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Overunity Machines Forum



Single Wire Tests

Started by duff, October 31, 2007, 03:42:00 AM

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duff


hartiberlin

Hi Duff,
depends on how much current you draw on the MOSFET.
If you don?t use such a big capacitor and calculate in the voltage of the cap and the
energy in the first few mikroseconds with the On-Resistance of the
MOSFET and the wire you could see, how much current it will draw there.
You also need a very big current driver for a MOSFET to switch it
very fast as MOSFET gates could have capacitances in the several hundred pF to nF range !

Good luck.

Regards, Stefan.

P.S: Kames,I still think you are kicking away your wire from the permanent magnet.
If you turn your field on and let it on, this is just a kick to accelerate the wire away
in the first few milliseconds, until a contanst force willjust repell it...
Stefan Hartmann, Moderator of the overunity.com forum

duff


kames

Quote from: hartiberlin on November 05, 2007, 03:40:15 PM
P.S: Kames,I still think you are kicking away your wire from the permanent magnet.
If you turn your field on and let it on, this is just a kick to accelerate the wire away
in the first few milliseconds, until a contanst force willjust repell it...


Hi Stefan,

Hopefully no more gods at least in one thread.
Obviously, when the wire is idling and then starts moving there is acceleration. However, you forgot about a resistor. I did say that a resistor multiple orders exceeds impedance of the wire. What happens with the voltage on the wire only and with the current through the circuit? There is a ?kick? in voltage on the wire. There is NO KICK (except for time == 0 and current ALSO == 0, what kind of kick is it??? ) in the current if the resistor exceeds the impedance of the wire by at least 2x3.14159268 (still remember this number). If you look at the oscilloscope, the current is rising smoothly, without any picks, such as ringing. The acceleration you are talking about would be the second differential of the current, not voltage. The very (smaller part) beginning of the current curve will show a positive acceleration. The second half of the curve, while the current is still rising, will show a negative acceleration. The rest of the curve has only negative or zero acceleration. Doesn?t look like there is a space for the kick. Even so, if there were a kick, the kick is a potential energy applied at time == 0. The mechanical movement is the real energy. How does hell in the world the potential energy result in the additional mechanical movement without seeing energy spent (like a current ?kick?) from the battery?
Let?s say you are right. What/who did spend energy on the additional movement? Don?t forget, the difference is huge and nothing on the oscilloscope.

Regards,

Kames.

kames

Hi Stefan,

To my post above. Jumping a little ahead. I do have two theories for now. One of them is directly connected with what SM said.
Quote
In that book it is related that Tesla states that you can have all kinds of electrons flowing through a wire traveling in different directions relating only to their potential power source. He even said that you could have different electron flows through a single wire completely separate from each other. I tried it and he is right!

Another one was a question in my exam in the university. ?Under what conditions the electron can have a negative mass??
Note: not weight, not charge, not speed but mass. The electron mass can vary.

Both ideas are extremely speculative and that is why I am not discussing them.

Regards,

Kames.

PS: I guess I said more than I wanted for now.