new magnetic motor goes 2000 rpm without load 1000 rpm with load

[JamesThomas]

Ergo:

I don't hope Magnacoaster belong in that category.

Nor do I. He seems very sincere, and has put a lot of time and work into his project; which is what makes it so puzzling as to why the extra little addition you have stated above is not done immediately upon thinking one might have an OU device. He certainly has the skill and means.

Perhaps it is a cognitive dissonance, were we will jump through every hoop but the simple one that will prove our machine a OU success or not. We would rather use up as much time as possible hoping it is, than close the loop and find it is not.

I hope Magnacoaster, the greatest success.

j

[Ergo]

I hope Magnacoaster, the greatest success.
j

Me to, but I encourage Magnacoaster to make the self runner we all want.

[dani1]

In my opinion MCs setup is just like the electromagnetic wankel of the Tom Bearden website at http://www.cheniere.org/techpapers/jap/fig8a.jpg with an attached generator.
Am i right?

[Honk]

Who knows?
It's almost impossible to tell from the few pictures on the net.

[Honk]

input voltage to motor
12 vdc @ 1.5 amps

output from motor circuit
200 vac @ 2.5 amps

Hi Magnacoaster.

Have you performed any oscilloscope measurements of the 200VAC output?
How does the waveform look? I'd like to know the shape, duration, rise time and voltage level of the output?
Please post a picture if possible.

I don't get the thing about putting back the output to the battery? This sounds very strange to me.
In a motor/generator design there should be an input to the system and an output of the generated voltage.
Why do you try to direct the output back into the battery?? This makes no sense.
Wouldn't it be easier to just rectify the output and then dump it into a resistor to calculate the efficiency.
When rectifying you should use a large capacitor to smooth the output to get accurate voltage readings.
Input       = volt x current
Output     = volt x volt / resistor value
Efficiency = Output / Input

I belive this could clear things up regarding the gain of your design! And it's easy for people to understand.
If your measurements show overunity, then please make a self runner as suggested to finally prove your design.
All you need is an AC-DC converter to fit the 200VAC output voltage to 12VDC input voltage. I can help you with this.