 recently reported his measured results of the effect of grounding: it increased output power by some milliwatts if I recall correctly.  Also, a quarter wave trick is mentioned, with no proof yet for us.  Of course, members tell lies in forums, in videos etc. so nothing can be proved by these... 

We may need to clarify what a gate driver IC does?  It does the same what a function generator, FG (set to square wave output) does: it switches a given (adjustable) voltage amplitude onto a load at one moment and takes it away at another moment (square wave amplitude and frequency). Both the FG and the IC output pin have a low output impedance (normally 50 Ohm for an FG and much less than that for gate drivers) so when the voltage is taken away the low impedance remains. In fact the low output impedance is present all the time regardless of the voltage amplitude between the 'hot' output and the negative supply rail or common ground. 

Let's suppose (for simplicity) the DC resistance of TX coil is again 1 Ohm I already wrote above as an example. When we drive this series LC by an FG at the resonant frequency, the 50 Ohm impedance of the FG comes in series with this 1 Ohm to form a closed circuit via the series LC components. Suppose the FG is set to 10 Vp unloaded output voltage and you connect the series LC at resonance across the FG output. So you load down the 50 Ohm output of the FG practically by 1 Ohm. The 10 Vp reduces to a much smaller output voltage i.e. to 0.196 Vp (voltage division between 50 and 1 Ohm). And a peak AC current of 0.196 Amper will be maintained in the series LC circuit. 

Now what happens when you use a gate driver to drive the series LC TX circuit? A decent gate driver can have an output impedance of around 1 Ohm. So it would drive a load of 1 Ohm, represented by the series LC TX circuit at resonance when no coupled satellite circuits are present. If the driver IC is fed from 10 V DC, its unloaded output voltage changes between quasi zero and 10 V peak voltage (a normal 50% duty cycle square wave) when driven from an FG.  If we load the output pin of the IC by the 1 Ohm resonant AC impedance of the TX circuit, the output voltage would drop to 5 V peak voltage due to the voltage divison between the 1 Ohm internal and 1 Ohm load impedance. And a peak AC current of 5 amper will be maintained in the series LC TX circuit.  Confront this to the case of the same TX LC circuit when driven by the FG that has the 50 Ohm output impedance.
This last two paragraph answers the question I kindly asked twice from A.king21 about 6 weeks ago, see here:
https://overunity.com/17491/confirmation-of-ou-devices-and-claims/msg534887/#msg534887 

but he gave no answer. This was my question: "So what is it which insures a larger EM field from the transmitter coil when a gate driver is used?" 

There would be some more to add but this post is already too long,  I hope I answered your questions and if you do not understand something, please ask.

Gyula

[rickfriedrich]

The Fogal arrangement creates a tank that he was oscillating around 500MHz and more. In the right position with the semiconductor (transistor in his case) it effectively blocked current flow while the amplifier was running normally. Depending on how you look at it you will describe the process accordingly. It does relate to some of the things we have considered here...

Rick, Thanks for the reply, that doesn't surprise me would ESR i have come across that befor would you like to explain a little more please ?

[rickfriedrich]

If you were meaning these comments then that is what we are doing with the motors energizers and the many Don Smith magnetic resonance systems. Some of the theory is in the book. The basic idea is that if you impulse electrons electrically then they will respond with a magnetic impulse first, followed by an electric impulse after. And if you magnetically impulse electrons they will first respond with an electrical impulse followed by a magnetic impulse. This is relatively easy to do and is being done all the time. It is just a matter of realizing this and setting up a good collection system. The resonance tank system creates a lot of such spin for free, and also at high CPS. Once you get that then it is game over. Then you will laugh and say, I now see why you wrote what you did to G.

"But you are not correct in assuming that is the only thing we can do. All we have to do is spin electrons and have a means of collecting the effects. That is easy to do in different ways."
Rick, Thanks for the reply, that doesn't surprise me would ESR i have come across that befor would you like to explain a little more please ?

[a.king21]

G:  I would prefer it if you would direct your technical questions to Rick. I do not have a permanent lab at my disposal and Rick is far better placed to answer your questions. My valuable time is spent verifying what I need to move on with other experiments. If you choose to disbelieve me that is absolutely fine and i will concede that you know better.
Itsu:  I can't remember the cold electricity circuit and it is not important to me if anyone verifies it or believes it. 

[rickfriedrich]

G,
I appreciate the time you put into typing all this out. Many words do promote clear and proper communication. Less words create ambiguity.

Nice attempt of understanding what is going on. But this wouldn't explain input going to zero, because then you would have to have zero EM field as you suppose. You are not considering everything that is taking place. Or rather, everything that can take place once proper spacing/placement is achieved and other factors. As I said, (A) you can make the secondary coils decrease while the input also decreases (as you mention), (B) you can make the input increase while other coils are added, or (C) you could make the input decrease while additional outputs are added without decreasing the existing outputs. The latter can be done carefully until the input is zero or even negative. Increasing or decreasing the system resistance is not the explanation. I understand that you claim you have not experienced that and thus do not believe it. But it is not very hard to see for yourself how you can add loads that decrease the input while the loads do not decrease.

There is more going on here than your standard coupling here. And that is where people just assume it is the same sort of thing. Resonance coupling has a gain over regular magnetic coupling. The tank is a real "amplifier" and the secondaries become their own transmitters as well. Once that is understood it really opens doors for you. People assume that there is a firm coupling so that the same energy is just transferred back and forth so that everything is in balance in regards to input and output. Naturally anything contradicting that is automatically disbelieved and special proof is required for that when no special proof is expected for confirming disprove claims. One video shows Itsu doing A and or B and that is believed but if another video shows C then it is needing more proof.

As for the DSE that is easy to see that the load is doubled or replicated as Don showed. While we do not need to focus on that it still is relevant. And quarter wave length gains are not a matter of needing proof but simply a matter of using them. People can say well I disbelieve such and such and content themselves to not opening their eyes to what is in front of them. I'm not saying that is the case here, but only saying that the onus is on either claimant. No one has the monopoly on science, no matter how popular an idea is. I mean come on didn't we all used to believe that the earth was round before the flat earthers convinced us even more of that 

When the resonant impedance of the TX circuit increases from say its original 1 Ohm example value to a 3 Ohm transformed back impedance, then naturally the gate driver IC can drive less current into the same TX circuit than it could in the previous unloaded coupled circuit case. This is important to understand: more and more coupled coils will increase the series impedance of the series LC TX circuit higher and higher. 
This process manifests measurably across the TX coil and capacitor: their resonant voltage amplitude gradually decreases, say from the initial some kV to as low as some hundred volts or lower. 
In return for this, the AC current taken out from the output pin of the driver IC will decrease according to the increasing number of the satellite coils and a decreasing AC current involves a decreasing DC current draw by the driver IC from its DC supply.  This process inherently involves a decreasing input power draw by the gate driver IC of course, hence the EM field the TX coil creates around itself will also decrease gradually.