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Overunity Machines Forum



The gyroscopic electric central

Started by geptole, May 19, 2018, 03:09:18 AM

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geptole

http://www.gencodex.com/giroscopio/
(translated by google)

IDENTIFICATION CODES

1,2,3,4) flywheel
5 and 6) three-phase alternator
7,8,9) electric motor continuous voltage
10) thrust bearing
11) collector and support base for alternators
12,13,14,15,16,17,18,19,20,21,22,23) graphite brush
24) cover
25) ball bearing
26.27,28,29) bolt
30,31,32,33,34,35,36,37,38,39,40,41,42) tube of plastic that is electrical insulating
43,44,45,46,47,48,49,50,51,52,53,54) tube of copper that is electric conductor
55,56,57,58,59) imaginary axis of rotation
60,61) voltage elevator transformer
62,63) high voltage pylon
64) voltage reducer transformer
65) Graetz bridge rectifier
66) manual switch
67) starting accumulator
68,69) washer
70) resistor
71) relay contact delayed to 5 seconds excitation

------------------------------------------

By closing the switch 66, continuous electric voltage arrives at the graphite brush 19 and also to the motor 9, so the motor 9 starts to accelerate the base 11.
From the graphite brush 19 electrical voltage arrives to the copper tube 50 which connects the electrical voltage to the graphite brushes 20 and 22.
All brushes have a small spring whose purpose is to hold the brush against a copper tube, but for simplicity in the design the small springs have not been drawn.
When electric voltage is reached at the brush 20, the electric motor 7 starts to turn and then the flywheels 1 and 2 turn.
When electric voltage arrives at the brush 22, it happens that the motor 8 starts to turn and then the flywheels 3 and 4 turn.
All four flywheels 1 2 3 4 are of heavy solid steel.

Because of the gyroscopic effect, the imaginary rotary axes 55 and 56 have the tendency to maintain the same angle in the space around them, it follows that if the base 11 is rotating, the rotors of the alternators 5 and 6 are forced to turn. producing electricity which is sent to six copper tubes which are 43,44,45,46,47,48.

The three copper tubes 43,44,45 feed the voltage transformer 60, instead the three copper tubes 46,47,48 feed the voltage transformer 61.
The secondary circuit of the elevator transformers is connected to the high voltage cables, this is normal as in all power stations.
It is already known that any electric motor in continuous needs at least 2 wires, in one wire the electric current and the other is considered by convention the return of the current, the copper tube 49 collects the return electric current and then complete the electrical circuit.
Since the mass of the base 11 is noticeable with respect to the rated power of the microscopic motor 9, it is necessary to complicate the electric circuit so as to ensure that the starting electric current is limited; to do this there is the electric resistance limiter 70 and the delayed relay 71 normally open.
By closing the circuit by means of the switch 66, the delayed relay does not close immediately so the electric current is forced to pass through the electric resistance limiter, but after about 5 seconds, the delayed relay 71 short-circuits the electrical resistance 70 and then arrives on the motor 9 full tension.
By mistake there could be an obstacle that blocks the base 11 and therefore the motor 9 so unfortunately the relay gives the consent even when it should not, in this case an automatic thermal protection switch must intervene to avoid burning the motor winding 9.
Instead of the delayed relay, a revolution counter could be placed; the tachometer is safer but it also costs more, or instead of the delayed relay you could put a watt regulator that excludes the resistance only if the number of revolutions exceeds a certain predetermined value.
There are numerous methods to soften the start of an electric motor, but there is no willingness to explain them all.

The imaginary rotational axes 57 and 58 rotate in the opposite direction to the rotation axis 59, it has not importance which direction the motor 9 rotates, but if by looking at the top we decide that the motor 9 must rotate clockwise, the rotors of the two alternators will turn counterclockwise.

As a consequence both the alternator stators will suffer an anti-clockwise mechanical twist which will be released on the base 11.
It will be unloaded on the base 11 because the alternator stators are bolted onto the base 11 by means of the bolts 72,73,74,75.
It is very important to take into account the mechanical twists acting on the base 11 and the direction of rotation of those twists.
The resulting vector of both counterclockwise twists will result in a total central mechanical twist whose rotation center is precisely the rotation axis of the motor 9, so the motor 9 is privileged by those twists and there is no contrast as is normal to think .
The motor 9 is pushed by 67 and is also driven by the mechanical twists generated by the stators of the two alternators.
The two mechanical twists are in one sense and by reaction the whole base is accelerated in the opposite direction, this is the basis of the principle of classical physics according to which every action corresponds to an equal and opposite reaction.
The law of action and reaction favors the engine 9.
This means that after the start-up period, the engine 9 could also function as an electric generator.
The flywheels 1,2,3,4 must perform many rpm per minute, minimum 2800 rpm if it is possible to do 28 thousand rpm is better, without exaggerating too much otherwise the steel of the flywheels will deform due to centrifugal force.

instead the engine 9 can turn slowly, 60 rpm per minute are sufficient but even 30 rpm are sufficient.

The flywheels 1,2,3,4 are the most important components, all the other components are of secondary importance, if those 4 flywheels are still, even all the other things stop.
The 1,2,7 components represent the first gyroscope, and the 3,4,8 components represent the second gyroscope.


geptole

this is an animation seen from above, but in this forum GIF animation does not work. >:(

It should be noted that the rotation axes of the gyroscopes maintain their angulation in space, this causes a relative velocity difference between the rotor of the alternator and its stator, hence the production of electricity.

At the same time, the motor 9 is idling, enough to counter the friction of the bearings.

stiplanet

hello thank you for sharing, I would like to know if it is a simulation or there is a prototype that works already, what is the power that can deliver this power plant. best regard .

magneat


Hi there!

why did the author decide that the load on the generator shaft 6 (5) is not affected by the motor shaft 9, which rotates the platform 11?
mentally connect the hard shaft of the generator 5 (6) to the generator 5 (6), which corresponds to the load -> to infinity.
provided that the axes of gyroscopes 1-2 (3-4) will retain their direction.
the engine 9 will stop, it will not be able to rotate the platform 11.
the number of generators (gyroscopes) here plays no role - you can put 1,2,3,4 ...
if anyone does not understand, I will explain differently.
leave 1 generator, for example generator 6.
The axis of the generator must be fixed relative to the outer space.
this condition is satisfied by the use of a gyroscope 3-4.
can be done differently - using guides in the form of the letter H (as in the plotter)
fix the axis of the generator on the linear bearing of the X-axis (the crossbar of the letter H).
The 2 Y-axis guides are fixed in the outer space.
A device similar to the author's device was obtained, only without gyroscopes.
Now when the platform rotates by the engine 9, the body of the generator 6 will move in space, and its axis will be
To maintain an unchanged position with respect to the external space (at a load of ~ 0).
but it is worthwhile to fix the axis of the generator 6 relative to its housing, the engine 9 will stop, unable to rotate the platform 11.
any load on the generator 6 will affect the engine 9.
p.s. would be glad to be not right, indicate my mistakes.


respectfully

geptole

You're right if the number of merry-go-rounds is 1, you're not right if the number of merry-go-rounds is greater than 1.
.
Consider the terrain is the piece 11