S1r PDF coil description and discussion !!!!

[whopper1967]

Hey capacitor,hows it going?You make any more progress in you trials?Very impressive so far.

[Super God]

Thanks for the circuit diagram, cap70.  I understand it better now.  Before it didn't make any sense, but now it does.  Thanks again!  You sure are a BIG help!!

[Shanti]

Well here are my thoughts about the circuit... 

As I see it, this coil setup works pretty similar to the Stan Meyer coil, or the Tesla patent how to rectify without diodes, just with coils...

This is how I see it, what this circuit does:

* If nothing is running, then the LV is running the lightbulb and at the same time, is responsible that quite some current is running through the LV coil, which does generate a magnetic field...which should also drive the core (nail) into saturation...(this is the only reason why the lamp and lv running while no firing is needed)

* If now the HV is firing the core is already in saturation and therefore the Hv coil does not see a big inductance. Now it will let the HV through to the spark, maybe there will also be a little transformer action, due to the coils being quite close together, but as the core is saturated I personally think it should not be big...
(This is somewhat strange for I think some transfromer action could be better, so that the LV coil gets an even higher voltage than the HV part. This would surely protect the LV part completely. If this would be wanted, then the coils should be ontop of each other... Then it would be kinda a circuit like that here: http://www.myelectricengine.com/projects/mpdthruster/ignition/ignition.html)
Nevertheless. If we think, there's little transformer action , then the Tesla principle has to work. Mainly, that the HV surge does see the unsaturated side of the lv inductance and will have a great deal of problem to flow to the battery (high impedance), therefore will also protect the battery from the HV.

Like that the HV can build the spark.

* As soon as the HV is over, the LV current will continue to flow, as at the beginning. But as now there's still some arc left from the HV, the LV gets discharged through the plug instead of the lamp. Now without any amp limiting device (lamp).

* After some time, the LV will not be able to maintain the plasma and the resistance of the spark gap will again rise, so that now, all the LV is again discharging through the lamp...
(And we are back at the beginning...)

Ahh, I forgot the lamp coil...Well, maybe just another protection from the hv surge, but a little bit made in a strange way...

Well these are just my quick thoughts. Hasn't be to be correct in any sense...

Second thought:
In layman terms a coil action is described as: The coil always tries to keep the current flowing at the same level...
So in this view, if the coil was running at 5Amps and you suddenly raise one side to a HV. If this layman term would be still correct, then the coil would still have to output its 5Amps, but now on HV level...

But as I said, this is in layman's terms, and far from any known electric science.
(But sometimes a layman finds things, a pro doesn't...)

I just watched s1r's first video again. I must be missing somthing. The inverter looks like it is hooked up. One leg to the base of the plug, the other goes into the can.

Aehmm, where's this video???

[cristache]

video 1
http://www.youtube.com/watch?v=tb3d_hf7R10
video 2
http://www.youtube.com/watch?v=pBCl3OdM9Y4

[Shanti]

Thank you very much! I really like the way, water powered motors sound like...

Again about the LV coil HV interaction. As I see it from a electronic side of it. The HV surge on the LV coil would try to stop the amp flow through the coil, so the coil would answer, as if it has been disconnected -> an inductive kickback (like the primary of an ignition coil). So it would also by itself generate a HV pulse by this inductive kickback, without any "transformer" interaction.
The only thing I think is strange, is the extremely low number of turns of the coils...
I could understand it, in the setup with the relay's, for the relays do have quite some turns, but 13 turns?

BTW: If this circuit really uses the Tesla way of protecting the LV side, then it would be essential for security to add a varistor on the battery side. Because if, due to any reason, the HV surge is not capable of discharging through the plug, it will go to the bat, although the impedance is big...(the impedance of the plug should always be much smaller than the lv coil...)

As I said before, these are just my thought. I don't tell anyone they are correct.
But maybe someone gets inspired by this. As I see it, it's best if everybody contributes his thoughts, so that we together can finally get to the solution...