Joule Thief

[xee2]

@ jeanna

With reference to the base capacitor test circuit posted on last page. When voltmeter is replaced by LEDs in parallel the current drain on battery is increased. With one LED in place of the voltmeter, the battery drain is 1.4 mA. With nine LEDs in parallel in place of the voltmeter, the battery drain is 1.5 mA. These results are when using 106K base capacitor. The increase in battery drain seems to be a result of the LEDs limiting the voltage produced at the collector. When the voltmeter is replaced with seven LEDs in series, the battery drain is still about 0.21 mA. I Will edit that post to show this new information. The seven LEDs in series are not very bright. But this is only about 0.21 mA / 7 = 0.03 mA per LED.

[Artic_Knight]

i propose 3 good reasons for why there should be additional current drawn when a cap is in parellel with a battery

1. you now have 2 power sources in parallel available to deliver current twice as fast
2. a capacitor discharges faster than a battery therefor should provide additional current
3. a battery now has to charge a cap and power the curcuit thus creating extra draw

with these reasons there was still no additional draw seen on the battery and doesnt make sense.

[xee2]

@ Artic_Knight

I posted a theory of what might be happening several pages back. All theories need verification. If you have a scope then you may be able to verify some of the aspects of the theory. I do not have a scope so I can only guess at what is happening.

[jeanna]

With reference to the base capacitor test circuit posted on last page. When voltmeter is replaced by LEDs in parallel the current drain on battery is increased. With one LED in place of the voltmeter, the battery drain is 1.4 mA. With nine LEDs in parallel in place of the voltmeter, the battery drain is 1.5 mA. These results are when using 106K base capacitor. The increase in battery drain seems to be a result of the LEDs limiting the voltage produced at the collector. When the voltmeter is replaced with seven LEDs in series, the battery drain is still about 0.21 mA. I Will edit that post to show this new information. The seven LEDs in series are not very bright. But this is only about 0.21 mA / 7 = 0.03 mA per LED.

I agree about the leds limiting the energy in the system. I suppose it could be at the C-E gain.
I am not putting any Leds there with a couple of notable exceptions.
It does get silly how LITTLE amps draw from the battery can still produce a light with these circuits.
I have marked up your chart and schematic in an effort to cover all the differences.
I think the main thing I was wanting to say yesterday is that the 103KpF cap was out of range until I had 12 turns. In all the other numbers I used even smaller caps. There was an overlap in their effects on the system. Perhaps I should continue and make more turns, but I won't at least for now. I am happy that after 12 turns the frequency soared to 2.2MHz with the 103kpF cap which had just gotten into range. I would expect that to go down as the turns and volts went up. At some point I would be where your chart begins.
But as you said yesterday, these 2 circuits are so different and I am testing off the secondary completely where you are testing in the BJTLed place.
Here is the chart all marked up.

thanks,

jeanna

[jeanna]

Newman's Hot Cinnamon Torroid with 4 bright whites.

The problem is mostly with the shutter, I think. This is the macro setting, but I need to push the button sooo deep that I cannot keep the camera still at this range. But it is also out of focus. I need a tripod, really. 

jeanna