Muller Dynamo

[gyulasun]

....
@all

I don't see any reason to have parallel diodes on the rectifiers.  I have researched and can't find any advantage.  I don't believe this is key to the selfrunner.  From what I have read, two diodes in parallel will allow more current only if they have the same specifications, better to just get a higher rated rectifier.  Two diodes in parallel doesn't change the voltage drop.

Hi 4Tesla,

Regarding this paralleled diode question you are free think what you wish of course, especially your very last sentence above. However you may wish to consider what I wrote earlier in this thread on paralleled diodes, please read  this link:
http://www.overunity.com/index.php?topic=3842.msg287926#msg287926 


Now I have tested a fast recovery type diode, RHRP8120 (1200V, 8A, with less than 55nanosec reverse recovery time) made by Fairchild. Using again a transistor curve tracer, I found 1.3V forward voltage drop across it with 1A forward current. Then I paralleled a 1N4007 type diode with it and the combined forward voltage drop was reduced to 0.84V at the same 1A current.
1.3-0.84=0.46V  this means that at 1A current the load can receive 1*0.46V=0.46W more power which would have been lost across the single RHRP8120 diode should it have been used.  For a 2A current this is already near to the 1W 'gain' towards the load which would never have reached the load via the single diode. 
In a full wave diode bridge, there is always two diodes ON at a moment, meaning nearly 2W 'gain' towards the load as useful output, for 7 gen coils this is nearly 14W 'extra' power, just regained from diode loss. (Assuming in this example that the diode bridge diodes have a similar forward voltage drop like my randomly chosen RHRP8120 type had.

So now it is quite understandable why Romero found that connecting 1N4001 or 1N4007 diodes in parallel with the inside diodes of an off the shelf high current diode bridge the output power increases in a not negligible way. Even if you regain a few Watts from the diodes loss, it can be useful for the load, or can be just the missing some Watts for looping...

rgds,  Gyula

[4Tesla]

Hi 4Tesla,

Regarding this paralleled diode question you are free think what you wish of course, especially your very last sentence above. However you may wish to consider what I wrote earlier in this thread on paralleled diodes, please read  this link:
http://www.overunity.com/index.php?topic=3842.msg287926#msg287926 


Now I have tested a fast recovery type diode, RHRP8120 (1200V, 8A, with less than 55nanosec reverse recovery time) made by Fairchild. Using again a transistor curve tracer, I found 1.3V forward voltage drop across it with 1A forward current. Then I paralleled a 1N4007 type diode with it and the combined forward voltage drop was reduced to 0.84V at the same 1A current.
1.3-0.84=0.46V  this means that at 1A current the load can receive 1*0.46V=0.46W more power which would have been lost across the single RHRP8120 diode should it have been used.  For a 2A current this is already near to the 1W 'gain' towards the load which would never have reached the load via the single diode. 
In a full wave diode bridge, there is always two diodes ON at a moment, meaning nearly 2W 'gain' towards the load as useful output, for 7 gen coils this is nearly 14W 'extra' power, just regained from diode loss. (Assuming in this example that the diode bridge diodes have a similar forward voltage drop like my randomly chosen RHRP8120 type had.

So now it is quite understandable why Romero found that connecting 1N4001 or 1N4007 diodes in parallel with the inside diodes of an off the shelf high current diode bridge the output power increases in a not negligible way. Even if you regain a few Watts from the diodes loss, it can be useful for the load, or can be just the missing some Watts for looping...

rgds,  Gyula

What I've read is the diode with the lowest forward voltage drop turns on first and will take most the current.. so is a 1N4001 or 1N4007 diode rated at 1A?  I don't think you can get a voltage drop below the lowest rated diode.  I believe the diodes that were added were doing most of the work because they had a lower forward voltage drop.

[Cap-Z-ro]

Quote from: Cap-Z-ro on Today at 06:52:19 AM

    What I get from Vicktor Schauberger is that water current is similar to electrical current in its general properties.

    I know that the pressurized release of water is more powerful than more loosely flowing water...AND that the pressurized release of water is pulsed is far more powerful than a steady stream of pressurized water.

    I also seem to recall that Tesla believed the capacitor to be the key to free energy.

    To me it appears that the bang of a dead short and collection of the fall out may be less efficient than build up of potential.

    Just my thoughts and objective once I am able to start on Clanzer's experimental unit...I wouldn't be too too disappointed if someone here were to beat me to it.

    After all, we are all a 'Johnny come lately' in this field of research...once its done, it will not matter anyway.

    Regards...


Quote from toranarod:

I also seem to recall that Tesla believed the capacitor to be the key to free energy. I am starting to think the same. Go Back to the EV gray Motor.

the coil shorting experiments lead me to this conclusion. HI current low voltage and convert it the voltage again into a capacitor. with no load on the drive system.  this is where todays test have concluded.

this is the wave form of the coil shorting test. the voltage goes over 200 volts when collected into a capacitor.
---
   

Thank you for the second on that Rod...interesting that water comes in waves also

Sometimes its hard to see something when you are heavily focused on something else...thats where an observant audience can be helpful.

I just wanted to pass that along, in the event it may light a spark.

Regards...

[gyulasun]

What I've read is the diode with the lowest forward voltage drop turns on first and will take most the current.. so is a 1N4001 or 1N4007 diode rated at 1A?  I don't think you can get a voltage drop below the lowest rated diode.  I believe the diodes that were added were doing most of the work because they had a lower forward voltage drop.

Yes, it is true what you read on the lowest forward drop diode conducts first and takes most current.  Also the 1N4000 diode series is designed for the 1A continuous current rate (but practice shows they can be abused a little higher than 1A, especially in a diode bridge config, just look up their data sheet for their max peak current ratings)
I also agree that the diodes that were added were doing the most of the work just due to their lower forwrd voltage drop.

But how do you mean you do not think you can get a voltage drop below the lowest rated diode?   You mean you have two diodes with say 1V and 1.3V forward voltage drops and you cannot get a lower drop than 1V when the two diodes are paralleled?

I have just described my findings in my previous post on that. In my referenced post written earlier I included that paralleling power diodes is not an accepted way in this art and many design engineers use power diodes just fit for a particular job, they never parallel them. But the fact remains: resultant diode bridge losses get reduced when diodes are paralleled with them!

Gyula

[neptune]

@Bolt . You talked about coil shorting creating "broadband harmonics ". Remember that there are no such things as sub-harmonics . So harmonics are always the fundamental frequency x 1 or 2 or 3 etc . So we are looking at frequencies much higher than we would normally expect . High frequencies mean skin effects  requiring the Multi strands or Litz wire .