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Overunity Machines Forum



ENERGY AMPLIFICATION

Started by Tito L. Oracion, February 06, 2009, 01:45:08 AM

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Low-Q

Quote from: Erfinder on January 19, 2017, 11:36:54 AM
Eventually it's going to be pointed out that this discussion I am participating in yet again, will go on for pages, and no one will come out any smarter.  So....to stay on topic, can someone please explain what "Energy Amplification" is, and how it whatever it is has been demonstrated in the Tesla patents.
In matter of Joules, you cannot achieve more Joules on the output than the input. I'm not talking about Teslas patens specificly, but if you charge a capacitor with 1 Joule in one second, you can discharge the capacitor at 1000 Watt in 1/1000 second, but it is still 1 Joule of energy. I think that is what "energy amplification" is much about - though you do not actually amplify energy, but just increase the energy density on the expense of shorter time.
The air or whatever that is the medium during a given discharge, might act as "fuel" into the system, that allows increased energy output, but on the other hand, that fuel already carry potential energy that has been waiting for ignition.
I remember when I was yong and ignorant, I though it was possible to connect several AC-transformes to achieve more energy out that in. For example using five 10/1 step up transformers, and end up with 100 000 times energy output. What I did not know was that the current capacity decreased 100 000 times too.
I haven read about Teslas patens, baybe breafly touched the subject once, so this answer might not help a bit :-)


Vidar

lancaIV

Quote from: Low-Q on January 25, 2017, 08:00:01 AM
In matter of Joules, you cannot achieve more Joules on the output than the input. I'm not talking about Teslas patens specificly, but if you charge a capacitor with 1 Joule in one second, you can discharge the capacitor at 1000 Watt in 1/1000 second, but it is still 1 Joule of energy. I think that is what "energy amplification" is much about - though you do not actually amplify energy, but just increase the energy density on the expense of shorter time.
The air or whatever that is the medium during a given discharge, might act as "fuel" into the system, that allows increased energy output, but on the other hand, that fuel already carry potential energy that has been waiting for ignition.
I remember when I was yong and ignorant, I though it was possible to connect several AC-transformes to achieve more energy out that in. For example using five 10/1 step up transformers, and end up with 100 000 times energy output. What I did not know was that the current capacity decreased 100 000 times too.
I haven read about Teslas patens, baybe breafly touched the subject once, so this answer might not help a bit :-)


Vidar

http://www.intalek.com/Index/Projects/Patents/DE3024814.pdf
from page 9:
pulse operation and it can the multiple of the necessary working current at electricity be produced in particular in this way, without material is used and without thermal circuit or a torque is necessary. if several are arrangedsuch energy producer switched in graduated size e.g. in a series that second receives the full performance first and third the full performance of the second energy producer to etc., then with a multiplicator of 10 in the sixth member of the series already 1000 megW performance are obtained, if one proceeds from 1000 W power input in the first and smallest energy producer at the start of the series.

You has not been alone with your thinking ! ;)

lancaIV

                                          Treating AmpĂ©re-turns as waves ?
                              Transforming displacement current in real power !

citfta

Quote from: Erfinder on January 22, 2017, 11:17:06 AM
Whats going on in this fig?


I am constantly referring to this....and will continue to refer to it, when you finally get it, you'll be like....so that's what the fuss was about....I live for that moment....

I am going to take a stab at analyzing this figure as you are saying it is important to understand it.  I have not seen any information as to the power source but have to assume it is DC for the circuit to function properly.  Also although not real clear from the figure I am assuming that the commutator H on the right end of the motor connects brushes G and K for part of the rotation of the armature.  Let's say that at the time of power being applied to the circuit the brushes G and K are not connected.  In that case current would flow from A to K and then into the capacitor.  From the other end of the capacitor current would flow through the primary winding M and thus generate a higher voltage on the secondary winding N which would be applied to the plates P.

The current that is flowing through primary winding M would also flow through the motor winding F and through the commutator and armature of the motor and then through the motor winding D and from there back to the other power connection B.  This causes the motor armature to rotate.

At some finite amount of time the cap would become charged and the current would stop flowing and the motor would stop except for the commutator on the right end of the motor.  As the motor turns the commutator H will connect brush K to brush G and this will create a path for capacitor L to discharge through primary coil M and thus create a high voltage on the secondary N of the opposite polarity of the original voltage which is passed onto plates P.

At the same time as the commutator H has the brushes connected together we now also have a path for the applied power to directly power the motor without going through the cap L or coil M.  So commutator H does two things.  It allows the motor to be powered directly with power and also allows the cap to be discharged and recharged thus giving us a high voltage AC power applied to the plates P.

Of course the high voltage on the plates produces the ozone which is forced from the plates by the fan on the motor.

Erfinder, I think I understand your methods well enough to know you probably aren't going to tell me what I have missed.  That is OK.  But would you please tell me if I have missed something important or do I just need to ponder my conclusions more thoroughly?

Respectfully,
Carroll

citfta


Could it be that I need to think more carefully about what happens when commutator H opens the connection between the brushes?