URGENT! WATER AS FUEL DISCOVERY FOR EVERYONE TO SHARE

[greendoor]

Thanks Ossie ... I was just speculating, because I know a battery can deliver huge peak current (e.g. starter motor).  A lead-acid battery is kinda like a large capacitor ... The problem you describe would seem to be solvable with switching??  I'm just thinking that any inverter or coil arrangement for voltage multiplication (or division??) might be a waste of power, if the Ampere force is the operating force.

Anyhoo - a random quote I just pulled from googling around ... I find it very enlightening:

To understand the effect you have to first realize that heat is space 'wiggling' in place. Then you also have to realize that an electric discharge is basically space realigning itself. So, a violent "moving" of space that allows the heat to instantly redistribute. Just like thunderbolts cool down...

Is he right?  I suspect yes ...

[greendoor]

I would like to point out one simple fact:

I can make this effect with a variac or inverter DISCONNECTED/ISOLATED (both terminals isolated) from the capacitor so this rules out 100% for a fact that I am getting any extra high current surge from the power supply.

Some want to believe it can come from a capacitor...(once it is discharged).

What S1R shows with some inverter touching the plug off and on through a relay and then ignition coil off/on...whatever he is showing is NOT the same method as Luc has found. So some are automatically thinking that there is some surge from the power supply to make this spark based on Luc's circuit because of some crossed idea that it is supposed to be the same thing?

Also, has anyone bothered to scope the function of the diode?

I see something that seems to almost be deliberately IGNORED here. My power supply is 100% separated from the capacitor on BOTH terminals when the capacitor is discharged into the spark plug. That means 100% as an undeniable FACT, there is no current surge from my variac or inverter going to the coil when the HV pulse leaves the ignition coil.

So that leaves the capacitor as the only thing connected to the circuit as far as input. Once the capacitor is discharged, there isn't enough to provide any current surge! With a 3uf capacitor, that is 0.0384 joules of work possible (with no losses) if it is charged to 160volts. That is LESS THAN 0.04 watt seconds worth of energy...and if using a 3uf cap, once it is discharged and claiming that there is some current surge from the cap..again AFTER it is discharged will have some current surge that assists this spark...even with a 47uf cap at 160v, that is 0.6 watt seconds or 0.6 joules...and AFTER discharge there is enough for some mysterious current surge??? LOL Well, again...is this DISINFORMATION...there might be enough energy left in the cap AFTER discharge to may raise 1 hair on a flea's leg, but to assist in some robust spark on a plug like we're witnessing???

1. Why do I get the effect without any power supply connected to my cap?
2. AFTER the cap is discharged, why do I get the effect still and do you honestly think there is enough in the cap to give some current surge to cause this effect?
3. HOW DOES A DIODE WORK?
4. Think about VOLTAGE POTENTIAL..........where there is any kind of voltage...that potential is available EVERYWHERE instantaneously wherever it it is in contact with some kind of conductivity as long as it is not blocked. When the arc is happening, the HV potential is available at the exit of the HV diode...what does that tell you?

Qiman - seriously thank you.  I have been quoting the Graneau paper as being the source that states (with apparant authority) that it is the Ampere force that is involved.  Maybe Graneau contains disinformation?  I don't anyone at this stage - and the fact this paper is freely available makes it suspect (even though it seems to be waving abundant free energy under our noses).

I am looking into the Electrostatic Cooling effect - and so far Voltage seems to be the key effect, not Amps so much.  So maybe I am the blind trying to lead the blind (almost certainly).
My apologies.  The one thing I am certain of, and have stated many times, is that we need to find both the minimum voltage required, and the minimum current required - in order to reduce total Power input, to maximise total Power available. 

I hope to build some devices very soon and report findings.

[qiman]

Greendoor,

The input of the diode is touching the low voltage +. The output of the diode is touching the HV+. Anytime the voltage on the output side of a diode is HIGHER than the input, the DIODE REMAINS CLOSED.

When is there less voltage potential on the diode's output than the input side? When does the voltage drop below the input side? When the cap is discharged, think about how how much is left and what that diode is.

When does the other side of the diode drop BELOW the input side of the diode in order to open that diode?

Until then....the diode remains closed.

[qiman]

Also, please note that not one ampre has been measured in the history of mankind.

Meters have never measured one single amp.

The meter measures VOLTAGE through a known resistance and that tells you how many "amps" is there...still NO AMPERAGE HAS EVER BEEN MEASURED DIRECTLY....the meters measure nothing but VOLTAGE through different circumstances.

[greendoor]

Hello all!

Only reading this forum for years, finally my first writing! 

Probably a bit offtopic, so sorry for that first...but:
Did we finally (re-)discover the "holy grail" of electronics here?
Powering a single "device" with two powersources. From one drawn high voltage, low current- from the other low voltage, high current.
Here joining them together just before the airgap (sparkplug).

What if you join them together just before a coil? Or an ordinary light-bulb?
How would then the effective power accumulate (From voltage x current (U*I) as Ohm?s Law says)?
If we draw from the hv-source 10 watts (100volts*0.1amps), and also 10 watts from the lv-source (0.1volts*100amps), would the effective combined power on the lightbulb be 20 watts or 10000watts?
Could this somebody try to verify? With an ordinary lightbulb?
Is there even a possibility to "create" such small voltage x huge amperage powersource?

Or is this all garbage? If so, then sorry for that...

Another thing regarding this circuit:

I am certain, that a circuit utilising resonance (between coil and capacitor) would undoubtly need less amount of energy than not in resonance.
Anybody considered that yet? Is it even possible to utilize in this circuit?
Of course this would mean fixed RPM within an ICE, but it maybe a possility in an ICE/generator setup with fixed RPM...


All the best to all of you guys, especially the few who do actually build and test things!

I'm not sure what you've been reading here - but your conclusions are nothing like what i've learned here ...

As far as i'm concerned, there is no secret power in the spark.  Most people here seem to be using the brute force approach - maxium volts, maximum amps - large power input, for hopefully enough power output to drive a piston down a cylinder ...

The power i'm interested in is in the water.  And it would appear to be in the molecular bonds holding water together in a liquid state.  By atomising the water with a spark - the water suddenly has less molecular bond energy - and because energy is neither created nor destroyed - the energy that was previously holding the molecules together is transformed into violent kinetic energy.  And apparantly the temperature drops too - which I don't understand yet.  Heat is kinetic energy - but obviously there are different forms of kinetic energy.  For example - it's possible to freeze something (reducing heat energy) and accelerate it (increasing kinetic energy) at the same time - so different effects are obviously at work here. 

The subject of electrostatic cooling seems to be linked here.  If objects can be suddenly cooled with the application of high voltage with minimal current - it would appear that massive overunity heat engines should be possible.  I'm thinking this water arc effect is ultimately a heat engine.  But I could be barking mad.

I'm just looking for the best strategy to build a device to test these wild theories ...