ENERGY AMPLIFICATION

[wattsup]

@gyulasun and @Magluvin

Thanks for responding to the three questions. Hmmmmmm. I gave this a few days to see if anyone else will answer the questions. OK, I am at work right now but when I return home I will prepare the answers and give them out here. Your answers were both the standard one would expect, but question #2 is wrong and #3 needs more explaining. I see now that for guys with the more classical perspective, I will have to break this down very slowly so you can understand what I will "try" to explain. I think it will be worth it.

wattsup

PS: Actually, if you figure that your volt meter has no real authority whatsoever to determine if a closed line is actually positive or negative, this will start to explain part of it, but there is so much more in this then that.

[Montec]

Hello wattsup

1 Open switch acts like a resistor of a very large value. No current flow so you get the same voltage as the power source.
2 Closed switch acts like a resistor of a very small value. Current flows so voltage across switch is dependent on resistance of switch.
3 Same as number 1. Polarities are a function of voltage generated across a circuit element.

[Dave45]

energy amplification

[MrMag]

@gyulasun and @Magluvin

Thanks for responding to the three questions. Hmmmmmm. I gave this a few days to see if anyone else will answer the questions. OK, I am at work right now but when I return home I will prepare the answers and give them out here. Your answers were both the standard one would expect, but question #2 is wrong and #3 needs more explaining. I see now that for guys with the more classical perspective, I will have to break this down very slowly so you can understand what I will "try" to explain. I think it will be worth it.

wattsup

PS: Actually, if you figure that your volt meter has no real authority whatsoever to determine if a closed line is actually positive or negative, this will start to explain part of it, but there is so much more in this then that.

I hope you make it home soon. I am very interested on your take of the questions you posted. I would also like to know why my meter has no authority to determine the polarity. As far as I know, isn't it all relative. Across a closed switch, wouldn't one lead be a little more positive or negative then the other? I can't wait to see what you are getting at.

[nul-points]

@gyulasun and @Magluvin

Thanks for responding to the three questions. Hmmmmmm. I gave this a few days to see if anyone else will answer the questions.

wattsup

hi Watts

interesting questions


this is my take on it:
(assuming v. high impedance DVM!)

1) Switch open;
   initial DVM reading at S1, relative to S2: +V Volts

2) Switch *closing* (< 0.1 second);
    any 'switch-bounce' present is likely to cause a few high voltage spikes as current starts to flow thro' coil then interrupts, giving high 'coil field-collapse' voltage ;

   Switch closed (> few seconds);
   steady-state DVM reading at S1, relative to S2:  +N uVolts
  {where N = ((Rsw)/(Rsw + Rcoil)) x V;
   Rsw probably a few milliohms, Rcoil probably a few hundred milliohms,
  so steady voltage on S1 wrt S2 of the order of around +1mV?}
 

3) Switch opens;

this is where it can get funky!

depending on voltage V, inductance L, & switch air gap,
then you *could* get sparking across S1-S2 inside switch

If  NO  spark occurs then the stored energy in the coil tries to dissipate any way it can, which since the switch is open & no current is arcing across it, the energy would probably dissipate in the form of an oscillation between the inductance of the coil and its self-capacitance (however small)

the DVM probably couldn't respond quickly enough to give a sensible reading but a scope might show you an initial high positive 'kick', followed by a decreasing sine wave, at S1, relative to S2, at the resonant frequency of the coil/self-capacitance, with the amplitude decaying away, offset at +V


If there IS sparking across the switch, then current will continue to flow in the same direction  thro' the switch due to coil-field collapse, but because the coil changes from storing to generating current the voltage polarity across the coil reverses and the S1 voltage rises sharply, much greater than +V

so, there will probably be an initial (very fast) high positive spike of voltage on S1, relative to S2, until the spike voltage reaches the break-down voltage of air for the switch gap-length

then the spark will extinguish when the energy has decreased enough that the voltage can't support a spark across the gap, at which point the remaining energy would dissipate as above, with a smaller decreasing sine wave offset at +V


...but, hey - what do i know?!?  ;o)


come on then Watts - spill the beans, man

all the best
np


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