Selfrunning Waterpump-generator device runs 60 Watts lamp...

[4Tesla]

what pump make and model did he use?
how much PSI?
how many watts to power a pump like that?

i see where hes going with this but his over all design is flawed and limited. he's gotta think "outside his box" lol.

I don't know what pump he is using, but this one is close to what he used:
http://www.plumbersurplus.com/Prod/EBARA-EPPD-3MS1-PRO-DRAINER-Manual-Sump-Pump-1-3-HP-1-x-115/10116/Cat/689

300 watts

Jason

[fritz]

Rewind:

Hardy mentions the maximum flow capacity "type of pump" as
turbine pump with 165Gallons/minute, thats 9900Gallons per hour.
This data as well as how it looks like identifies it as
CAL T10000 pump.
http://www.calpump.com/productsub.asp?modelno=T10000&category=5
Additional there is a datasheet available: see attachment below.

From the demonstration at the beginning, we see that the pump drains
the 20 Gallons of water in about 20 seconds.
Thats equal to a flow of 60GPH in this usecase - what equals 3600Gallons per
hour.
Because of the fact that the pump has to lift the water more than 1 meter - the
flow in the scenario later will be slightly higher - lets say 4000GPH minimum.

Now we take the datasheet and if you interpolate a bit - the powerconsumption
in such a case will be around 900 Watts.
According to the SI unit system 1kWh equals 3.6MJ of energy.
If this pump runs for an hour it needs 0.9kWh-> 3.24MJ of energy.

The water:
According to the video - I would say that the diameter of the water beam is
3/4 inch, 1.905cm. This gives a cross section of d^2*pi/4 of 2,85cm2.
If you divide 1000ccm by the cross section - you get the length of this
waterbeam which equals a kilogram = 1l. Thats 350cm.

The pump puts out 4000GPh-> thats 1.11 Gallons per second-> equals (x3.
-> 4.22 liter/second.
As we calculated before, 1l gives a water beam of 3.5 meter - this means that
if we have 4.22 liter/second - we have  14,78m/s speed of the water beam.

Because of the fact that the pump is not really lifting the water - maybe only
1-2ft in the video - we completly ignore the effects of potential energy here.

BTW: The pump somehow manages it that it accelerates every second 4.22liter
water to a speed of 14,78m/s.
This gives a kinetic energy from the water in the beam of
ekin = (m*v^2)/2 - thats (4.22N*14,78(m/s)^2)*0.5 = 460J per second
x 3600 seconds per hour ->1,66MJ that gives a cop of 0.51 (compared to the
3.54MJ electrical input power).

What happens if the flow would be 6000GPH ?
Electrical Power -> 1000W, 1kWh in an Hour -> 3,6MJ
Now we have 6.33 liter/s - and 22.16m/s
which gives: ___5.6____MJ and a cop of __1.55___ ..

Conclusion: it looks like the pump has at least a cop of 0.5.
And its really amazing how the kinetic energy rises with the
speed of water.

[khabe]

Vacuity Nr.14

Belt wheel has  18" diameter, generator bulley 4"  , transmission 1:4,5 , losses appr. 5% ,
Waterwheel made used like the same 18% wheel,
Why waterwheel blades placed on the 18" diameter wheel - - why not on the 4"  wheel - direct on the shaft of generator, saved 5%,
Why inventor wants to lose at least 5% of energy?
Is it some kind of ritual, like tantra, or immolation - driving away demons?

khabe

[fritz]

Another thing:

If we take the first example with 15m/s, 4000GPH.
If the water stream would oscillate - say working
in a 50% dutycycle with 30m/s 50% 0m/s 50%,
the resulting kinetic energy would be 3.5MJ -almost
COP =1. with the same flow we had before@cop=0.5.

(and if you listen to the video - there is lots of "noise"
form the water - doesn?t seem to be a constant flow)

That means that a turbulent flow has more energy.

The remaining question is how this turbulances couple
back to the pump- and how much extra energy is consumed
due to an oscillation in the flow.

[BATMAN]

BATMAN ...HERE HI ALL

Here is pic of 10,000 watt gen. hook -up to turbine shaft.

have fun ...BATMAN