The Tesla Project

[allcanadian]

@wattsup

Also, I'm puzzled, please see on your post the second figure diode seems to be in backwards given the direction of flow. I could be wrong but in wikipedia the diode current is shown going the other way.

If you look at the circuit "current" flow in my last post you can see if the diode was reversed all current would flow around the inductor --- a short circuit. The diode direction depends on the circuit and whether the inductor is allowed to "collapse" and reverse polarity or just act as a flywheel as in step-up buck boosters.
Here is the best site I have seen on buck-boosters or DC/DC converters, go to flyback converters near the end---- very cool.
http://www.powerdesigners.com/InfoWeb/design_center/articles/DC-DC/converter.shtm

I have attached a picture of localjoe's circuit, notice it is a boost converter step-up converter, with a low inductance coil (L2) in the switch leg, which is well....... very cool. 

[Localjoe]

@armagdn03

Fair enough . Just wanted to make sure you weren't toying with me.

@AllCanadian

Thanks for the real circuit drawing  .
                                                                           Joe

[wattsup]

@Localjoe

allcanadian is the one who put up that circuit.


@AC

Here's what I am trying to explain about the diode being backwards in the circuits. I pulled these gifs off of wiki. It shows current can only enter from the triangle side, pass the straight line and cannot come back. This is why I am so confused about those two circuits. Is wiki wrong (would not be the first time) on something so obvious.

[Charlie_V]

@wattsup,

The way wikipedia has drawn it is correct.  Current (which is conventionally drawn flowing positive to negative) will go in the direction that the diode arrow makes, the bar means that it cannot flow back the other way.  In the circuit, the battery will charge the capacitor until it reaches a point where it arcs (atleast it seems like the break in the top portion of the circuit is a spark gap).  Which will then allow current to flow from the battery into L2.  However, this circuit doesn't seem to allow the capacitor to discharge?

@AllCanadian,

I'm going to be conducting Tesla's power transfer experiment for one of my directed studies.  Since you've been experimenting with Tesla stuff, I wanted to ask you some questions.  One, do you know why he matches mass weight between his primary and secondary coils?  He says its for best results but never mentions why it gives best results, have you figured this out?  What frequencies do you use?  In Colorado Tesla used 90-400kHz, is this the range your using or is it lower/higher?  Are you reducing the internal capacitance of your coils? (aka are you using single layer coils with widely spaced windings so that the capacitance between the wires is as small as possible?)  Tesla mentions that a coil with high inductance and low internal capacitance will be able to freely oscillate for longer periods of time.  And lastly, have you tried the "extra coil" yet?  Apparently, since the coil is away from the inductive coupling of the primary, it doesn't get damped and can really resonate for a long period of time.  Tesla said that when he used his "extra coil" he only used the secondary as a normal step-up transformer (acting on only the turns ratio) where as the extra coil was used for the resonant rise magnification.  The thing that confuses me is that I think he was still making sure that the secondary was a quarter wavelength of the frequency.  Since the extra coil was also a quarter wavelength, this means there's 1/2 wavelength in the secondary circuit and the standing wave anti-nodes will be all messed up.  Have you figured this part out yet?

Thanks,
Charlie

[wattsup]

@Charlie_V

Sorry if I was not clear but the circuit diagram I am referring to is on this thread but on previous page here.
http://www.overunity.com/index.php/topic,3972.msg77183.html#msg77183

For the mass matching, we had covered this with Erfinders first circuit where there were two primaries with their total mass equal to the total mass of the four secondaries. It has to do with the total electrons being moved from one to the other so one produces just enough for the other to handle, not more, no less, making it a perfect tunable pair. There is also a question of timing or frequency matching using Tesla speed of electricity calculations. But others here will have a better explanation I am sure.