Tri-Force Magnets - Finally shown to be OU?

[sm0ky2]

@ OMNI

go back and read your own last 10 posts......     i think we need to take away your "virtual-scientist" title...

I'm going to give you a little gift here in a couple of days....

You go back, read them carefully and try to understand them. It will only be to your benefit.

Besides, who are those "we" you're referring to. You are the one saying the above and you're not a royalty to refer to yourself as "we". Therefore, edit your post and replace the "we" with "I".

"we" was referring to this particular online community, as "I" do not have to power alone to strip you of your self-proclaimed  title. Rather - "I" think "WE" should no longer give you credit for this self-proclamation.  <<--- does that suit you better?

[Omnibus]

@ OMNI

go back and read your own last 10 posts......     i think we need to take away your "virtual-scientist" title...

I'm going to give you a little gift here in a couple of days....

You go back, read them carefully and try to understand them. It will only be to your benefit.

Besides, who are those "we" you're referring to. You are the one saying the above and you're not a royalty to refer to yourself as "we". Therefore, edit your post and replace the "we" with "I".

"we" was referring to this particular online community, as "I" do not have to power alone to strip you of your self-proclaimed  title. Rather - "I" think "WE" should no longer give you credit for this self-proclamation.  <<--- does that suit you better?

PK, then don't refer to your opinions as expressed by "we" because that's not the truth. Edit your post and replace the "we" by "I".

[sm0ky2]

On the right side of this Image you see a scale. This scale depicts even increases in Magnetic Potential.   @ A_0 (Point A of the SMOT) the ball is outside of the magnetic field,  and thus M(a) can be considered "0". - (in this set-up, we have a necessary "null" space between A-0 and A_1.)
@ A_13 (Point B of the SMOT) the ball is at the entrance of the SMOT, and thus M(b) is MAX.
Let's assume this energy value to be 13 Joules. (Giganta-SMOT)

As the ball is raised to A_1 - the ball is imparted with 1 Joule of potential energy - the Ball-Lifter has at this point imparted -1 Joule of energy to hold the ball in-line with Point B. (also added is the +mgh)
As the ball is raised to A_2 - the ball is imparted with 1 Joule of potential energy, bringing the ball to total 2 joules potential, and -2 joules imparted by the Ball-Lifter.

This continues up to A_13 - where the ball is imparted with a total of 13 Joules of potential energy -
and -13 Joules of energy have been imparted by the Ball-Lifter.

The ball is sent towards Point C - during this transition, the 13 Joules of potential energy are converted to kenetic energy - When the ball reaches Point C - this energy is inverted to -13 Joules of potential energy.  <----- WHAT?? -13?  YES -> you also have a +mgh(c)  energy at this point, which we'll go ahead and make the assumption that it is greater than 13 Joules.

Gravity strips the ball off the magnet @ Point C, downwards vertically,  out of the magnetic field, onto the ramp, returning the ball to point A. Converting the -13 joules of potential energy, the +13 joules of gravitational potential, and the remainder of  [mgh(c) - M(c)] leaving the ball with 0 Joules of Energy. Just as it started with.

*losses to heat/sound/friction/ect. are not taken into consideration in this model

[Omnibus]

On the right side of this Image you see a scale. This scale depicts even increases in Magnetic Potential.   @ A_0 (Point A of the SMOT) the ball is outside of the magnetic field,  and thus M(a) can be considered "0".

Wrong. I already told you that but you don't want to learn. No need to go any further into your text. You are totally confused.

[sm0ky2]

On the right side of this Image you see a scale. This scale depicts even increases in Magnetic Potential.   @ A_0 (Point A of the SMOT) the ball is outside of the magnetic field,  and thus M(a) can be considered "0".

Wrong. I already told you that but you don't want to learn. No need to go any further into your text. You are totally confused.

considered "0" means the magnetic field AT THAT POINT has no observable effect on the BALL. the other forces on the ball are dominant AT THAT POINT - thus the magnetic potential isn't DOING ANYTHING TO THE BALL.  Now,- is there "some" force on the ball, pulling it towards (vertically under) C?
yes - in fact there IS! but this is insignificant. 

I feel like im talking to a child here. It's absolutely AMAZING that I have to explain everything to a "scientist" in baby steps.
Now, before you start rambling bull$%& again - allow me to REDIRECT you to the fact that i am talking about the POTENTIAL FOR THE BALL TO MOVE - not some arbitrary energy value, offset by gravity and friction. - and yes, the conditions on the ball DO change as the ball leaves the 'ground' - THIS is why there is a NECSSARY "NULL" zone.