Bedini motor with Avramenko plug OU COP = 1.1

[Pirate88179]

Way to go Stefan!  Good decision.

Bill

[X-File]

I am tired and fried mind.
Ho god, I need to rest.

[nievesoliveras]

Hi!

@hartberlin
I dont know but I saw that the motor was using a bigger amount of amperes than what was putting out the whole time.
Forgive my ignorance, but I cant see how you got the numbers for the overunity. If the input is 240ma and the aoutput is 200ma I think that it is loosing 40ma in the process.
I can be wrong though.

Jesus

[Groundloop]

@nievesoliveras,

Attached is a drawing of Ohm's law. Print the drawing and put in on your wall.

U = Voltage, R = Resistance, I = Current and P = Watt
Use Voltage, Ohm, Ampere and Watt when calculating a value.

The input was 18 Volt and 200 mA = P = U * I = 18V * 0,2A = 3,6 Watt.
The output was 240 mA across a resistance of 110 Ohm, so
P = R * I * I = 110 * 0,19 * 0,19 = 3,971 Watt.

COP = OUTPUT / INPUT = 3,971 / 3,6 = 1,103

Groundloop.

[AbbaRue]

I have watched the video over and over again.
The text says 18Volts input 210mA        output 200mA.
              and 18Volts input 200mA        output 190mA.
That means the loss of power is 10mA.
Were do you get this over unity COP=1.1
Unless I'm understanding his labeling wrong.