The Lee-Tseung Lead Out Theory

[Koen1]

yeah thanks for that excercise of the laughing muscles Kul_ash

I still think the part where he describes cheating on his IQ test is a hoot.
So he couldn't understand the text instructions when IBM allegedly gave him an IQ test,
which is why he never really completed the test and IBM concluded he was too dumb.
Instead of brushing up on his English so he could read the text and complete the
IQ test properly, he goes and studies various IQ tests so that he knows all the
standard type questions and answers and then he cheats the IQ test, obtaining
an impossible score, which is obvious and was probably pointed out by the nameless "agency".

What does that say about Tseung?
It at least shows how he either does not understand the use and intention of an IQ test,
or he does but decides cheating to get an impossibly high score is better than honestly
doing the test and getting a real score.
That's the type of person we're dealing with: a guy who cheats on an IQ test, defeating its purpose.
A guy who receives money fom his son every month for food and refers to that as financial backing of his work.
A guy who was called  an "imposter or uneducated scientist not knowing the fundamental Law of Conservation of Energy" by
"peers", with whom I think he means actual scientists (and who, by the same statement, clearly do not see him as a "peer"),
and was called a "stupid old man working on impossible perpetual motion machines" by the Hong Kong Government, and still
maintains his proofless claims out of pure stubborn self-centeredness. Or "supreme self-confidence" as he calls it.
(And I haven't even asked why exactly he needed to do an IQ test in the first place; did he make such a dumb impression?)

[Top Gun]

More on the experiment related to Pendulum12.jpg


Let us do a more exact analysis on the vertical work or the potential energy gained by the weight of 60 units and the external work done by the constant force F as illustrated in Pendulum12.jpg.  I am using Pendulum14.jpg to help in the illustration.

Let us assume that
(1)   The initial length of string from the pulley to the initial position is M1 and can be adjusted to exactly 2 meters.
(2)   The horizontal distance between the initial position to the pulley is M2 + DX as shown.
(3)   If the string is non-stretchable, the constant force F would have dropped a distance = M1 ? M2.  This distance is slightly more than dX
(4)   The length of the pendulum string is L = 1 meter
(5)   Pythagoras theorem tells us that M1*M1 = dH* dH + (dX+M2)*(dX+M2)
(6)   The Mass of the bob = 60 Kg
(7)   The acceleration due to gravity = 9.8m/s/s
(8 )   The constant force F = 1/6 that of the weight = 1/6 Mg
(9)    The final angle is given by tan(a) = F/Mg = 1/6, a = 9.46 degrees

Using the Excel Spreadsheet program, we can determine that
(1)   The vertical displacement of the bob = dH = L(1-cos9a))
= 0.013599 meters
(2)   The horizontal displacement of the bob = dX = Lsin(a)
= 0.164359 meters
(3)   (M2+dX) = sqrt((M1*M1) ? (dH*dH)) = 1.99954 meters
(4)   M2 = 1.835595 meters
(5)   M1-M2 = 0.164405 meters

Thus the potential energy (mgh) gained by the 60 unit bob
= 60*9.8*0.013599 = 7.99645 joules

The work done by the constant force F of 10 units
= 10*9.8*(M1-M2) = 10*9.8*0.164405 = 16.11171 joules

This more exact analysis still shows that the work done or energy supplied by the constant force F in pendulum12.jpg is different from the potential energy gained by the 60 kg weight.

This means that we cannot close our eyes and apply the Law of Conservation of Energy.  We must do a detailed force, displacement, work and energy analysis.

Pendulum12.jpg can be verified by experiment.

Can any one find any errors in the mathematics???

[Kul_ash]

More on the experiment related to Pendulum12.jpg


Let us do a more exact analysis on the vertical work or the potential energy gained by the weight of 60 units and the external work done by the constant force F as illustrated in Pendulum12.jpg.  I am using Pendulum14.jpg to help in the illustration.

Let us assume that
(1)   The initial length of string from the pulley to the initial position is M1 and can be adjusted to exactly 2 meters.
(2)   The horizontal distance between the initial position to the pulley is M2 + DX as shown.
(3)   If the string is non-stretchable, the constant force F would have dropped a distance = M1 ? M2.  This distance is slightly more than dX
(4)   The length of the pendulum string is L = 1 meter
(5)   Pythagoras theorem tells us that M1*M1 = dH* dH + (dX+M2)*(dX+M2)
(6)   The Mass of the bob = 60 Kg
(7)   The acceleration due to gravity = 9.8m/s/s
(8 )   The constant force F = 1/6 that of the weight = 1/6 Mg
(9)    The final angle is given by tan(a) = F/Mg = 1/6 = 10.46 degrees

Using the Excel Spreadsheet program, we can determine that
(1)   The vertical displacement of the bob = dH = L(1-cos9a))
= 0.013599 meters
(2)   The horizontal displacement of the bob = dX = Lsin(a)
= 0.164359 meters
(3)   (M2+dX) = sqrt((M1*M1) ? (dH*dH)) = 1.99954 meters
(4)   M2 = 1.835595 meters
(5)   M1-M2 = 0.164405 meters

Thus the potential energy (mgh) gained by the 60 unit bob
= 60*9.8*0.013599 = 7.99645 joules

The work done by the constant force F of 10 units
= 10*9.8*(M1-M2) = 10*9.8*0.164405 = 16.11171 joules

This more exact analysis still shows that the work done or energy supplied by the constant force F in pendulum12.jpg is different from the potential energy gained by the 60 kg weight.

This means that we cannot close our eyes and apply the Law of Conservation of Energy.  We must do a detailed force, displacement, work and energy analysis.

Pendulum12.jpg can be verified by experiment.

Can any one find any errors in the mathematics???

Firt one for starter:

When you are pulling string from middle point, L is effectively altered and has become L/2 = 0.5 m. Because the final angel you are showing is not the angle between support and bob, but the angle between point of force application and support.

[Kul_ash]

More on the experiment related to Pendulum12.jpg


Let us do a more exact analysis on the vertical work or the potential energy gained by the weight of 60 units and the external work done by the constant force F as illustrated in Pendulum12.jpg.  I am using Pendulum14.jpg to help in the illustration.

Let us assume that
(1)   The initial length of string from the pulley to the initial position is M1 and can be adjusted to exactly 2 meters.
(2)   The horizontal distance between the initial position to the pulley is M2 + DX as shown.
(3)   If the string is non-stretchable, the constant force F would have dropped a distance = M1 ? M2.  This distance is slightly more than dX
(4)   The length of the pendulum string is L = 1 meter
(5)   Pythagoras theorem tells us that M1*M1 = dH* dH + (dX+M2)*(dX+M2)
(6)   The Mass of the bob = 60 Kg
(7)   The acceleration due to gravity = 9.8m/s/s
(8 )   The constant force F = 1/6 that of the weight = 1/6 Mg
(9)    The final angle is given by tan(a) = F/Mg = 1/6 = 10.46 degrees

Using the Excel Spreadsheet program, we can determine that
(1)   The vertical displacement of the bob = dH = L(1-cos9a))
= 0.013599 meters
(2)   The horizontal displacement of the bob = dX = Lsin(a)
= 0.164359 meters
(3)   (M2+dX) = sqrt((M1*M1) ? (dH*dH)) = 1.99954 meters
(4)   M2 = 1.835595 meters
(5)   M1-M2 = 0.164405 meters

Thus the potential energy (mgh) gained by the 60 unit bob
= 60*9.8*0.013599 = 7.99645 joules

The work done by the constant force F of 10 units
= 10*9.8*(M1-M2) = 10*9.8*0.164405 = 16.11171 joules

This more exact analysis still shows that the work done or energy supplied by the constant force F in pendulum12.jpg is different from the potential energy gained by the 60 kg weight.

This means that we cannot close our eyes and apply the Law of Conservation of Energy.  We must do a detailed force, displacement, work and energy analysis.

Pendulum12.jpg can be verified by experiment.

Can any one find any errors in the mathematics???

Second point:

The work done by the constant force F of 10 units
= 10*9.8*(M1-M2) = 10*9.8*0.164405 = 16.11171 joules

Wrong again. Now your force is tangential and not horizontal any more. So the force applied will split in to horizontal and vertical components. It will do work in both directions. You are applying tangential force but considering it as horizontal force.

[Top Gun]

Firt one for starter:

When you are pulling string from middle point, L is effectively altered and has become L/2 = 0.5 m. Because the final angel you are showing is not the angle between support and bob, but the angle between point of force application and support.

In Pendulum14.jpg, L is distance between the pivot and the knot. 

We are dealing with the parallelogram of forces in this experiment.