Selfrunning Waterpump-generator device runs 60 Watts lamp...

[spinner]

Cavitation in liquid dynamics is something any engineer is fighting against since ever. Why? Simply because it always introduces additional losses (poorer efficiency due to a changed fluid viscosity, sonic/vibration,.. thus severely reducing machinery parts life.

Maybe you should check what cavitation does to e.g. power boat propellers, high-pressure nozzles, pump/turbine vanes and cavities, etc... A great amount of time, research and resources went into this.... Wouldn't you think that at least some of the people (experts) who were and are professionally working in this area would notice some interesting anomalies (especially in energy terms)?

In one of my earlier posts I made a comment that a setup like we saw on the video cannot be more than some 10, at best 15 % efficient. In order for such system to become self-sustaining, (at least) one of the parts must produce rather large 'overunity', say 10-times...

Without knowing any real data (inventor promissed new info in this week, yes?) it seems that most of the optimistic people here are looking at the pump as the (main) source for OU. But why would this pump (so far we don't know if it is modified) which looks like a common, serial product, been able to produce 10-times more work as it's input is???
You gotta be kidding....

Say, for instance, pump's CoP is 10. Naturally, when you say "coefficient of performance", then you have to define from where the additional energy is comming from. Period.

Ok, for the sake of discussion, let's say we don't know the source/origin of this surplus energy (e.g. we don't know what exactly is happening INSIDE the pump).
But, people, any water pump - if one consideres it as a thermodynamic system - has no unknowns regarding the input/output (co-efficiency) definitions.
If inputs are known (electrical (pump motor), water mass/volume/pressure/flow/temperature), then outputs are easy measurable, too.

Please, don't forget about CoM (conservation of mass) principle. Water (as a medium, a carrier of energy) pumped output mass is equal to input mass. Water flow/pressure ratios are conserved, too. So if a large pressure is observed at the output, the flow is reduced
accordingly. If not, your pump would be creating water out of nothing.

OU pump or not? Just do proper measurements of pump's electro-motor in operation. No matter if hyper-cavitation, nuclear reactions or even Dark Energy makes your pump OU, then the total electrical input (supplied power) to the pump motor would drop accordingly.
And with proper el. measurements you have to deal with inductive motor power factors, ohmic losses, V/I phase shifts, + all the other losses.... Don't worry, if the pump is 10xOU, even a cheap amp-meter will show you enough...

If anything unusual is happening inside the pump, then the temperature of the output water stream would be noticeably higher, too. Not just for the rather small amount which is a consequence of cooling a motor + other fluid friction effects...

OK, let's see those OU pumps now....

Indeed, this setup is not hard to replicate. Good luck to all the enthusiasts!
Hope to hear promissing news from the inventor.
Soon?

[khabe]

Thanks spinner ,
After all we can see that not all have lost common sense,
Finally!
Anyway - will attend closely to ;-)
khabe

[scotty1]

Hey.....If he needs a good water wheel come and see me....
http://home-and-garden.webshots.com/photo/2552791560053353196cHREle
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I make pumps all day and come here to read about pumps..
Scotty.

[spinner]

@Khabe
Thanks!
Yes, we'll se what the future will reveal.
Cheers!

[guyver2k]

what pump make and model did he use?
how much PSI?
how many watts to power a pump like that?

i see where hes going with this but his over all design is flawed and limited. he's gotta think "outside his box" lol.