Mysterious Resonant Circuit

[xee]

@ EMdevices

Hmmm, most things increase in resistance with temperature. I checked a 75 watt light bulb and it was 14 ohms without power and of course it is about 200 ohms with 120 volts powered.

watts = E^2/R =  120^2/200 = 72

If I did my math right, a 150 ohm carbon resistor will be about 190 ohms when its internal temperature is about 800 C.

[EMdevices]

@xee,  maybe your right,  I think I got my light bulb measurements backwards.  I did this a while ago.  Good point to check then, I'll follow the advice and go buy a higher power rating resistor.

@grumpy,  I checked it just with the 150 ohm resistor shorted across the 9 volt battery, and it draws around  0.4 amps, and yes things heat up quick, even the battery.  Actually, letting the circuit run for a while (I tried about a minute)  heats the resistor up really good, and I guess the battery warms up a bit too.

gyulasun, thanks for the suggestions

hoppy,  the Vbe voltage swings negative to -10 Volts or so, as can be seen in the scope shots I posted.  I hope nothing will degrade, but it might.  The transistor is certainly operating in a non conventional way.

[nul-points]

something's not adding up here:

EM measured the load res at 148.7R right?  shorting the load res direct across the 9V battery reads 0.4A on his meter

9v / 148.7R = .0605mA


time to start checking components and meter again, very carefully

all the best
sandy
Doc Ringwood's Free Energy site  http://ringcomps.co.uk/doc

[nul-points]

...in fact, if the battery is still at around 6.25V, as shown on the trace, then 6.25/148.7 = .042A

@EM
any chance your reading of 0.4A is actually 0.04A?

just a thought
sandy
Doc Ringwood's Free Energy site  http://ringcomps.co.uk/doc

[gyulasun]

something's not adding up here:

EM measured the load res at 148.7R right?  shorting the load res direct across the 9V battery reads 0.4A on his meter

9v / 148.7R = .0605mA


time to start checking components and meter again, very carefully

all the best
sandy

Hi Sandy,

You happen to have a typo:  9 / 148.7 = .0605 Amper , ok?  (you wrote mA) 
Putting it in mA,  it is 60.5mA.

Otherwise I agree with you.

rgds, Gyula