Roll on the 20th June

[oak]

Sean, beautiful job.

Archer (and all), does the wheel as a whole need to have a certain minimum mass to provide enough momentum for the rod magnets to "break the wall."  In other words, so that the wheel will keep turning enough, by inertia, for the rod magnet to be pushed into the fields of the upper and lower magnets so that the rod will lift.  If there is not enough mass (inertia) in the turning wheel, will the repulsion of the lower magnets simply stop the wheel?

[legendre]

@legendre,

My question was not that of free energy or not. My question was if there will be a decreased, increased or the same power usage in the electric motor.

If I understand your answer correct then because of the magnetic sticky point there will be an increased power usage?

Groundloop.

First, we have to get our thinking straight. Power is a measure of the rate at which work is done (or may be done); power is not a quantity of energy. Power is instantaneous, and in the case of your examples, varies continuously over the course of a cycle. So, where in the cycle would you like to take your power readings? Clearly, there are an infinite number of positions at which power can be measured..

What's most important to understand about your question, is that in either example (with or without magnetic forces) total energy around the loop sums to zero - minus losses to friction, air and so on. That is, in both cases, the only continuous energy input required to complete a cycle (or series of cycles) is that energy which is lost to friction, etc. Now, in the first example, if we start at the ground state (car at 6 o'clock) we must do work to raise it to 12 o'clock, which requires a quantity of energy input - but after completing a cycle (or series of cycles) we may take our energy 'loan' back out, as the system can perform work for us as it's allowed to fall back to the ground state.

So, if the example with the magnets introduces more friction to your system (likely, due to radial loading), it will require more energy to complete a cycle. As for the maximum power at any given point in the cycle, that will be determined by the interplay of gravity and the magnetic forces which you've introduced - and are an unknown quantity.

-L

[ramset]

LEG  the question  more or less[POWER] to run the motor [car is on wheels with THK bearings and yoko low friction race tires]                                                                                                                             
@REDRI NICE VID lays out the concept quite clearly
@Sean nice!! solution in the middle
@ Mank cool simple path to proof of concept
  Chet

[noonespecial]

I just have a dumb question......
Unless I'm missing something, why are the opposing magnets/weights tied together? Wouldn't centripital force move the descending ones out anyway without needing to be pulled out (assuming there's considerable rotation)? What if there were only opposing magnets at 7,9, and 11 which moved the ascending magnets in. I was looking at Sean's work of art before he added those hideous hacksaw blades  and it struck me.
I'm sure that someone will 'splain what I'm missing....thanks!

[ramset]

NOONE   there is another whole arm that cantalevers over the mags  and if you don't push the weight back in it just won't spin pretty or not    it works on the concept of an unbalanced wheel never being able to stop turning   Chet