Free energy from gravitation using Newtonian Physic

[Mr.Entropy]

When a kid leans back on a swing, they go higher and higher. They're increasing their acceleration.
And if a weight attached to the pendulum is doing the same thing, why would it be different ?

Kids on swings would seem to be very clever...  It's not about leaning back and forth.

They lean away from the swing's pivot point near the top of their swing, and pull themselves back up towards the pivot near the bottom.  When they pull back up, they work against more gravity and centrifugal force than are acting on them when they lean away, because they are close to the bottommost, fastest part of their swing.  The extra work they do there adds kinetic energy to their swinging motion.

The interesting thing is that kids don't know this, or need to know it.  If you're squirming around on a swing, there's really nowhere that any work you do can go, except into your swinging motion, so all you have to do is find something that's hard to do, and it will make you swing faster.  If kids practice swinging for a while, their bodies learn this all by themselves.  They learn to lean up, raise their feet, and bend the chains to raise their bottoms, because they can tell when they're working hard and they intuitively come to understand that work -- any kind of work -- produces speed.

In other words, kids on swings understand the conservation of energy :-)

Cheers,

Mr. Entropy

[pequaide]

Roy; .2038 meters is not twice the original height it is quadruple the original height of .051m. So: half the mass four times as high is double the original energy.

[hansvonlieven]

Sorry Roy,

even if they sit on a rigid bar welded to the arms it will still work, a little uncomfortable perhaps, but it will still work.

Hans von Lieven

[Evil Roy Slade]

Roy; .2038 meters is not twice the original height it is quadruple the original height of .051m. So: half the mass four times as high is double the original energy.

Ah yes, I misread your original post. But how did you use d = 1/2v?/a to calculate the finish height of .2038 instead of .102?

Hans: I guess we have to agree to disagree until I get some kid to try it!

[pequaide]

Roy: two pendulum bobs that swing down from .051 m have a velocity of 1 m/sec. If these two bobs are on the opposites sides (and moving the same direction around the circle) of a horizontal circle they can be used as a cylinder and spheres apparatus. As the spheres swing out on the end of tethers all the motion is transferred to a small portion of the mass.

d = 1/2v?/a; if velocity is 1 m/sec rise (d) is .051 m, if velocity is 2 m/sec rise is .2038 m. (a) is acceleration 9.81 m/sec  d = 1/2v?/a   or   Ã¢Ë†Å¡2ad = v

If by any means you can transfer the momentum of a massive object to a smaller portion of itself you have made energy. The cylinder and spheres is one means and the rolling ring is probably another.