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TopRuslan

Started by r2fpl, March 21, 2023, 11:47:39 AM

Previous topic - Next topic

0 Members and 3 Guests are viewing this topic.

pix

Quote from: Dog-One on May 06, 2023, 09:07:59 AM
You are asking that question because you have not thought this
through enough.  You need two traveling waves moving in opposite
directions to get one set of standing waves.  You need two sets of
standing waves in order to pit one against the other, with your
load in between.

So how does energy from the environment enter into this system?

What did I say about this being a transmission line?  One leg of the
transmission line is the air around the coil.  This device has setup
the conditions where the environment must provide what is missing
in order to satisfy the physical/electrical restrictions within the coil.
It is most definitely an open system.  A normal transmission line is
a closed system and wave propagation is fixed based on the segment
L/C ratio.  With this device, wave propagation speed is still a fixed
parameter unless you externally alter the capacitance between the
coil and the air around it.  This is what I suspect happens naturally--
charge is pulled into the air, to charge that coil/air capacitor and keep
the system in balance electrically.  This external charge actually alters
the capacitance dynamically while the device runs.
Tesla coil is doing exactly what you are describing.
Top terminal alters it's  capacitance.
One standing wave forms within secondary, which is electrically 1/4 of wavelength, so you have clear 2 points: node and antinode.
Maybe enviroment is providing something "extra", but I don't know by what process.
But as I said before, it is like electromagnetic compressor that is adding up pockets of small signal into a large one, that is in the useable form. Energy of that system rises expotentially versus linear energy feed. "Per-se" there is energy positive imbalance.
Many small guys climb on each other to form a big guy.
The same principle applies to air conditioners and a heat pumps. A large volume of low temperature ambient air is converted to smaller volume of high temperature air. Basically it is an OU device with COP 3-5. And nobody is questioning this fact.
Why people do not accept it's electromagnetic example?


Cheers,
Pix


AlienGrey

You don't need a Yesla coil to feed a grenade coil, you can see that from the Don Smith device.
and it don't have run at 2mhz but the spark plug simulation needs to be realy fast in the nsecond
regon.

Do you refer to all that radiation and charged particals that comes from the sun by any chance 8) 8)

Sil

Dog-One

Quote from: pix on May 06, 2023, 09:41:28 AM
Maybe enviroment is providing something "extra", but I don't know by what process.

If you have a capacitor with a value of 30uF and this capacitor is being
slightly charged from some unknown source, will it still behave as a 30uF
capacitor?

I would say no.  It will behave as something less than a 30uF capacitor
during charge, determined by how much external charge it is receiving.
The good news is, when you go to discharge it, it will behave like a
capacitor greater than 30uF.  So magically we are now able to charge a
capacitor faster than we discharge it, given the same resistance. That
directly translates to power my friend, coming from an unknown source.
That unknown source is the environment, the air around the coil, dynamically
altering the characteristics of this transmission line.

pix

Quote from: AlienGrey on May 06, 2023, 10:52:58 AM
You don't need a Yesla coil to feed a grenade coil, you can see that from the Don Smith device.
and it don't have run at 2mhz but the spark plug simulation needs to be realy fast in the nsecond
regon.

Do you refer to all that radiation and charged particals that comes from the sun by any chance 8) 8)

Sil
Nope.
Any "slow wave" resonator will do. The lower frequency the better.  I gues "grenade" coil is another way to physically shorten the resonator.

pix

Quote from: Dog-One on May 06, 2023, 10:56:32 AM
If you have a capacitor with a value of 30uF and this capacitor is being
slightly charged from some unknown source, will it still behave as a 30uF
capacitor?

I would say no.  It will behave as something less than a 30uF capacitor
during charge, determined by how much external charge it is receiving.
The good news is, when you go to discharge it, it will behave like a
capacitor greater than 30uF.  So magically we are now able to charge a
capacitor faster than we discharge it, given the same resistance. That
directly translates to power my friend, coming from an unknown source.
That unknown source is the environment, the air around the coil, dynamically
altering the characteristics of this transmission line.
With grounded Tesla secondary, every "push" from primary amplitude of standing wave rises, and more and more electrons are attracted and repelled from the ground. "Electrical mass" is rising . Energy is expotentially rising, feed from primary is constant.
Positive energy imbalance is rising. And it is  an"open" circuit to the enviroment.
No need to search for exotic energy sources.
In my opinion that's the process.


Cheers,
Pix