Chas Campbell free power motor

[hartiberlin]

In other words, once again, when the cup with the ball in it gets to the exit ramp and moves out of the big wheel's cup and onto the ramp, at that very moment, no matter there may be 87 balls waiting and ready to get into the next available entry cup from the top ramp, the receiving cup isstill a whole foot away from being in position to receive a ball.  

So what about having more balls waiting on the lower ramp, than are on the upper ramp ?
Then you could easily stop the wheel and wait until the next ball has gone 4 x distance out and
still have a next ball at the lower entrance to go upwards !

Not so complicated right ?
So Humbuger,
where are still your torque calculations ?

[Humbugger]

Shrugged...I have added your name and Hans' to my deathbed request above.  Thank you for helping an "arrogant" old tired engineer get some well-deserved sleep.  It was really bugging me.

Thanks for thinking hard

Humbugger

[hartiberlin]

So Humbugger,
what about this ?
10 balls in play game,
enough waiting to get picked up.
If the upper left ball at 11 o?clock is on the upper ramp,
wheel is stopped shortly, so the ball can roll out and get the next red
ball to propell the wheel ?
So who is showing me the error in my torque calculation
of the 3.9 to 3.6 advantage ?

Thanks.

[Humbugger]

In other words, once again, when the cup with the ball in it gets to the exit ramp and moves out of the big wheel's cup and onto the ramp, at that very moment, no matter there may be 87 balls waiting and ready to get into the next available entry cup from the top ramp, the receiving cup isstill a whole foot away from being in position to receive a ball.  

So what about having more balls waiting on the lower ramp, than are on the upper ramp ?
Then you could easily stop the wheel and wait until the next ball has gone 4 x distance out and
still have a next ball at the lower entrance to go upwards !

Not so complicated right ?
So Humbuger,
where are still your torque calculations ?

Either you are really purposely avoiding this issue or I have overestimated your intelligence.  You are entirely capable of doing the math.  I just wanted you to do it with a correct understanding of how many balls are on the right side of the wheel.  I have worked far too hard at communicating an extremely clear and obviously true fact to be fooled into thinking I need to do more. 

I am convinced; you may choose to go on with the pretense that your calculations based on having a 4:1 wheel setup and two balls on the right are valid.  If we cannot agree on the number of balls on the wheel, there is no point in adding up the torques.  I'm tired of this particular game.

You tell me how many balls are on the outer wheel averaged over 30 degrees at a 4:1 ratio.  If the number agrees with mine [hint: it's less than unity], I'll do the calculation.  If not, we end this charade.

Humbugger

[shruggedatlas]

So Humbugger,
what about this ?
10 balls in play game,
enough waiting to get picked up.
If the upper left ball at 11 o?clock is on the upper ramp,
wheel is stopped shortly, so the ball can roll out and get the next red
ball to propell the wheel ?
So who is showing me the error in my torque calculation
of the 3.9 to 3.6 advantage ?

Thanks.

There is something wrong in your chart, I think.  It is hard to explain without pointing and showing - alas the Interent - but I will do my best.  You notice how the receptacles in the outer wheel are not evenly spaced?  I think you simply moved the receptacles in the outer wheel to where they would line up with the ramps, without accounting for where they actually need to be for the system to work.  You will notice that if you try to trace a straight line, you cannot get from the ball in the outside wheel receptacle to the corresponding ball in the inner wheel.