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Gravity Mill - any comments to this idea?

Started by ooandioo, November 03, 2005, 06:13:20 AM

Previous topic - Next topic

0 Members and 3 Guests are viewing this topic.

tbird

hi andi,

you're moving right along.  well done.

i have a question or 2.

"This will be V=7854cm?*1000cm=785.398.000cm? this weights 785.398kg"

"V=785.398cm? "

is the first V value just another way to write the second (never saw this before)?

"its force is F=m*g=7.704 N"  what is g?

also not sure what you mean "Looks very good, as we need quite less lifting power."  less than what?  what are you comparing it to?

"E=m*g*Dh/3.600.000J/kWh"  is Dh distance of height?

one last.  if the fall distace were .75m, does that mean power would be 1/2 again more (1.6kwh)?

tbird
It's better to be thought a fool than to open your mouth and prove it!

ooandioo

Quote from: tbird on August 24, 2006, 09:34:41 AM
hi andi,

you're moving right along.  well done.

i have a question or 2.

"This will be V=7854cm?*1000cm=785.398.000cm? this weights 785.398kg"

"V=785.398cm? "

is the first V value just another way to write the second (never saw this before)?

QuoteI mean, 785.398.000cm? equals 785.398 kg water mass.

"its force is F=m*g=7.704 N"  what is g?

Quoteg=gravitational acc.=9.81m/s?

also not sure what you mean "Looks very good, as we need quite less lifting power."  less than what?  what are you comparing it to?

QuoteI'm comparing to the mass thats above sealevel, thats the mass that has to be pumped with the shuttle.

"E=m*g*Dh/3.600.000J/kWh"  is Dh distance of height?

Quoteright

one last.  if the fall distace were .75m, does that mean power would be 1/2 again more (1.6kwh)?

Quotealso right.

tbird


tbird

hi andi,

got most of your answers. 

still not sure what mass above sealevel you are comparing.  we are talking about your design that only works on the up stroke, right?  are you comparing the weight to produce the pressure needed to compress the shuttle piston in the first design to.... something?  i'm stuck.

help!

tbird
It's better to be thought a fool than to open your mouth and prove it!

ooandioo

hi tbird,

the shuttle has to be lighter than the water it displaces, then it wents up. In a closed pipe, heading 1m above sealevel, it also has to overcome the weight of the water in the pipe above sealevel, that is 785,4kg. It has to be lighter, or its volume has to be bigger than its weight in compare of the weight of the water it displaces+the water it shall displace in the pipe above the sealevel (i think i don't understand the sentence myself...).

Andi

tbird

andi,

i think i see why we confused each other.  the water being pushed out doesn't stay above the pipe (creating back pressure). it could be delivered to a holding device supported above sealevel (you used that word) but lower than the max height the shuttle can push the water to. once the water starts to fall, work can then be extracted.  after we get water delivery (a waterfall) accomplished, then we can design the best way to make work using this falling water.  does that change your figures any?

tbird
It's better to be thought a fool than to open your mouth and prove it!