Chas Campbell free power motor

[hartiberlin]

Yes, Humbugger, you are wrong.
If you stop the wheel, when the next ball has come up at the left side,
it has enough time to run out to 4x.
Then always one ball is at the right side and it can then start the wheel again.

As you did not do any torque calculation yet and my 3.9 to 3.6 advantage still stands,
nobody has shown the error yet.

[hartiberlin]

hi all , first of all please excuse my very bad edit of some one elses pic, but would this work ?.

Can we please have a torque calculation for this too ?
Maybe a few less yellow balls needs to be brought up at the
left side ?
With what gear ratio is the transport chain coupled to the wheel ?
Thanks.

[tropes]

Yes, Humbugger, you are wrong.
If you stop the wheel, when the next ball has come up at the left side,
it has enough time to run out to 4x.
Then always one ball is at the right side and it can then start the wheel again.

As you did not do any torque calculation yet and my 3.9 to 3.6 advantage still stands,
nobody has shown the error yet.

And to prove your point Stefan, you should do the next logical step; Build the Wheel and show us all how right you are!
Peter

[Humbugger]

Stefan...

Forget all about the speed or stopping the wheel to wait for a ball.  I already allowed for light-speed ball travel on the ramps. 

There are physical ball receptacles spaced 30 degrees apart on the wheel.  Whenever the vertical straight-line (chord) linear distance betwen those fixed physical receptacles is larger than the diameter of the center smaller lifting wheel (i.e. above 3.8xxx:1 ratio)...

There will be some period in which there is no ball on the outer wheel!  This is because the lower ball receptacle has dumped its ball onto the lower ramp, but the next receptacle available for picking up a new ball (that we can assume is there waiting)...that empty receptacle has not yet arrived in place to receive a new ball from the upper feed ramp.  So, for a moment, no balls on the outer weel.

As you make the ratio larger, the portion of time there is a ball on the outer wheel gets smaller.  This is because the ramp feed and takeup positions can never be farther apart than the diameter of the center wheel or there would be no slope to induce travel.  Yet the distance between the receptacle cups iof the outer wheel continues to get larger and larger, meaning more empty time.

ONLY CUPS WHICH ARE BELOW THE FEEDING RAMP AND ABOVE THE DUMPING OFF RAMP CAN HAVE A BALL IN THEM.  IF THE DISTANCE BEWEEN CUPS IS BIGGER THAN THE DISTANCE BETWEEN THE RAMPS, THERE WILL BE TIMES OF NO BALLS.

This is not wrong.

Get it?  There isn't any point in doing a torque calculation if we cannot agree on the number of balls that will be on the right side, now, is there?

Humbugger

[Humbugger]

Yes, Humbugger, you are wrong.
If you stop the wheel, when the next ball has come up at the left side,
it has enough time to run out to 4x.
Then always one ball is at the right side and it can then start the wheel again.

As you did not do any torque calculation yet and my 3.9 to 3.6 advantage still stands,
nobody has shown the error yet.

And to prove your point Stefan, you should do the next logical step; Build the Wheel and show us all how right you are!
Peter

Peter,

Please don't leap in and make comments to piss off Stefan right now.  I'm trying very hard to get him to see the point i am making.  Snippy remarks will not help him grasp it.

Humbugger