Stubblefield coils (bifilar) and speculations

[resonanceman]

You don?t think the Electron shuttle looks like Tesla?s wireless energy?
(the missing transmitter)
sad, and hostile.
i deal with electrostatics. i have a 30 cm Wimshurst i built.
does that count as "builder"?

Cliff,

Cliff

Sorry

I didn't see any  mention of  your  Wimshurst machine   on the links .

To be honest I didn't  see  the electron  shuttle  as  tesla's  wireless transmition ............but it  could be .

I  was wondering  about if it  could be adapted to  efficient HHO production
One of my  projects on my want to do list is a tesla based   electrolizer .
Imagine  a  beaker  of water  placed in the  center of a  fairly  low voltage  tesla coil secondary .
2 sheets of stainless  steel  .......one  longer than the other can be wound into a coil    the  smaller  one  would  have a ground  wire attched .

there would  be a  variable  resistor  on the  ground 

with the   stinless steel   coil  in the  water  ..........the  longer   piece  of steel  will pick up more voltage from the  tesla coil  secondary .


you now  have   a  pair of  electrodes   in water ....... you can  control the  relative  voltage  of the  electrodes with the   resistor  on the ground wire .  .......and the whole thing is in a stong  magnetic field   


now ............my  question  for you 

would  your  electron  shuttle  add to my  idea  if I was to do something  like   put  large plates on each side of my  stainless  coil  and  shuttle   electrons  back and forth?

[Localjoe]

@bill

I bet your inital cap rod setup woudl run a small digital clock. next to positive acctually.   
                                                                                                  joe

[Pirate88179]

@ All:

For some of the newer folks, here is a video of an electrode set up where he claims 1.1 vdc and 1.8 amps.  One of his electrodes is like a very long grounding rod used in home electrical applications.  Thought you all might like to see it.

http://www.metacafe.com/watch/834037/battery_hack_the_planet/


@ Joe:

I will have to look around for one to give it a try.  I honestly never considered trying anything more than the leds at that time.  I think the more variety of things we can power from what little we have would be cool.

Bill

[Pirate88179]

@ Jeanna:

Here is a video of a guy who also wound a secondary.  Since you have been doing a lot of this work, I didn't know if you had seen this one or not.

http://www.metacafe.com/watch/yt-BmNoLfjIEac/stubblefield_earth_cell_battery_demonstration/

Bill

[DrStiffler]

@ Jeanna:

Here is a video of a guy who also wound a secondary.  Since you have been doing a lot of this work, I didn't know if you had seen this one or not.

http://www.metacafe.com/watch/yt-BmNoLfjIEac/stubblefield_earth_cell_battery_demonstration/

Bill

@Pirate88179

BIll, I'm sure I am making a mistake by talking on this thread as the last time on a different but related thread some dude that showed a picture of himself 'Fat, pimple faced and discussed his first date  "Love"  life' chased me off.

Any way I have watched both threads and I see a common error in how one assumes they are getting some place. First current or voltage are irreverent unless considered together. To get to watts the very simple formula of P=EI can be used where P=watts, E or V = volts and I = amps. Now 1amp X 1volt = 1W as does 0.5amp X 2volt = 1W. When you see someone showing 1.2V then connecting the source together and showing for example 1amp, does not mean 1.2 X 1 = 1.2W. The reason being the meter in amp measuring mode should present a very low impedance (resistance) if you will (else it would act like a resistor across a load and dissipate energy. The last video you referred to should have measured E or V and I together, then we could see what was really available.

From the brightness of his LED one can be sure that the so called voltage drops a lot when even the LED is connected, reason is no matter how it is shown the LED is really very dim.

All I am saying is you want to look at V and I together in your work and if you use the very simple approach of P=V X I you will see where many of the reading found by experimenters are about the same when it comes to P. Yes indeed V may be higher, but I is lower, then I is higher and V is lower and the product stays about the same.

Sorry for jumping in here and don't send .... after me.