Chas Campbell free power motor

[hartiberlin]

Surely one has to calculate into the wheel
the Angular momentum conservation law
as the wheel is tapped in my calculation every 30 degrees
out of a 60 degree rotation with 2.16 more torque at the right side.

This stores intertia flywheel energy into the wheel which keeps
lifting the balls on the left side...

[rMuD]

On a side note, that no matter what you do here.. it's going to come out to 1:1  this literally follows the math of a Pully with loss because of the gravity feed..  Second FYI the only reason I can see this functioning is in the current design, if a ball falls out on the upward motion will there be a positive gravity effect.

4x the size..  down to 28.8% (estimation should be 30 degrees I think) with no slope for the return or feeder so it's either average of  90% of the time there will be a ball on the down stroke.. meaning it will go backwards 10% of the time

[Humbugger]

I'm saying (surprise surprise) that it cant possibly work at a ratio of 3.8763 or more because 30 degrees on the outer wheel is then equal to 1 unit of height; same as the diameter of the inside ring of ball holders.  There is no possible slope left for the linear ramps.  Only one ball then could ever be on the right side now.  A new ball cannot enter the outer wheel on top right until after the lower ball had left at the ratio of 3.8763 to 1.

Humbugger

EDIT:  Okay...rMuD to the rescue again!  You see his two radials in blue at 28 degrees apart intersecting his 4" circle, well what I'm saying is that if they were 30 degrees, they would hit a 1" height intersect if the circle were 3.8763", 

I find it much easier to visualize, rMuD, if the wheel is rotated 15 degrees so that you can easily see these relationships, similar to how you have drawn your 28 degree lines.

Humbugger

[hartiberlin]

Okay, if we mathematically say the wheel is accelerated by a 2.16
torque advantage for 30 degrees out of 60 degrees,
then we have a duty cycle of input power of 50on :50off .
so for one complete rotation we have got  only half the applied torque.

That means we can just half the torque on the right side.

So instead of 7.8 units we will have then 3.9 units,
which is still more than the 3.6 units we have on the
left side.

So indeed this wheel will spin up and accelerate
and produce mechanical energy from gravity.

[Joh70]

Ok, changed my mind: This system will not work.

Each ball going down must go a longer way up on the other side. Inner circle draws a longer way for the same height compared to the way down on the outer circle. And it helps nothing to change the ratio of the diameters. The ways to travel came directly out of the ratio of diameters and are in proportion against the resulting forces. For example: As wider the outer circle gets as less a ball on the inner circle gets lifted by a ball on the outer circle on its way down.

A demo-unit would behaive as follows: Either you ran out of balls on the upper level or they get into a jam/dam up on the lower level. Imagine the timing - thats a proplem here! The best what you can get, is a balanced system with the lowest losses at an optimum configuration, when moved by external force.

Forget it. It is a nice, simple idea - but too simple. This setup should be easily simulated with a good Mechanics-Workbench-Software (i have none, did it on paper).