ENERGY AMPLIFICATION

[Magluvin]

There is more to the story.  Will post it later today after work
Mags

[Tito L. Oracion]

Ok sorry if i got here again ok?,
Don't worry it's not my plan to  indulge here more ok?
I just want to spice and add some salt into the topic of
Capacitor ok?.
Here it is:
First is we always have to pour or discharge the cap
Into a lot lot lot lot lot of coil and the very thing that we
Should know is the controller of discharger, what i mean is
As much as possible we only need an electron movement or a very
Very very short movement is all it takes to energized the bunch of coils
And collectors.
A very huge of magnetic field is created in just a very very small movement
An electron point of move or push is all we need everyone. Imagine that.
Offcourse the strenght of magnetic field will  still depends on the primary voltage
,size of coils and the faster we can sudden stop the movement.
Ok.
Thank you and goodbye
Covid is getting nearer and nearer in my vicinity i'm really  in danger
Maybe and i think i'm going to discharge the capacitor in me to kill the virus if
I got infected


Bye friends probably this is my really last post.
By the way just to give hopè to new comers
There is one free energy solution in dC and one in AC and  in capacitor, tesla switch and radiant energy receiver ok?
Currently i'm thinking about and will try to combine different kinds of metals with americium 231 and a magnet finding a natural pouring of electron movement continously. In that sense
We only need a vibrating relay to make power.


Bye everyone
GOD Bless all of you

[WhatIsIt]

100uF , 20V discharge parallel into another 100uF.
Now you have 2 caps of 100uF , 10V each.

Connect them in series, 2x100uF, 10V and you got output of 100uF, 20V.
There is no energy loss.

[WhatIsIt]

As far as I know, there was 2 members trying to exploit cap conundrum.
Both were nailed to the cross by the members eventually.
Aldo, they both gave interesting solutions.

One was to use load while caps equalize,
first cap discharge trough resistor, load into second and
do some work, until both caps equalize in voltage.
And then with the help of serial law, the energy is returned to source.
It involved complicating??? switching of 3 switch.
Both members was buried before they had chance to present their project all the way through.
I stayed in contact with them for a while, and did some experiments
which showed me that in some cases source was spent just a little and result was positive.

Anyway, it was hard to do it with mosfets, and there was lots of circuitry involved,
and in time I abandon idea and left the project to sit in corner for some future events.

[Void]

100uF , 20V discharge parallel into another 100uF.
Now you have 2 caps of 100uF , 10V each.

Connect them in series, 2x100uF, 10V and you got output of 100uF, 20V.
There is no energy loss.

Sorry, but that is completely wrong.
Analyzing this only requires very basic electronics knowledge.

Stored energy of a 100uF cap at 20V: 20mJ
Stored energy of 100uF cap at 10V: 5mJ
Total energy of two 100uF caps at 10V: 5mJ + 5mJ = 10 mJ (Yes, 50% of the energy is already lost)
Stored energy of two 100uF caps in series, each cap at 10V (Note: two 100uF caps in series equals 50uF, so we have 50uF at 20V): 10mJ

Clearly, 50% of the energy was already lost before ever having connected a load,
so there would only be 50% of the energy left for powering a load in your above scenario.
This type of approach very obviously does not work.

This is the same reason why Bedini's 4 battery ("Tesla Switch") or 3 battery setup system can not work.
Basic analysis indicates the batteries will run down.