The Lee-Tseung Lead Out Theory

[jeffc]

.....

I have been taking a wait and see attitude until this point, considering that Lawrence has repeatedly stated direct involvement with the university, which implies they believe Lead Out has some sort of scientific basis.  If they really do deny even knowing about this, then we are all wasting time, as it is likely the other credible parties which have been claimed to be involved are fabrications as well.

I hope this is not that case, as the optimist part of me would like to believe that there is actually something incredible going on in China with free energy.  I think if Lawrence has contacts at the university, he should help us clarify this apparent flaw in his claims.

Regards,
jeffc

Dear jeffc,

You should have asked for information earlier.  I was eager to share it - especially my picture at the Lecture Hall of Tsing Hua University.  It was an honor for me.  Almost all my friends and relatives have a hard copy.

Please see the attached file.  Hans can now ask his Chinese Lecturer friends at Tsing Hua University to confirm our visit in September-October 2006. 

Lawrence Tseung
Asking intelligent questions Lead Out valuable answers.  You can put good questions on  multiple pulses in case I overlooked them.

Hi Lawrence,

Thank you for the photo and information.  The post which I made before was in direct response to Hans statement about his attempts to verify your relationship with Tsing Hua.  Prior to his statement, I had taken for granted that your credentials with respect to the university were as you stated, and was instead rather happy to try and follow the scientific elements of this discussion.  But when Hans brought what appeared to be a valid challenge to your information, it seemed to be something which needed your help to verify. 

If you read the last part of my post, it says that "I hope this is not that case", because I am an optimistic person and I have no reason to disbelieve anything you have said.  In any case, if we are able to confirm the truth in this issue, perhaps we can get back to science! 

I will continue to read this topic with interest, and ask questions when I think it will be helpful for reaching conclusions.  Please understand that I do not want to make a personal attack on anyone in this forum.  I'm here to be a small part of progress, and thats all.

Regards,
jeffc

[Mr.Entropy]

(1)   A pendulum with no pulse force can be analyzed with the simple law of conservation of energy.  At any point in time, the sum of potential energy and kinetic energy are equal.

  mgh + 1/2 * m *v *v = constant

(2)   When a pulse force is applied, how should the analysis be done?  Can we apply the Law of parallelogram of forces?  Will this pulse force supply energy to the system?  Will the tension of the string contribute to the resulting forces and the resulting energy?

You asked someone else, but I'll answer, anyway.

If you apply a pulse force F (vector) to the pendulum bob while it moves through a displacement D (vector), you do work equal to F dot D, and you should find then find that the total energy in the pendulum has changed by exactly that amount.  If you find that the new total energy exceeds to old total energy by more than that, then congratulations -- you have an overunity device. Note that this does not have anything to do with the tension on the string.

For a pulse force, F is typically very large, and D is typically very small, and this makes it very difficult to measure F dot D directly.  Instead, what you want to do is charge some small resevoir of potential energy, like a spring or a capacitor (but not a battery) or a lifted weight, and expend that energy into the pendulum with a pulse.  It's easy to measure the energy in the original charge, and if you're careful about your engineering, you can ensure that that energy is transferred to the pendulum efficiently.

Measuring the total energy in the pendulum is also problematic if you're adding magnets and stuff, but one way that works is to pick some point in the pendulum's swing (like the bottom) and measure its velocity there before and after the pulse.  The difference is the amount of energy you have added to the pendulum.  Without magnets and stuff, it's easier -- just measure the difference in the height of the pendulum's swing and use mgh.

I'm going to actually propose an experiment in another post...

Cheers,

Mr. Entropy

Footnote:  In cartesian coordinates, where vectors F and D are (Fx,Fy) and (Dx,Dy), F dot D = Fx*Dx + Fy*Dy.  This is equal to length_of_F * length_of_D * cos(angle_between_F_and_D).

[ltseung888]

Itseung888:

What the heck does that have to do with anything?  The sum of potential energy and kinetic energy are always equal in any system...at least the ones we know about.  I fail to see how this applies in any way to your theory. I will re-read all of the previous posts (almost done) and I mean no disrespect to you at all. If I have read this right thus far, the "energy" you are describing could easily be described by a bouncing ball, which will also come to rest eventually.  It does not emit or give off or generate any additional energy even though it is "defying" gravity during half of it's cycles.  Maybe I am just ignorant, which is always possible. I always try to maintain an open mind on such matters.  I will research this phenomenon a little more.  Thanks for your reply.

Bill

Dear Bill and Mr. Entrophy,

Thank you for your replies.  Bill is right in comparing the pendulum with the bouncing ball in the case of NO External Pulsing Force.  There is no obvious external energy entering the system.  If there were no loss of energy, we can apply the CoE and limit the energy of the system to be just the two terms - Potential Energy (mgh) and Kinetic Energy (1/2 * M* v* v).  The sum of these two terms will be the same while the ball bounces up and down or while the pendulum is swinging.

We sometimes use the formular
mgH = mgh + 1/2m*v*v) = 1/2m*V*V
where H is the maximum Height reached and V is the highest velocity at the lowest point. h is the height at any instant. v is the velocity at the same instant.

Scientists already know how to use gravitational energy in the following case.  Water from a dam drives a turbine to generate electricity.  The potenital energy of water is used.  However, to get the water back to its original height, we need to wait for the sun to evaporate the water and the rainfall will complete the cycle. 

If we want to continuously use gravitational energy, we should look for repeatable systems.  These systems, fortuanately, are available to us easily.  The first example is the simple pendulum with no external pulse force.  We know that we can safely apply the CoE and use the forumula
mgh + 1/2 m*v*v = constant.

Now consider exactly how we supply energy to the stationary pendulum.  The pendulum is hanging in the vertical position.  We apply a horizontal Force F.  The pendulum will have both a vertical and a horizontal displacement. (The D vector mentioned by Mr. Entrophy).  Just before we stop the force F, there will be THREE forces involved in the pendulum system.

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approxiately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer. )

(3) The Tension  of the String (If there were no string, the pendulum will not swing back)


Bill rightly stated that these three forces are also vectors.  In order to determine the energy supplied by these three forces, we need to apply the vector mathematics of Force * Displacement.  (Note that it is Vector Mathematics and not the scalar multiplication.)

The relationship of the forces MUST obey the Law of Parallelogram of Forces.  That set of Laws is taught at Mechanics 101 in secondary school physics.

I shall pause here to get your response first.

Regards,

Lawrence

[shruggedatlas]

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approxiately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer. )

(3) The Tension  of the String (If there were no string, the pendulum will not swing back)

The weight of the pendulum plus the horizontal pulse force already sum up the force the object exerts on the string.  I do not know why you add (3) above.  If someone was pulling on the string, then yes, you would need to calculate that force, but seeing as the string is fixed at a point, why even include this?

[ltseung888]

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approximately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer.)

(3) The Tension of the String (If there were no string, the pendulum will not swing back)

The weight of the pendulum plus the horizontal pulse force already sum up the force the object exerts on the string.  I do not know why you add (3) above.  If someone was pulling on the string, then yes, you would need to calculate that force, but seeing as the string is fixed at a point, why even include this?

Dear shruggedatlas,

When the pendulum is at rest, there were two forces.  They were the tension of the string and the weight of the pendulum bob.  They were equal and opposite to each other.

When we applied a horizontal force on the pendulum bob, there would be three forces.  They were the tension of the string, the weight of the pendulum bob and the horizontal force.  When the Pendulum Bob moved to its new position and was momentarily at rest under the influence of these three forces, we called this system of three forces as ?at equilibrium?.  When these 3 forces were at equilibrium, we could apply the Law of Parallelogram of Forces.

This would be the situation when the first Pulse Force was applied.  In this particular situation, the vigorous application of the Physics Law of Parallelogram of Forces and energy analysis conclusively indicated that the total energy entering the system was not just the energy from the horizontal pulse force.

The Pendulum Bob moved up.  There was displacement up.  The force up was from the vertical component of the tension of the string.  This displacement up times the force up represented work done or energy exchanged in the up direction.  This is the Lead Out Energy!

For more details, see a result from google search:
http://www.antonine-education.co.uk/Physics_AS/Module_2/Topic_2/Forces%20and%20Equilibrium_files/frame.htm.

I shall pause here for responses.

Regards,

Lawrence Tseung
Three forces at equilibrium Leads Out the use of the Parallelogram of Forces. If one of the forces is Pulsed (repeated) at the right moment, resonance can result.  Useful Energy is not just the energy from the Pulse.  Useful Energy will include the Lead Out Energy.