Very Easy question about batteries?

[Magnethos]

Think that I have 1 battery (3 Volts @ 1mAmp), of course, think now that I have 10 batteries like the first one:
10 (3Volts @ 1 mAmp).... In parallel connection = 3 Volts @ 10 mAmp.

I know, I can get more volts or more amps... but If I get more volts I will get Less amps.
My question is... the total output is 3 Volts @ 10 mAmp... Can I get more Amps if I get less volts? 1Volt @ 30mAmp? How?

[mscoffman]

@Magnethos

The voltage on a single cell of a battery is set by the chemical reaction that runs
the battery and you generally cannot easily change that voltage. So simply
by stacking batteries - you are always going to have to have a multiple of
the voltage of a single cell. Useful chemical electro-negativites are in the range
of .75volts to 3volts on a single cell.

This though can be easily handled by what is called a dc-to-dc converter circuit. The circuit
produces AC by switching and the uses a transformer get to the desired voltage.  Rectify,
filter, and regulate and viola you have your desired output voltage. A converter can step up,
step down or simply isolate grounds. Correct designs make high efficiencies possible.

:S:MSCoffman

[Magnethos]

So... It's possible if I use a DC-to-DC converter unit... I won't use chemical batteries. I'm going to use an antenna receptor... in other words... energy from thin air. I use an antenna and a circuit.

[Magnethos]

And now think... if I have 1300 Volts @ 20 mAH... I can get 12 Volts @ 2160 mAH?
(1300/12 = 108..... 20 * 108 = 2160)

I think I would need to build my own DC-DC converter, Right? But... this could be possible using my DC-to-DC?

[pese]

Think that I have 1 battery (3 Volts @ 1mAmp), of course, think now that I have 10 batteries like the first one:
10 (3Volts @ 1 mAmp).... In parallel connection = 3 Volts @ 10 mAmp.

I know, I can get more volts or more amps... but If I get more volts I will get Less amps.
My question is... the total output is 3 Volts @ 10 mAmp... Can I get more Amps if I get less volts? 1Volt @ 30mAmp? How?

do you mean
3V 1mAh  that say the Battery can be unload (dissipate 3volt for duration of 1 hour
or 0,1mA for 10 hours  -  2ma for an hal hour and so so on
-

IF you use 10 batteries in parallel so you have the 10 times Power
(because 10 batteries.

This is: 3volt with 10mAh- ("h" for one hour)


Of you place the 10 batteries in SERIE so you
have 30volt with over-all 1mAh


If you calculate
1 Battery  3V time 1mA (h)  so is the dissipation
is:         3mW (h)

10 batteries

3V 10mA   = 30mW
30V  1mA   =30mW      Both is 10 time more
                     power that with one single battery

I hope this was your question
GP