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Overunity Machines Forum



Tesla Switch need help

Started by TheOne, September 16, 2007, 07:27:52 PM

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0 Members and 1 Guest are viewing this topic.

NerzhDishual


Hi Nul-Points,

Yes, I agree with you.
Some (fractions of) coulombs seem to appear. However,'Joules-wise', some energy
(even if not half the NRG) seems also to have vanished (as stated by mainstream science).

I was just wondering (dreaming :)) ). Should a modified JLN circuit (or another one)
be able to give the following results:

C1 = C2
VC1init = 26 volts
VC2init =  0 volts (empty)

VC1end  = 20 volts
VC2end  = 16.61 volts (instead of about 13 volts)
Or something like:
VC1end  = 19 volts
VC2end  = 17.75 volts

Or any combination that gives  VC1end^2 + VC2end^2 = VC1init^2

No NRG would be lost....
And, I that case, Kirchoff & Maxwell would owe us champagne! ;D

-----------------------------------------

I'm so weak as to think that is possible.... Why?
As stated in the D3.pdf document :




Electrons are not used up when they 'feed' a circuit (multiplication of bread?) .

The following experiment is also promissing:


Best
Nolite mittere margaritas ante porcos.

allcanadian

@NerzhDishual
It's about time somebody started getting this ;D
As I said in my last post you need an LC circuit---- both capacitance AND inductance, an electric motor is an inductance and it has another important property as well--- inertia. When the power is disconnected from an electric motor and this motor is still in series with a capacitance not only will the inductive discharge from the inductance charge the capacitance but the electric motor becomes an electric generator and will use the momentum given to it to charge the capacitance as well.
The next problem you are going to encounter on your journey is the" voltage drop ", in your light bulb circuit the amperage in the circuit is continous in every part of the circuit but the voltage is not -- power in watts is volts times amps. Now you have to deal with the voltage drop, there are ways to always produce a voltage rise in a circuit and I am sure you will find them soon enough. If you want to fast track your progress try googling --DC/DC step-up converters.
We should remember that every component you add to a circuit increases resistance and other losses therefore the best circuit will have a minimum number of resistive components.This includes diodes, transistors and resistors which will add to the voltage drop.
Knowledge without Use and Expression is a vain thing, bringing no good to its possessor, or to the race.

nul-points

@ND , AllCanadian

yes, useful work can be done during the charge transfer and AC's comments are the way

you can see in Ccts 3 & 4 that i've been able to combine both requirements by feeding the 2nd cap stack via the primary of a transformer, giving some LC in the 1st transfer and also do some useful work via the secondary in feeding forward a pulse into the load before the new charge on the 2nd cap stack itself gets switched to the load

the diodes are also able to reclaim some of the 'flyback' energy from the coils into the caps

all these different packets of energy contribute to the output - but my best COP is still only just over 0.8

i look forward to hearing whether your JLN circuit replication can reduce the losses even further ND - good luck!
"To do is to be" ---  Descartes;
"To be is to do"  ---  Jean Paul Sarte;
"Do be do be do" ---  F. Sinatra

NerzhDishual


@Nul-Points

Thanks for your 'feedbacks'. I'm very interested in your experiments. Would it be possible for you to give me more accurate precisions? IMHO, your pictures do not allow a rigorous replication.
I'm retired now. I was a computer programmer. Then I have time and I could try to reproduce your circuits.

I'm very doubtfull about the JLN circuits specifications.
For example:
In http://jlnlabs.online.fr/cnr/negosc.htm (non 'OU' experiment, BTW)
He claimed:
Bat =  12 V
Cap =  1nF
Inductance = 6mH
I= 6 mA
36 volts out pk-pk.
It did not work for me (should the 2N2222A be blamed?) .

I got, after some others tedious trials:
Bat = 12 V
Cap = 500 pifs (0.5 nano)
Inductance = 2.7mH
I= 7.2 mA
30 volts out pk-pk
That is not so bad, but I had to divide the claimed values by 2.

------------------------------------------------------------------------------
@AllCanadian

Thanks for your remarks. I guess I see what you mean...  LC circuits...

I'm not completely newbie (moronic) in basic DC electricity, Ohm's Law ,voltage divider, Th?venin, Norton and all these these sorts of fascinating guys and things  :-\

Basic AC electricity is also even not entirely over my mind yet it uses imaginary numbers and all these kind of strange & funny gobbledegook... However, I must confess that things like transistor 'Common Base Stage' or else are saturating my few left brain neurons... :P

Anyway, I cannot help thinking ('feeling' would be more accurate) that there are somethings 'wrong' (= uncompleted) in mainstream science notably about capacitors, Faraday Electrolysis, Lenz Law, Magnets Resonance, Relativity, Gravity, etc.

Consequently, I firmly 'believe' that OU (COP >1, not efficiency >1) is possible.
Am I able to 'achieve OU' is another question.

I guess that spending my time posting things in this very forum and designing some simple experiments should be better than boozing myself outside in some fishy bars where smoking is no more allowed.  ;D

Best
Nolite mittere margaritas ante porcos.

nul-points

@ND
happy to help if i can, let me know what info you want - my circuits weren't critical values, i was just experimenting to look for general trends

your rep of the JLN negistor results seem reasonable to me - always going to be differences even if you used same value components

regards
sandy
"To do is to be" ---  Descartes;
"To be is to do"  ---  Jean Paul Sarte;
"Do be do be do" ---  F. Sinatra