A truly overunity Transformer / Meg

[Nali2001]

1: A irfp250 npn fet was used at 24v 50% duty.
2: The voltage of the cap was 100v max. All together 1mf was needed for 'best wave', but ya need to tune the cap which means maybe in you setup you would need 2mf or 100mf/ depends on freq/volt/pulse width. Just connect a scope and add or remove caps until you get what you want. Anyway the 'oscillating' sine voltage that is produced is many time higher than the initial voltage input. One other thing the caps must be foil or run caps. And not electrolytic caps since have a fixed polarity.
3: The diode can be anything that supports the volts (and amps in real use) I think I used a Byv95c http://pdf1.alldatasheet.com/datasheet-pdf/view/61974/GE/BYV95C.html But any cheap diode will do use 600v or 800v types or something to be sure. Not that important in these '1watt' tests.
4: Don't know how many turns, was not all that important at the time, the test was to show the effect but If I have to make a guess I'd say 500wraps of 0.8mm wire.

[nievesoliveras]

Hi!

Thank you nali2001!
I have another question if it is not too much to ask.
If I dont have an oscilloscope. Is there anyway to know the values of the capacitance I need?

Jesus

[Nali2001]

Hmm well, you could use a volt meter (I prefer analogue) to see which value cap gives the biggest peak to peak sine wave voltage.
But a max voltage peak is not really the idea behind this pulse-to-sine method in meg use. You need the right value cap so that the sine it produces correctly 'connects up' with the next dc pulse. And only a scope can 'show' this to ya. If you have some spare cash I recommend to get yourself a second hand scope http://shop.ebay.com/items/__oscilloscope_W0QQ_nkwZoscilloscopeQ20QQ_cqrZtrueQQ_nkwuscZocciloscope or a usb scope. I have(and a old analogue one): http://shop.ebay.com/items/?_nkw=dso-2090&_sacat=0&_fromfsb=&_trksid=m270.l1313&_odkw=2090&_osacat=0 The software has some very handy functions like real time rms calculation form strange waveforms and such. Comes with two probes as well.

[Nali2001]

That your transformer with diode was lighting the bulb is because regular transformers can't handle dc (half wave) transformation. If you pulse a core constantly at one input polarity it will in between pulses not 'reset' or flip it's polity and so always tend to stay in a 90% magnetized state, even in between pulses. That means it saturates in a blink of an eye and start pulling massive amps. Those amps were pulled through your bulb so it lit up. That is why there is ac, so that the polarity of the core is inverted each cycle which causes good field change and so good output/performance. Also it will in ac set up a back emf against itself so when unloaded it only draws one watt or so. Simple to test, put half wave ac in a transformer and it saturated with a few volts/ and whop the amps sky rocket. And yes if a core is saturated it can pull 10amps+ easily(no limit). You then only have dc resistance on your coil. So your 100watt core was most very likely pulling more than that. In a sense you made a 'saturable reactor' or else know as a 'Magnetic amplifier' http://en.wikipedia.org/wiki/Magnetic_amplifier Where the saturation level of the core acts as a switch(regulator) for the to-be-regulated ac power. http://en.wikipedia.org/wiki/Saturable_reactor


Lets call back emf> Bemf
and a inductive collapse/flyback> inductive collapse

Did the ohm test you described and don't really see anything unusual. Same value each combo. So maybe you used a core that hold a little permanent field?

Regards,
Steven

Hello Steven,

good question. I once had observed a weird effect when I loaded the primary of a step-down ring-transformer
( 230 V -> 12 Volt , 100 Watt ) with a halfwave, as this is shown in the hand-drawing above . Since I am a cautious person I put in series behind the diode a 230 V incandescant-bulb ( 30 Watt ). Now without diode the free wheeling transformer ( no load attached to the secondary) usually consumes just 0.7 watt and the bulb is dark.
But with diode the bulb was fully lit and the ring-transformer was humming and vibrating very loud with 50 Hz.

I stopped this experiment because at that time I thought it does not make sense to have that much of energy lost already at the primary with no load. Now the problem was that my watt-meter ( I bought this from a professional electronic-company here in germany) was showing more than 30 Watt input, so I knew then that it was reading false values.

You can try this yourself. I think something weird is happening with the Kick-Back-EMF after each halfe-wave which is not synchronized with the grid-frequency. If the kick-back-emf arrises it feeds back into the grid at the time the negative-part of the sinus-wave of the grid is on thus it is a grid-controlled back-feeding of the Kick-Back-EMF with no diode.
I now must repeat this experiment and find out more.

When I say Kick-Back-EMF then I do not refer to Back-EMF - this is something different.

In order to give you an impression of this  Kick-Back-EMF - especially in ring-transformers - you do the following experiment :

You take a transformer ( ring-trafo or a usual trafo of bigger size - at least 100 Watt ) measure with a analoge-Ohm-Meter  the primary until the scaler has reached his final position. Then - and you have to do this very quick in about 2 seconds  - you disconnect the probes and measure again but this time with changed probe- position on the leads. Tell me what you see.


Regards

Kator

[Kator01]

Hi Getca,

lol !
why I asked you if you are frowning is because you just put these three images  without any further
comments.

No, I don not question your results but just want to make it sure you use correct measurement-values.

Why not bulbs ? Because it is of no advantage since they have a non-linear inner resistance depending on voltage and current : you have to measure in the same way - as you stated wiht scope

1) Current
2) Voltage

to find the actual power

Many inventors just use the brightness of an incandescant bulb for cop > 1- proof.  And I assume you know this here :

http://en.wikipedia.org/wiki/Incandescent_light_bulb


Go to paragraph : Electrical characteritics

... and understand that you can - for example - have verly large current at lower voltage ( bulb is dark ) and lower current at higher Voltage ( bulb is lit ) but wattage is bigger in the dark input-bulb.

In order to have proof it is a must to use normal resistors and not bulbs.

I do stress this subject here because in one of the videos he showed  three bulbs in series lit up by the MEG.

Regards

Kator