Free energy from gravitation using Newtonian Physic

[pequaide]

Homer; The released sphere (or cart) would travel tangent to the circumference of the spinning cylinder (or wheel) but there is a string attached to the sphere and it is wrapped forward of the sphere?s release point (or wheel's release point) along the circumference of the cylinder (or wheel). This string prevents the tangent course of travel for the sphere.

Draw a circle with a tangent line. If you draw a diagram with equal distances marked off along the circumference of the moving circle, these marks would represent the motion of the point of release. Equal distances marked off along the tangent line would represent the new position of the sphere after equal units of time from the release. This shows how the point of release is moving away from the tangent line of travel of the sphere and the distance between the sphere and the point of release becomes larger and larger.

The point of attachment of the string to the cylinder moves away from the sphere?s tangent line of travel as well; the string creates a second tangent line between the point of contact of the string with the cylinder and the sphere. The string connected to the sphere remains tangent, as it unwraps, until the point of attachment of the string with the cylinder is reached. Since the distance from the sphere, on its tangent line, to the point of contact of the string with the cylinder is greater than the corresponding length of the string; the string will pull the sphere off the tangent line. The sphere will obtain a new direction.

A portion of the force in the string is in the same direction as the line of travel of the sphere, this force will accelerate the sphere. The sphere will obtain a new velocity, as will the cylinder.  The remaining forces in the string are balanced centripetal and centrifugal forces.

With the new velocity of the component parts and new angles, the force applied in the direction of the sphere?s travel will also change.  The sphere will obtain a new direction a new velocity and a new force, this new direction new velocity and new force will happen for every subdivision of time.   

The force in the string is in the opposite direction of the line of travel (rotation) of the mass in the cylinder, this force will slow the rotation of the cylinder. The force in the string is equal in both directions (Newton?s Third Law of Motion).

You get a complex arrangement of angles and forces but the fact that the cylinder stops has been proven by experiments.

According to Newton?s Second Law of Motion (F = ma) the equal forces applied to the cylinder and the spheres will cause equal momentum changes on both ends of the string. The momentum change of the cylinder will equal the momentum change in the spheres.

Some scenarios are thought experiments, many are real experiments that have been video taped, strobe light photographed, and photo gate timed. Some experiments are hand held some are in spinning mechanical arms and some were conducted on a frictionless plane. All experimental data shows that Newtonian physics is correct, and that the cylinder and spheres phenomenon (the transfer of momentum from a large mass to a smaller mass) is a means of energy production.

[Homer S.]

Homer; The released sphere (or cart) would travel tangent to the circumference of the spinning cylinder (or wheel) but there is a string attached to the sphere and it is wrapped forward of the sphere?s release point (or wheel's release point) along the circumference of the cylinder (or wheel). This string prevents the tangent course of travel for the sphere.

Pequaide, I have another question: is the string wrapped in the same direction as the rotation direction of the cylinder or in opposite direction?
However, regardless the winding direction of the string, the string cannot apply a force to the sphere (mass) as long as the string will be unwrapped by the cylinder and tangential moving sphere because string and sphere have the same value of velocity.

I hope you agree so far?

Regards,
Homer

[pequaide]

In the mechanical arm model the spheres are moving 1.29 m/sec; if not for the force in the string restraining the spheres after release they would move tangent and be over 1 meter away from the cylinder in less than a second. This forced restraint cost the cylinder all of its motion. Yes; there is force in the string. They are moving at the same speed but they are not moving in the same direction, the string must force the sphere back into a circular path.   

[Homer S.]

Good day pequaide,

It's a pity that you didn't answer my question about the wrapping direction of the string in relation to the rotation direction of the cylinder. Hence I guess wrapping and rotation direction are equal!?

I have attached a sketch which shows stills of motion of the released spheres how I would expect it. However, gravitation forces are not taken into account at all.

Here my remarks to the single points:

1. Fixed spheres rotating around the circumference of the cylinder at velocity value Vu.

2. Spheres are released and moving away in tangential direction. The connected string is unwrapping from the cylinder. The velocity of cylinder's circumference, spheres and connected strings is identical and unaltered at velocity value Vu.

3. Strings are still unwrapping from the cylinder. Same conditions as stated under No. 2.

4. Unwrapping of the strings is finished. Tangential movement of the spheres is abrupt stopped by the strings. The translation energy of the spheres as well as a accordant part of the rotation energy of the cylinder was changed into stretch energie (elastic force) and at last into heat.
That means the formely translation energy of the spheres is no more available.

5. The remaining rotation energy of the cylinder (if there is any left) will be partly transferred to the spheres and because of the tight strings the spheres begin to rotate around the center of mass of cylinder and spheres.
The remaining rotation energy is much smaller as at the begin with fixed spheres at the circumference of the cylinder. Thus V1u will be much smaller than Vu, depending on the mass of cylinder, spheres and string length.

Sorry, but how I understand it you have built more or less a break instead of a energy device. 

Regards,
Homer

[pequaide]

Well Homer ?how you would expect it? is wrong.

The tangent direction is immediately altered by immediate force in the string; it doesn?t wait to jerk the sphere back it happens immediately.


The string goes forward of the sphere,