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Overunity Machines Forum



A machine to convert gravity to mechanical energy # 2

Started by brian334, October 04, 2008, 01:08:18 PM

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brian334


brian334

Fritz,
The surface area of the piston is not written in stone.
The size of the piston should match the falling 65 lb weights ability to push it out.

fritznien

Quote from: brian334 on October 12, 2008, 02:22:05 PM
fritz,
Its important to remember that because of the moveable pulley the falling 65 lb weight has a 2 to 1  mechanical advantage over the piston.

The weight falls about 11 in. the piston moves about 5 in.

i never gave a thought to the details of the mechanism, just how much energy to make the expansion
for so much as the float goes up. a 65 pound weight falls 11 inches=69.6 foot pounds , thats enough to move a piston 13
square inches 11 inches against 5 psi water. 143 cubic inches of exspansion. call it a column 12 inches square by 12 high. .5pounds X 12 X 10 = 60 foot pounds. which is what you put in with the weight.
how are you going to reset the weight without using all you gained from the float?

brian334

Fritz,
The weight in the tank floats to the top. At the top the tank flips putting the weight back on top ready for the next cycle.
Any calculation of how much the tank will expand needs to include the momentum of the falling 64lb weight.

brian334

The maximum impact velocity for a object falling 10 ft is about 17 mi/hr.
For 8 ft the tanks fall in a continuous column, when the tanks fall as a continuous column there is almost no drag with the water. At the top and bottom the tanks are pulled along by the draft of the preceding tanks.