Chas Campbell free power motor

[hartiberlin]

I can't seem to figure out how to upload an autocad.dwg file or change it to a bitmap...my bad.
Humbugger

Do you have Autocad for WIndows ?
Then press ALT and PRINT together,
then the bitmap is in the windows cache.
Then start a graphics program like Irfanview.
Say PASTE command from the edit menu and save
as JPEG.

Please let me know, where my calculation is wrong.
I still see a 3.9 to 3.6 advantage for running...

[Humbugger]

Okay, thank you... ...I now have a saved image.  How the hell to I upload it into a post? 

Humbugger's total inexperience at posting graphic images is fully exposed to all...

[rMuD]

15 degrees offset..  no balls at 4x  2 at 3x and 2x   

[hartiberlin]

15 degrees offset..  no balls at 4x  2 at 3x and 2x   

What do you mean by this ?
Can you explain it a bit more please ?

What about the 3.9 to 3.6 advantage of running ?

@Hum,
just put the path to your picture into the attachment line
and then press the Post button.

[Humbugger]

As the ratio of the two diameters is increased from two to three, what rMud says is true but even worse.  There are only two balls on the right side for a very few degrees of rotation, not 1.5 balls average, but much less.    The picture shows that brief moment.

At all other times, i.e. most of the time, only one ball can be on the right side, as the lower ball has been delivered to the lower return ramp and yet there is significant rotation that must take place before a new ball socket comes into position to receive the next ball. 

Note that our feed and return ramps are shown level but in reality they have to be sloping. The slopes further reduce the short rotation angle (to near zero or below) when there are two balls on the 3" rim.

At a ratio of 3.8763 to 1, the linear supply and return ramps reach the theoretical limit of having no possible slope left to deliver balls left and right, since the linear vertical chord distance between positions on.the outer wheel is exactly the same as the inner wheel diameter.  At this ratio, the maximum number of balls on the right side at any given moment becomes one.  For anything larger, there are times when no ball at all is on the right side.